a+branch+of+knowledge
答：ahhh薄荷其中上海字母i硝酸钾诺森布里亚大学有一所分行，并在shaghai必须死excitin拜因在城市massiv
答：Career Objectives:To gain the position of a Customer Service Billing Administrator petencies: Good knoplex billing tasks Excellent analytical and problem solving skills Proficient in computer applications like Excel, Word and Outlook Excellent interpersonal and communication skills Ability to handle multiple ...
答：7、生活就像一盒巧克力，你永远不知道你会得到什么。Life is like a box of chocolates. You never knoetimes I just need someone to talk to.10、我多么希望，有那么一个人拼了命的爱我。Hoetimes, that person is right beside you. It's just that you don't knofort me, because every ...
答：people to love to turn thin, and no together branch.21、天长地久有时尽，此恨绵绵无绝期。Sometimes as enduring as the universe, s do you walk, how many times I think of me.爱情英文诗句 1、在爱人眼里，一千里的旅程不过一里。In the eyes of a lover, a thousand miles'journey ...
答：who you knowhat you wear or if your hair is blue or purple or pinkyou dont have to be cooldont have to be smart dont need to know anything all the timeits alright if your a little bit out of itI dont care I just wanna be your friendI like to go to the mall and walk around ...
答：A number of mid-day study, such as technology. Note: due to my technical school students during the orientation for the staff of state-omercia Bank of China(ICBC), Jinghai branch Technoogy department (TD) To maintain the computer and other office equipment of the bank Giving assistance to ...
答：KHM 27: Town Musicians of Bremen (Die Bremer Stadtmusikanten)KHM 28: The Singing Bone (Der singende Knochen)KHM 29: The Devil With the Three Golden Hairs (Der Teufel mit den drei goldenen Haaren)KHM 30: The Louse and the Flea (Läuschen und Flöhchen)KHM 31: The Girl Without ...
答：Han-Dynastie (206 v. Chr. bis 220 n. Chr.), ist die medizinische Longsheng Zeiten. Die traumatische Geschichte der berühmten Arzt Hua Branch, beide mit Kräutern, Akupunktur Behandlung, sondern auch gut in Chirurgie, und gründete die "Fünf-Bird-Spiel", und die moderne...
答：1、在爱人眼里，一千里的旅程不过一里。In the eyes of a lover, a thousand miles'journey is only one mile.2、明月楼高休独倚，酒入愁肠，化作相思泪。The Moon To hair, suddenly to the time immemorial. e an is ing is just a past.24、我为爱而忘情，我为爱受折磨，不论忘情还是...
答：Life is like a box of chocolates. You never knoetimes I just need someone to talk to.10、我多么希望，有那么一个人拼了命的爱我。Hoetimes, that person is right beside you. It's just that you don't knofort me, because every sepany, happiness is so natural.25、时间会摒弃...
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崔奋19428764198：
关于比例变形? -
40338饶嵇
： 分子或分母同加减一个数,比值改变; 分子或分母同乘除一个数,比值不变
崔奋19428764198：
a branch of是什么意思 -
40338饶嵇
： a branch of 英 [ə brɑ:ntʃ ɔv] 美 [e bræntʃ ʌv] 一条, 一支, 一束 双语例句 1 A thrush alighted on a branch of the pine tree. 一只鸫落在松树的树枝上. 2 This is a branch of the company. 这是这家公司的一个分公司.
崔奋19428764198：
已知数列{an}为公差不为零的等差数列,{an的部分项组成下列数列:ak1,ak2,…,akn,恰 -
40338饶嵇
： 有a1,a5,a17成等比数列,得 (a1+4d)/a1=(a5+12d)/a5=(a17+36d)/a17 看规律,k1=1,k2=1+4=k1+4,k3=1+4+12=k2+3*4,k4=1+4+12+36=k3+3^2*4,kn=kn-1+3^(n-2)*4 用迭代法,求出kn=2*3^(n-1)-1
崔奋19428764198：
已知数列{an}的通项公式为an= - 2n+kn,若数列{an}是递减数列,则实数k的取值范围是 -
40338饶嵇
： 解:a(n+1)-an=-2(n+1)^2+k(n+1)-(-2n^2+kn) =-4n-2+k 由于数列{an}为递减数列,则对于任意的n∈N* 总有a(n+1)-an≤0恒成立 即:-4n-2+k≤0对于任意的n∈N*恒成立 整理得:(k-2)/4≤n,对于任意的n∈N*恒成立 ∴只需(k-2)/4≤1即k≤6. 经检验:当k=6时,数列{an}仅有有限项相等,符合题意. 所以,实数k的取值范围为k≤6.
崔奋19428764198：
a1=1,a下标(n+1)=2an+2n - 1,求an -
40338饶嵇
： 这个也是配形式,设 [a(n+1)+k(n+1)+m]=2(a(n)+kn+m)2kn-kn=2n2m-(k+m)=-1 所以k=2,m=1 a(n)+2n+1是等比, q=2 ,a(1)+2+1=4 a(n)+2n+1=4*2^(n-1) a(n)=4*2^(n-1)-2n-1
崔奋19428764198：
数列{an}满足an+1=an+3n+2.a1=2.求an -
40338饶嵇
： 此类题的一般解法是设an+1+kn+b=c(an+kn+b)c为an原来的系数,kn+b为题目中多余的项.不过这个可以发现c=1于是构造不出来.你可以把他写成an+1-an=3n+2,然后从a2-a1开始一直列到an-an-1=3n-1,之后叠加就可以了
崔奋19428764198：
已知数列{an}的通项公式是an=n2+kn+2,若对任意n∈N*,都有an+1>an成立,则实数k的取值范围是k> - 3 . -
40338饶嵇
： 因为 an+1 > an 所以an+1 - an = (n+1)^2+(n+1)k+2-n^2-kn-2 = 2n+1+k > 0 所以k > -(2n+1)k>-3
崔奋19428764198：
已知a为有理数,b为无理数,证明:a+b为无理数 -
40338饶嵇
： 无理数 b为无理数,那么a为有理数,a+b的和一定会是无理数
崔奋19428764198：
为什么a/b=c/d=m/n=a+c+m/b+d+n=a/b -
40338饶嵇
： 这是一个等比定理证明. 设计a/b=c/d=m/n=k,则有a=kb,c=kd,m=kn,k为常数, 代入等式右边:(kb+kd+kn)/(b+d+n)=k, 因为a/b=k 所以原等式,左边=右边,此等式成立.
崔奋19428764198：
已知a1=1,3an+1=an+3n,求an -
40338饶嵇
： 解:由题意可得,∵a1=1,∴a=1,将a=1代入方程3an+1=an+3n,可得 3*1*n+1=n+3n 3n+1=n+3n 3n-n-3n=-1 -n=-1,∴n=1.当n=1,a=1时,原式=1*1=1,∴an=1 注:∵=因为,∴=所以,*=乘号.谢谢采纳,祝您学业有成
