loves+philosophy
答：Person deeply loves the movie which as, I very already to Bruce Leethis name familiar-sounding can detailed, but ashamed is, continuouslyall the...In 1961, the Bruce Lee middle schoolgraduated, in May was admitted by the excellent result WashingtonState University, majored in the philosophy. ...
答：其实你都没有说字数，很难控制哦~~~我尽力了,sorry 在这张周杰伦的同名专辑中，他就一手包办了全部歌曲的作曲、作词、编曲、合声及编写合声，充分展现其音乐才华。周杰伦从小就学钢琴，后来又学大提琴，国中就开始写歌，高中上音乐班，无论古典音乐或流行音乐，都难不倒他。1;In this album edition,...
答：Nancy watches comedies and she loves sitcoms. But Lily can't stand them .She just likes game shows. Jack doesn't like sitcoms either. He ...life philosophy, "the four great classical novels" I finished reading, I have benefited a lot from such as "a dream of red mansions" tell people...
答：My philosophy of life is work . (Thomas Alva Edison , American inventor)我的人生哲学就是工作。 (美国发明家 爱迪生 . T . A .)When work is a pleasure , life is joy ! When work is duty , life is slavery .(Maxim Gorky , Russian writer )工作是一种乐趣时,生活是一种享受!工作是一种...
答：wine and other enhancing ingredients. Even in our cooking we never forget to practice our “Yin Yang” philosophy; contrast and balance, the soft and the crisp, the light and the dark, the sweet and the sour. When slicing pork or beef, always cut it against the grain. The m...
答：The SON is typical of the black descendants of civilization, his dark robust, whole body is full of nature's breath, he did not understand the philosophy of the theory, but it has a strong ability to survive, and are willing to work to get through something of value, he ...
答：the humanity being core successfully with the buddy who works together" manage idea, with the whole nation eight big clothings faction, almost three thousand domestic , international family are first-rate clothes and ornaments enterprise forms strategy alliance, The famous brand (loves US...
答：In the following sentences, Forrest’s speech reveals some simple life philosophy. And at the last of his first important speech, Forrest, as other Americans, begins to flatter the nurse by her shoes and he uses another exaggeration- and not feels a thing. Only from these words, Forrest ...
答：Tom Booker seems to have a healthy scepticism for the legend however and makes his down to earth philosophy pretty clear from the first moment when we hear him say, " Well truth is, I help horses with people problems."Despite Tom and Robert's reluctance, Annie drags Grace from...
答：My philosophy of life is work . (Thomas Alva Edison , American inventor)我的人生哲学就是工作。 (美国发明家 爱迪生 . T . A .)When work is a pleasure , life is joy ! When work is duty , life is slavery .(Maxim Gorky , Russian writer )工作是一种乐趣时,生活是一种享受!工作是一种...
网友评论：
田韩13039314069：
已知向量OP=(1 - 3分之1)向量OA+3分之1向量OB,则向量AP=?向量AB求高手帮忙解答啊、、、谢谢了 感激 T T -
34119羊琬
：[答案] 向量OP=(1-1/3)向量OA+1/3*向量OB =向量OA+1/3(向量OB-向量OA) =向量OA+1/3向量AB 移项: ∴向量OP-向量OA=1/3向量AB ∴向量AP=1/3向量AB
田韩13039314069：
因为向量OP=rOA+uOB,那么u+r=1,请问1/mAP+1/nAQ=3AG,那么1/m+1/n=3成立吗,大写字母它们都是向量 -
34119羊琬
：[答案] OP=rOA+uOB,u+r=1 => P is on AB (1/m)AP+(1/n)AQ=3AG AG= [1/(3m)]AP+[1/(3n)]AQ 1/(3m)+1/(3n)=1 1/m+1/n=3 => G is on PQ
田韩13039314069：
已知P在P1P2上,且向量P1P=向量λPP2,求P点的坐标 求到OP=OP1+P1P=OP1+入PP2=OP1+入(OP2 - OP)然后怎么求? -
34119羊琬
：[答案] OP=OP1+P1P=OP1+入PP2=OP1+入(OP2-OP) 即OP=OP1+入(OP2-OP)= OP1+入OP2-入OP (1+入)OP= OP1+入OP2 OP= OP1/(1+入)+入OP2/(1+入)
田韩13039314069：
空间直线的向量表达式:OP=OA+tAB=(1–t)OA+tOB 为什么?这个式子怎么能成立呢? -
34119羊琬
：[答案] 对任意点M,AB=MB-MA 这是向量的常用性质 当然M可以取点O 即AB=OB-OA 即OP=OA+tAB=OA+t(OB-OA)=OA+tOB-tOA=(1-t)OA+tOB
田韩13039314069：
已知向量op=(3+t,1+2t),求|op|min -
34119羊琬
：[答案] |op|^2=(3+t)^2+(1+2t)^2=5t^2+10t+10=5(t+1)^2+5 开口向上的二次函数,t=-1时,上式最小值为5 所求为:根号5
田韩13039314069：
如何证明:向量OP、OA、OB、OC满足OP=xOA+yOB+(1 - x - y)OC, -
34119羊琬
：[答案] 说明A,B,C,P共面 我从后面出发. 以下虽然没有向量符号,可还是响亮 CP=xCA+yCB(四点共面) OP-OC=xOA-xOC+yOB-yOC OP=(1-x-y)OC+yOB+xOA 希望你可以看得懂,并且采用.呵呵.
田韩13039314069：
已知向量OP1+OP2+OP3=0,|OP1|=|OP2|=|OP3|=1,则向量OP2,OP3的夹角为我知道答案是120°,但不知道是怎么求出来的,求详细的过程 -
34119羊琬
：[答案] op2+op3=-op1 1+1+2op2op3=1 (两边平方) op2op3=-1/2 cosα=-1/2 即op2与op3夹角为120度.
田韩13039314069：
椭圆x2+4y2=16上有两点P、Q,O为原点,若OP、OQ斜率之积为 - 1/4,求证|OP|2+|OQ|2为定值20. -
34119羊琬
：[答案] 证明: 设P(4cosα,2sinα),Q(4cosβ,2sinβ). ∵kOP*kOQ=-1/4, ∴(2sinα/4cosα)*(2sinβ/4cosβ)=-1/4 →cos(α-β)=0, 即α-β=2kπ±π/2,k∈Z. 所以, |OP|^2+|OQ|^2 =16(cosα)^2+4(sinα)^2+16(cosβ)^2+4(sinβ)^2 =20(cosβ)^2+20(sinβ)^2 =20为定值
田韩13039314069：
都是向量 OP1+OP2+OP3=0 且|OP1|=|OP2|=|OP3|=1 则 OP1 OP2 OP3两辆的夹角为?为什么? -
34119羊琬
：[答案] 因为OP1+OP2+OP3=0 所以OP1+OP2=-0P3=P30 又|OP1|=|OP2|=|OP3|, 由平行四边形可得P1P2=P2P3=P1P3 所以是等边三角形 所以两两为120°
田韩13039314069：
若向量OP1,OP2,OP3满足OP1+OP2+OP3=0,且|OP1|=|OP2|=|OP3|,试判断三角形P1,P2,P3的形状,理由~ -
34119羊琬
：[答案] 因为OP1+OP2+OP3=0 所以OP1+OP2=-0P3=P30 又|OP1|=|OP2|=|OP3|, 由平行四边形可得P1P2=P2P3=P1P3 所以是等边三角形
