climb+up+bed
答：climb mountains爬山 climb—climbed 爬 climb往上爬 closet壁橱；衣橱 clothes衣服 cloud云；云彩 cold 寒冷的 collect leaves收集树叶 collect stamps集邮(ing形式:collecting stamps)colour 颜色 come from来自…；从…来 comic book 漫画书 computer 计算机 cook dinner做饭 cook the meals做饭 cool 凉爽...
答：climb up爬上去 later on 过后;以后 come along过来 League member团员 come to school来校 leave a message 留言 cover…with以……覆盖…… do the waching洗衣服 cut down砍倒 do well in在……方面做得很好 do(a lot of)work干(许多)活儿 dress up 穿上盛装;乔装打扮 do housework 做家务 every day ...
答：闽教版小学六年级上册所有英语单词都有：vacation stay the summer palace the white house seem rest woods camp plan wonderland again cousin learn unit 2 housework past made clothes every messy water unit 3 holiday booklet hotel waterfall raft trip forecast unit 4 stream miss people vast ...
答：Maroon 5 – Woman 我的女人 If I'd be soinclined to climb up beside you 我对你是如此倾心以至于愿攀爬到你身旁 Would you tell methat the time just isn't right?你要告诉我这个时机不适合吗 And if I shouldever find the key you hide so well 如果我发现你把钥匙藏匿的那么深 Will...
答：Climb up, to sweet YanZong printed cabinet, inside, there is three statue of Buddha, Buddha is in the middle of the, on the right is the medicine Buddha, amitabha Buddha on the left, with 18 arhats respectively arranged on both sides. It is dark inside, Buddha is very big, very ...
答：make the bed铺床 use a computer使用计算机 do morning exercise晨练 havebreakfast吃早饭 have dinner吃晚饭 go to school.上学 have English class.上英语课 play sports 进行体育活动 get up起床 climb mountains爬山 go shopping买东西 play the piano弹钢琴 visit grandparents看望(外)祖父母 make a...
答：A bad beginning makes a bad ending.不善始者不善终。A bad thing never dies.遗臭万年。A bad workman always blames his tools.不会撑船怪河弯。A bird in the hand is worth than two in the bush.一鸟在手胜过双鸟在林。A boaster and a liar are cousins-german.吹牛与说谎本是同宗。
答：read, climbed 用一般过去时
答：Father's work, then how can pyronaridine I do not sound lazy to climb up to wash clothes brush it started cleaning the garbage I have to say about a good clean-up to blame the sorry though I am a girl but the room was indeed a public In fact, the landfill vice table I put thi...
网友评论：
富哗14726565215：
如图所示,将△ABC沿着DE翻折,若∠1+∠2=80°,则∠B=______度. -
65775尉中
：[答案] ∵△ABC沿着DE翻折, ∴∠1+2∠BED=180°,∠2+2∠BDE=180°, ∴∠1+∠2+2(∠BED+∠BDE)=360°, 而∠1+∠2=80°,∠B+∠BED+∠BDE=180°, ∴80°+2(180°-∠B)=360°, ∴∠B=40°. 故答案为:40°.
富哗14726565215：
如图,已知:AB∥CD,求证:∠B+∠D+∠BED=360°.(至少用三种方法) -
65775尉中
：[答案] 证明:(1)连接BD,如图, ∵AB∥CD(已知), ∴∠ABD+∠CDB=180°(两直线平行,同旁内角互补). ∵∠1+∠2+∠BED=180°(三角形内角和为180°), ∴∠ABD+∠1+∠CDB+∠2+∠BED=360°, 即∠ABE+∠CDE+∠BED=360°. (2)延长...
富哗14726565215：
如图,已知AB∥CD,求证:∠B+∠D=∠BED,试完成下列的证明过程.证明:过E点作EF∥AB(已作)∴∠1=∠B (______)又∵AB∥CD ... -
65775尉中
：[答案] 证明:过E点作EF∥AB,(已作) ∴∠1=∠B,(两直线平行,内错角相等) 又∵AB∥CD,(已知) ∴EF∥CD,(平行的传递性) ∴∠2=∠D, ∴∠B+∠D=∠1+∠2, ∴∠BED=∠B+∠D.(等量代换)
富哗14726565215：
如图已知AB∥EF,∠BED=∠B+∠D,求证:AB∥CD证明:因为 AB∥EF,______所以∠B=∠1.______因为∠BED=∠B+∠D,( 已知 )所以... -
65775尉中
：[答案] 证明:因为 AB∥EF,(已知) 所以∠B=∠1. (两直线平行,内错角相等) 因为∠BED=∠B+∠D,(已知) 所以∠BED=∠1+∠2,(等量代换) 所以∠2=∠D,(等量代换) 所以 EF∥CD. (内错角相等,两直线平行) 又 AB∥EF,(已知) ...
富哗14726565215：
课题学习:平行线的“等角转化”功能.阅读理 如图1,已知点A是BC外一点,连接AB,AC.求∠BAC+∠B+∠C的度数.(1)阅读并补充下面推理过程. 过点A... -
65775尉中
：[答案] (1)∵ED∥BC,∴∠B=∠EAD,∠C=∠DAE, 故答案为:∠EAD,∠DAE; (2)过C作CF∥AB, ∵AB∥DE, ∴CF∥DE, ∴∠D=∠FCD, ∵CF∥AB, ∴∠B=∠BCF, ∵∠BCF+∠BCD+∠DCF=360°, ∴∠B+∠BCD+∠D=360°, (3)A、如图2,过点E作EF∥...
富哗14726565215：
将三角形ABC沿着DE翻折,翻折后∠1加∠2等于80度.求∠B的度数 -
65775尉中
：[答案] ∵∠B+∠BED+∠BDE=180 ∴∠BED+∠BDE=180-∠B ∵将△ABC沿着DE翻折 ∴∠1=180-2∠BED,∠2=180-2∠BDE ∴∠1+∠2=360-2(∠BED+∠BDE) =360-2(180-∠B) =2∠B ∵∠1+∠2=80 ∴2∠B=80 ∴∠B=40°
富哗14726565215：
如图,已知AE平分∠BAC,BE⊥AE于E -
65775尉中
：[答案] 如图,已知AE平分∠BAC,BE⊥AE,垂足为E,ED∥AC,∠BAE=36°,那么∠BED=126度. 解 析 已知AE平分∠BAC,ED∥AC,根据两直线平行同旁内角互补,可求得∠DEA的度数,再由三角形外角和为360°求得∠BED度数. ∵AE平分∠BAC ∴∠...
富哗14726565215：
...然后在平行线间画了一点E,连接BE、DE后(如图①),他用鼠标左键点住点E,拖动后,分别得到如图②、③、④等图形.这时他突然一想:∠B、∠D与... -
65775尉中
：[答案] (1)选图③. 过点E作EF∥AB ∵AB∥CD, ∴EF∥CD(平行于同一条直线的两直线平行), ∴∠D=∠DEF,∠B=∠BEF, 又∵∠BED=∠DEF-∠BEF, ∴∠BED=∠D-∠B. 故答案为:平行于同一条直线的两直线平行,∠DEF-∠BEF,∠D-∠B (2)①,如...
富哗14726565215：
如图,已知AB平行于CD,BE平分角ABC,DE平行于角ADC,角BAD等于80度.若角BCD等于N度.试求角BED的度数 -
65775尉中
：[答案] 连接BD 在△BCD中,内角和=∠BCD+∠CDB+∠DBC=180° 在△BED中,内角和=∠BED+∠EDB+∠DBE=180° ∠EDB=∠CDB-∠CDE=∠CDB-∠BAD/2=∠CDB-40° ∠DBE=∠DBC+∠CBE=∠DBC+∠BCD/2=∠DBC+N/2 所以在△BED中,内...
富哗14726565215：
如图,三角形abc中,ab=ac,d是bc上中点,角edf=角b,求证:三角形edf相似于三角形def -
65775尉中
：[答案] 证明: ∵AB=AC ∴∠B=∠C ∵∠CDE=∠B+∠BED=∠EDF+∠BED ∴∠CDF+∠EDF=∠EDF+∠BED ∴∠BED=∠CDF ∴△BED∽△CDF
