请教一下类似于SqLserver中的select top 1 from table order by id 在ORacle中是怎么写的。 SQLSERVER取前10条记录怎样取
oracle sql\u67e5\u8be2\u524d50\u4e2a\u8bb0\u5f55 \u6211\u7684\u8bed\u53e5\u662fselect top 50 * from table order by id desc;oracle\u6ca1\u6709top\u7684\u8bed\u6cd5\uff0c\u9650\u5236\u8bb0\u5f55\u6570\u90fd\u662f\u4f7f\u7528rownum < N\u6216\u8005rownum <= N\u7684\u3002
\u4f60\u8fd9\u7528\u5f97\u7740\u5d4c\u5957\u5417\u3002\u4e0d\u662f\u591a\u6b64\u4e00\u4e3e\u5417\uff1f
select top 10 A.name,B.sex from userinfo A,sexinfo B where A.id = B.id and A.sex = B.sexid order by A.id
\u8981\u662f\u771f\u8c61\u4f60\u90a3\u4e48\u5199\u7684\u8bdd\uff0c\u4e5f\u53ef\u4ee5
select top 10 C.name,C.sex from (select A.name name,B.sex sex ,A.id id from userinfo A,sexinfo B where A.id = B.id and A.sex = B.sexid) C order by A.id
简单地说，实现方法如下所示：
SELECT 列名1．．．列名n FROM
(SELECT 列名1．．．列名n
FROM 表名 ORDER BY 列名1．．．列名n)
WHERE ROWNUM <= N（抽出记录数）
ORDER BY ROWNUM ASC
下面举个例子简单说明一下。
顾客表customer(id,name)有如下数据：
ID NAME
01 first
02 Second
03 third
04 forth
05 fifth
06 sixth
07 seventh
08 eighth
09 ninth
10 tenth
11 last
则按NAME的字母顺抽出前三个顾客的SQL语句如下所示：
SELECT * FROM
(SELECT * FROM CUSTOMER ORDER BY NAME)
WHERE ROWNUM <= 3
ORDER BY ROWNUM ASC
输出结果为：
ID NAME
08 eighth
05 fifth
01 first
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