2X1/4怎么画图
这就需要用到概念的问题，二分之一乘四分之一的式子。参考如下：
绛旓細鐢电嚎涓婃爣璇嗙殑2x1,o锛屾槸杩欐牴鐢电嚎鐨勮鏍硷紝瀹屾暣涔﹀啓鏄2*1.0mm²琛ㄧず鐨勬槸杩欐牴鐢电嚎鏄2鑺數缂嗭紝姣忚姱鐨勬í鎴潰绉ぇ灏忔槸1.0骞虫柟姣背
绛旓細杩欐槸涓涓満姊伴浂浠,鏄竴涓┖鍒妲(涔熷彨鐮傝疆瓒婄▼妲),妲藉2姣背,娣1姣背.
绛旓細涔2鍦烘瘮璧涳紝蹇呴』寰椾拱瀵
绛旓細2x1x2鐨勬爣鍑嗗舰閰嶆柟娉曪細2X1X2= 2(y1+y2)(y1-y2) -2 (y3+y4)(y3-y4)= 2y1^2-2y2^2-2y3^2+2y4^2銆俧=2x1x2-2x1x3-6x2x3 = 2(y1+y2)(y1-y2)-2(y1+y2)y3-6(y1-y2)y3 = 2y1^2 - 8y1y3 - 2y2^2 + 4y2y3 = 2z1^2-2z2^2-6z3^2 鍚箟 鍚湁绛夊彿...
绛旓細绛旓細x1婊¤冻锛2x+2^x=5锛2x1+2^(x1)=5 x2婊¤冻锛2x+2log2(x-1)=5锛2x2+2log2(x2-1)=5 璁総=log2(x2-1)鍒檟2-1=2^t 鎵浠ワ細x2=1+2^t 鎵浠ワ細2(1+2^t)+2t=5 鎵浠ワ細2(t+1)+2^(t+1)=5 鎵浠ワ細x1鍜宼+1閮芥槸鏂圭▼2x+2^x=5鐨勮В 鎵浠ワ細x1=t+1=log2(x2-1)+1...
绛旓細瑙ｅ師鏂圭▼x1+x2=-3/2 x1x2=-1/2 鎵浠ユ柊鏂圭▼x1+x2=2(-3/2)=-3 x1x2=2x1=-1 鎵浠ユ柊鏂圭▼涓篨^2+3X-1=0 绗2 X1+X2=-3/2-2=-7/2 ( X1-1)(X2-1)=X1X2-(X1+X2)+1=-1-(--3/2)+1=3/2鎵浠ユ柊鏂圭▼涓簒^2+7/2X+3/2鍖栫畝寰2X^2+7X+3=0 绗3 鍘熸柟绋嬩袱鏍瑰拰鐨...
绛旓細2x+1鈮0 x鈮-0.5 浠诲彇x2>x1鈮-0.5 f(x2)-f(x1)=鈭(2x2+1)-鈭(2x1+1)=2(x2-x1)/[鈭(2x2+1)+鈭(2x1+1)]鈭祒2>x1鈮-0.5 鈭磝2-x1>0,鈭(2x2+1)+鈭(2x1+1)>0 f(x2)-f(x1)>0 f(x2)>f(x1)鍥犳锛屽嚱鏁板湪瀹氫箟鍩熷唴鍗曡皟閫掑銆
绛旓細x²+x-12=0锛宎=1锛宐=1锛宑=-12 x={-1卤鈭歔1²-4x1x(-12)]/(2x1)={-1卤鈭歔1+48]/2 ={-1卤鈭49}/2 ={-1卤7}/2 x1=(-1+7)/2 =6/2 =3 x2=(-1-7)/2 =-8/2 =-4 x²-²鈭2x-1/4=0锛²鈭2x鏄粈涔堟剰鎬濓紵x²+4x+8=2x...
绛旓細x1鐨勫钩鏂瑰噺x1鍔爔2鐨勫肩瓑浜3銆傗埖x1鏄柟绋嬬殑涓涓牴 鈭磝1² - 2x1 - 1=0 x1² - x1 - x1 - 1=0 鍒檟1² - x1=1 + x1 鏍规嵁闊﹁揪瀹氱悊锛歺1 + x2=2 鈭村師寮=1 + x1 + x2=1+2=3
绛旓細杩欐槸鍥介檯璐告槗鐞嗚鐨勫熀鏈ā鍨嬬殑缂╃暐璇2*2*1妯″瀷鏄寚涓や釜鍥藉銆佷袱绉嶄骇鍝佸拰涓绉嶇敓浜ц绱狅紙閫氬父鏄姵鍔級锛屽彜鍏稿浗闄呰锤鏄撶悊璁烘ā鍨嬪父鐢紙濡傛潕鍢夊浘鐨勬瘮杈冧紭鍔跨悊璁猴級锛2*2*2妯″瀷鎸囦袱涓浗瀹躲佷袱绉嶄骇鍝佸拰涓ょ鐢熶骇瑕佺礌锛堥氬父鏄姵鍔ㄥ拰璧勬湰锛夛紝鏂板彜鍏稿浗闄呰锤鏄撶悊璁哄父鐢紝濡傝但鍏嬫瓏灏-淇勬灄锛圚-O)鐨勮绱犵璧嬬悊璁恒
