c语言编程题，急4.定义一个包含10个整数的数组，实现先逐个从键盘输入这10个整数？ C语言编程，输入10个整数，分别按顺序和逆序输出
C\u8bed\u8a00\u7f16\u7a0b\u9898\uff1a\u5b9a\u4e49\u4e00\u4e2a\u6570\u7ec4\uff0c\u7136\u540e\u5229\u7528\u5faa\u73af\u4e3a\u6570\u7ec4\u8f93\u516510\u4e2a\u6574\u6570\uff0c\u7136\u540e\u518d\u5c06\u6570\u7ec4\u8f93\u51fa\uff0c\u8bf7\u95ee\u8be5\u600e\u4e48\u505a\uff1f#include
int main(){
int a[10]={},i,sum=0;
printf("\u8bf7\u8f93\u516510\u4e2a\u6574\u6570\uff1a\n");
for(i=0;i<10;i++){
scanf("%d",&a[i]);
sum+=a[i];
}
printf("10\u4e2a\u5143\u7d20\u548c\u4e3a\uff1a%d",sum);
return 0;
}
\u6269\u5c55\u8d44\u6599\uff1a
\u4e00\u4e2a\u6570\u7ec4\u4e2d\u7684\u6240\u6709\u5143\u7d20\u5177\u6709\u76f8\u540c\u7684\u6570\u636e\u7c7b\u578b\uff08\u5728C\u3001C++\u3001Java\u3001pascal\u4e2d\u90fd\u8fd9\u6837\u3002\u4f46\u4e5f\u5e76\u975e\u6240\u6709\u6d89\u53ca\u6570\u7ec4\u7684\u5730\u65b9\u90fd\u8fd9\u6837\uff0c\u6bd4\u5982\u5728Visual Foxpro\u4e2d\u7684\u6570\u7ec4\u5c31\u5e76\u6ca1\u8fd9\u6837\u7684\u8981\u6c42\uff09\u3002\u5f53\u7136\uff0c\u5f53\u6570\u636e\u7c7b\u578b\u4e3a Variant \u65f6\uff0c\u5404\u4e2a\u5143\u7d20\u80fd\u591f\u5305\u542b\u4e0d\u540c\u79cd\u7c7b\u7684\u6570\u636e\uff08\u5bf9\u8c61\u3001\u5b57\u7b26\u4e32\u3001\u6570\u503c\u7b49\u7b49\uff09\u3002\u53ef\u4ee5\u58f0\u660e\u4efb\u4f55\u57fa\u672c\u6570\u636e\u7c7b\u578b\u7684\u6570\u7ec4\uff0c\u5305\u62ec\u7528\u6237\u81ea\u5b9a\u4e49\u7c7b\u578b\u548c\u5bf9\u8c61\u53d8\u91cf\u3002
\u53c2\u8003\u8d44\u6599\u6765\u6e90\uff1a\u767e\u5ea6\u767e\u79d1-\u6570\u7ec4
C\u8bed\u8a00\u901a\u8fc7\u8f93\u5165\u5341\u4e2a\u6574\u6570\u7136\u540e\u5206\u522b\u987a\u5e8f\u548c\u9006\u5e8f\u8f93\u51fa\u7684\u7f16\u7a0b\u601d\u60f3\u548c\u65b9\u6cd5\u5982\u4e0b\uff1a
1.\u9996\u5148\u9700\u8981\u5b9a\u4e49\u4e00\u4e2a\u6574\u578b\u6570\u7ec4\u7528\u4e8e\u5b58\u50a8\u8f93\u5165\u768410\u4e2a\u6574\u6570\u3002\u8fd9\u91cc\u5b9a\u4e49\u4e00\u4e2a\u6570\u7ec4a\u3002
2.\u7136\u540e\u5229\u7528for\u5faa\u73af\uff0c\u63a5\u53d7\u4ece\u952e\u76d8\u8f93\u5165\u768410\u4e2a\u6574\u6570\u3002\u8fd9\u91cc\u4f7f\u7528i\u4f5c\u4e3a\u5faa\u73af\u7684\u6e38\u6807\u53d8\u91cf\u3002
3.\u8f93\u5165\u5b8c\u6bd5\u540e\uff0c\u518d\u6b21\u5229\u7528for\u5faa\u73af\u6765\u987a\u5e8f\u8f93\u51fa\u5b58\u50a8\u5728\u6570\u7ec4\u7684\u5341\u4e2a\u6570\u3002\u8fd9\u91cc\u540c\u6837\u4f7f\u7528\u5c40\u90e8\u53d8\u91cfi\u4f5c\u4e3a\u5faa\u73af\u7684\u6e38\u6807\u3002
4.\u63a5\u7740\uff0c\u518d\u6b21\u4f7f\u7528for\u5faa\u73af\u6765\u9006\u5e8f\u8f93\u51fa\u5b58\u50a8\u5728\u6570\u7ec4\u7684\u5341\u4e2a\u6574\u6570\u3002\u540c\u6837\u5730\uff0c\u8fd9\u91cc\u4ecd\u7136\u9700\u8981\u4e00\u4e2a\u5c40\u90e8\u53d8\u91cf\u4f5c\u4e3a\u5faa\u73af\u6e38\u6807\u3002\uff08\u65b9\u6cd5\u4e0e\u987a\u5e8f\u8f93\u51fa\u5927\u81f4\u76f8\u540c\uff09
5.\u4ee3\u7801\u7f16\u5199\u5b8c\u6210\u540e\uff0c\u70b9\u51fb\u8fd0\u884c\u7a0b\u5e8f\uff0c\u5728\u8c03\u8bd5\u7a0b\u5e8f\u7684\u7a97\u53e3\u5373\u53ef\u770b\u5230\u6700\u7ec8\u7684\u8fd0\u884c\u7ed3\u679c\u3002
4:
#include<iostream>
using namespace std;
int main(){
for(int i=0;i<10;i++){
int a;
cin>>a;
if(a%3==2 && a%5==3){
cout<<a;
}
}
return 0;
}
5:
#include<iostream>
using namespace std;
int main(){
int pos[10];
int neg[10];
int zero=0;
int t1=0,t2=0;
for(int i=0;i<10;i++){
int a;
cin>>a;
if(a>0){
pos[t1]=a;
t1++;
}else if(a<0){
neg[t2]=a;
t2++;
}else{
zero++;
}
}
cout<<"positive:"<<endl;
for(int i=0;i<t1;i++){
cout<<pos[i]<<endl;
}
cout<<"negative:"<<endl;
for(int i=0;i<t1;i++){
cout<<neg[i]<<endl;
}
cout<<"zero:"<<endl;
for(int i=0;i<t1;i++){
cout<<0<<endl;
}
return 0;
}
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