C语言:输入一个大于100的三位正整数n,输出100-n中满足条件的所有数? C语言求教输入两个正整数m和n(m≥100,n<1000),...

c\u8bed\u8a00\u7f16\u7a0b\uff1a\u8f93\u5165\u4e00\u4e2a\u5f88\u5927\u7684\u6574\u6570n(n<100),\u8f93\u51fan\u5404\u4f4d\u6570\u5b57\u4e4b\u548c ,\u5229\u7528\u5b57\u7b26\u4e32\u5b9e\u73b0

\u601d\u8def\uff1a\u8f93\u5165\u5b57\u7b26\u4e32\uff0c\u4ece\u5b57\u7b26\u4e32\u7684\u7b2c\u4e00\u4e2a\u4f4d\u7f6e\u5f00\u59cb\u4f9d\u6b21\u628a\u6bcf\u4e2a\u6570\u5b57\u5b57\u7b26\u8f6c\u6210\u6574\u6570\uff0c\u5e76\u8ba1\u7b97\u5176\u7d2f\u52a0\u548c\u3002
\u53c2\u8003\u4ee3\u7801\uff1a
#include "stdio.h" #include "string.h" int main() {char a[100];int i,sum=0;gets(a); for(i=0;a[i]!='\0';i++)//\u904d\u5386\u6c42\u7d2f\u52a0\u548c sum+=a[i]-'0';printf("%d\n",sum);return 0;}/*\u8fd0\u884c\u7ed3\u679c\uff1a1234515*/

/*
m n = 100 1000
100 121 144 225 400 441 484 676 900
Press any key to continue
*/
#include #include int hasRepNum(int n) {int a,b,c;if(n 1000) return 0;a = n % 10;n /= 10;b = n % 10;n /= 10;c = n % 10;if(a == b || b == c || c == a) return 1;return 0;}int main() {int i,m,n,t;printf("m n = ");scanf("%d%d",&m,&n);for(i = m; i <= n; ++i) {t = (int)sqrt(i);if(t * t == i && hasRepNum(i))printf("%d ",i);}printf("\n");return 0;}

#include <stdio.h>

void main()

{

int i,a,b,c,n;

scanf("%d",&n);

for(i=100;i<=n;i++)

{

a=i / 100;

b=i / 10 % 10;

c=i % 10;

if(a*b*c==32 && a+b+c==10)

printf("%d
",i);

}

}




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