result+some+causes
答：最容易错的词语是看望外祖父外祖母。visitgrandparents,
答：Sometime, the rip-off produts may be not worse than the authentic counterpart. However, without the fame popularity of the copied brand, they cannot be accepted widely. Thus, they have to be sold at very low price. Even though the quality cannot be as good as the imported o...
答：saving the earthAs time goes by ,man is making the earth sick .People cut down too many trees and leave rubbish everywhere .Factories let out their waste without doing anything to do it.This has cauesd some serious problems.For example ,the land is sandy ;the river is dirty :the air i...
答：The United States of America is the world's most diverse, multiethnic country situated in North America. It is a land of natural beauty, ranges from coastlines to mountains, from deserts to rainforests. The U.S. covers an area of 3.8 million square miles, consisting of 50 stat...
答：As time goes by ,man is making the earth sick .People cut down too many trees and leave rubbish everywhere .Factories let out their waste without doing anything to do it.This has cauesd some serious problems.For example ,the land is sandy ;the river is dirty :the air is not cleanany...
答：I will help you better understand the law sometime nextweek.I am keen on English.He is keen on Geology.I was keen on math when I was a little boy.She will be keen on cauculation after this lesson.Ants is diffrent from worms.She is diffrent from Mary.I can not believe ...
答：As time goes by ,man is making the earth sick .People cut down too many trees and leave rubbish everywhere .Factories let out their waste without doing anything to do it.This has cauesd some serious problems.For example ,the land is sandy ;the river is dirty :the air is not cleanany...
答：Another scholar causht in the undertow.史努比：有些玩笑的代价比较昂贵……Some laughts are woryj more than other…史努比：当狗就是这点不好，别人什么事都不告诉你……That\'s the only trouble with being a dog…they never tell you anything…史努比：生命的秘密就在于远观最佳。The ...
网友评论：
夹曲13051965945：
用C语言编写程序计算并输出数列1 - 1/3+1/5 - 1/7+1/9 - 1/11+·····+1/101的值. -
9521温终
： #include int main(){ double result=0; double s=1; int count=1; do{ if(count%2==1) { result+=1/s; s+=2; count++; } else { result-=1/s; s+=2; count++; } }while(s <= 101); printf(＂1-1/3+1/5-1/7+1/9-1/11+·····+1/101=%f\n＂, result); system(＂pause＂); return 1; }
夹曲13051965945：
C++编程:编程计算1+2+3+...+100. -
9521温终
： #include ＂iostream＂ using namespace std; int main() { int i,result=0; for (i=1;i<=100;i++) result=result+i; cout<<result; }
夹曲13051965945：
使用双重循环,计算result=1!+2!+3!+4!+5!+6!+7!+8!+9!+10! -
9521温终
： #include#include ＂math.h＂ //你要用pow函数,必须加上这个头文件int main(){ long a=1,n,s=0,k=0; // k的值应该从0开始 for(n=1;n
夹曲13051965945：
java以下代码中,if 语句为什么要加上result1=result1+＂\n＂+... 才能显示出前面的结果,否则只能 -
9521温终
： result1=result1+＂\n＂+...这个是在原有的值上边进行追加,不写的话相当于重新给result1重新赋值,+“\n”是为了输出的时候换行
夹曲13051965945：
C#语句 int result=9; console.writeline(＂结果是:＂+result);int i; console.writeline(i+＂＂);请解释 -
9521温终
： int i加号 “+” 是连字符,在console; console.writeline(i+＂＂);这里,就要转型,也就是我们常说的“装箱”,那么 系统就把两个字符串连成一个输出~~ 如果其中有一个不是;".writeline()里面,先将 变量 i (int型数值)装箱为i(字符串类型值),然后将这个值与",加号两边都是字符串
夹曲13051965945：
C语言程序设计里(给出相应的符号,作出相应的操作C(例如:输入“+”,则计算两个数的 -
9521温终
： printf(＂您开玩笑了,没有这个运算符.\ int result,m;,&op),result),m; switch(op) { case ',result),m; case '-';n＂); scanf(＂: result=m+n;); printf(＂ printf(＂%d+%d=%d\,n; } break; default;%d-%d=%d\n＂您想进行哪种运算呢,n; else { result=m/n; printf(...
夹曲13051965945：
java语言s=1+2+3+4.....+n当s>5000时,求n -
9521温终
： int result = 0; int i=1; while (result<5000){ result=result+i; i++; } System.out.println(result); System.out.println(i-1); 结果是n到100时结果=5050
夹曲13051965945：
用C#输出1+2+3····999+1000的字符串,并输出结果 -
9521温终
： string str=＂＂; int result=0; for(int i=1;i if(i==1){ str+=i.ToString(); }else{ str+=＂+＂+i.ToString(); } result+=i; } Console.WriteLine(str); Console.WriteLine(＂结果是:＂+result);
夹曲13051965945：
result+=i啥意思? -
9521温终
： result = result + i C语言是从右边执行的 相当于把 result + i送给 result 这和普通数学的思维是不一样的 =是把右边东西的送到左边 ==才是相等的意思
夹曲13051965945：
Java 中 请输出1+2 - 3+4 - 5....N -
9521温终
： int f(int n){int result=1;if(n<0){return 0;}else if(n==1){return 1;}for(int i=2;i<=n;i++){if(i%2==0){//偶数result+=i;}else{//奇数result-=i;}}return result;}
