编写函数求1+2+3+k
答:int xsum(int k){ int sum = 0; while ( k-- >= 1 ) sum += k; return sum;}
答:include <stdio.h>int fun(int n){int i,k=1,s=0;for(i=1;i<=n;i++){k*=i;s+=k;}return s;}void main(){int n;scanf("%d",&n);printf("%d",fun(n));}
答:include "stdio.h"int f(int n,int k){int i,j,s,t;for(s=0,i=1;i<=n;s+=t,i++)for(t=j=1;j<=k;t*=i,j++);return s;}int main(int argc,char *argv[]){int n,k;printf("Please neter n & k(int 0<n,k)...\n");if(scanf("%d%d",&n,&k)!=2 || n<...
答:include <stdio.h>int fun(int n){int k=n;if(n==1) k=1;else k+=fun(k-1);return k;}//以上为求和的递归函数,以下为主函数int main(){int n;scanf("%d",&n);printf("%d",fun(n));return 0;}//运行示例:
答:function z=g(n,k)temp=0;for i=1:n;temp=temp+i^k;end z=temp;end 调用方式:s=g(4,2)
答:include<stdio.h>int sumnum(int n){ int i,j=1,sum=0; for (i=1;i<=n;i++) { j=j*i; sum+=j; } return sum;}int main(){ int s,n; n=6; s=sumnum(n); printf("%d\n", s); return 0;} ...
答:if(k==0){ break;} max=min;min=k;} printf("最大公约数:%d\n",min);printf("最小公倍数:%d\n",m*n/min);} 2、include <stdio.h> void func(int n){ if(n){ printf("%d",n%10);func(n/10);} } main(){ int n;printf("输入整数:");scanf("%d",&n);printf("...
答:include <stdio.h> int fact(int k){int pro=1,i;for(i=1;i<=k;i++)pro*=i;return pro;} int sum(int n){ int s=0,i;for(i=1;i<=n;i++)s+=fact(i);return s;} int main(){int a;scanf("%d",&a);printf("%d\n",sum(a));getch();} ...
答:int sum=0,i,j,k;for(i=1;i<=n;i++){ for(k=j=1;j<=i;j++)k*=j;sum+=k;} return sum;
答:include <stdio.h> int sum (int k){ int i=0,s=0;for(i=0;i<=k;i++) // 不要分号 s=s+i;return (s);} int main(){ int k;printf("输入一个数");scanf("%d",&k);k=sum(k);printf("%d",k);}
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茹孙15651359861:
编写函数xsum,计算1+2+3+……+k -
23455於丽
: int xsum(int k) {int sum = 0;while ( k-- >= 1 ) sum += k;return sum; }
茹孙15651359861:
用递归函数实现一个累加和函数sum()计算1+2+3+....+k的和 -
23455於丽
: 用递归的方法就必须先自定义一个函数,函数实现递归功能,同时考虑用户输入的合法性具体代码如下:1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37#include <stdio.h> #include<...
茹孙15651359861:
编程 编写函数1!+2!+3!+...K!的和 -
23455於丽
: 不知道你要的数据范围,我就用long了 #include void main() { long int sum1,sum2=0; int k; int i,j; scanf("%d",&k); for(i=1;i
茹孙15651359861:
C语言编程:求1!+2!+3!+、、、+n!的值? -
23455於丽
: #include<stdio.h> main() { int i,b,sum=1,g;/*定义各个需要的元素,sum初值化,就拿1-4的阶乘的和来试炼*/ for(i=2;i<5;i++) { g=i; /*切记要赋值一下,因为下面要改变*/ for(b=1;b<=i-1;b++) { g*=b; } sum+=g; } printf("总和是%d\n",sum); }
茹孙15651359861:
编写程序求0!+1!+2!+3!+……+k!( )并输出. -
23455於丽
: //k的值不能过大,否则会发生溢出.#include int fact(int n) { int f=1,i; for(i=1;i f*=i; return f; } int main() { int i,k,t=0; scanf("%d",&k); for(i=1;i t+=fact(i); printf("%d\n",t); return 0; }
茹孙15651359861:
vb编写函数,计算1 +2 +3 + ... k,在命令按钮的click事件过程中输入m,n,p -
23455於丽
: Private Function getResult(m As Integer, n As Integer, p As Integer) As Double Dim i As Integer Dim tempA, tempB, tempC As Integer tempA = 0 tempB = 0 tempC = 0 For i = 1 To m tempA = tempA + i Next i For i = 1 To n tempB = tempA + i Next i ...
茹孙15651359861:
功能:编写函数fun求1!+2!+3!+ …… +n!的和,在main函 数中由键盘输入n值,并输出运算结果.请编写fun 函数功能:编写函数fun求1!+2!+3!+ …… +n!的... -
23455於丽
:[答案] float fun(int n) {int i,j; float s=0,sum=0; for(i=1;i
茹孙15651359861:
用函数实现求k !,并在主函数中调用求 sum=1!+2!+3!+……+n!. -
23455於丽
: #include <stdio.h> long factorial(long n) { if (n == 0 || n == 1) return 1; else return n * factorial(n-1); } void PrintResult(int n, long result) { int i = 0; if (n == 0) printf("%d! = ", 0); else if (n == 1) printf("%d! = ", 1); else if (n == 2) printf("%d!+%d! = ", ...
茹孙15651359861:
vb 编写一个function程序和一个sub程序,都能根据参数k求1+2+3++k,用两个按钮的 -
23455於丽
: Private Sub Command1_Click()Dim s As Integers = InputBox("请输入要累加的数字:")For i = 1 To sa = a + iNext iMsgBox "从1累加到 " & s & " 的数是 " & aEnd Sub
茹孙15651359861:
C语言,编写函数f(n)计算1+2+3+...+n.要求返回double类型. 利用函数编程:输入一个整数n,计 -
23455於丽
: #include void main() { int Num,i,j; double dResult; dResult = 0; printf("Please Enter a Number:\n"); scanf("%d",&Num); j = 0; for(i=1;i j = j + i; dResult += (i+0.0)/j; } printf("The Result is %lf",dResult); getch(); return; } 其中dResult += (i+0.0)/j; ...