编写程序,利用Python中的方法和函数提取出给定列表5,8,-7,4,6,2,-3,0中的最大？ python实现给定一个列表判断里面是否有重复元素
\u7f16\u5199\u7a0b\u5e8f,\u5229\u7528Python Community\u8f6f\u4ef6\u53d6\u51fa\u7ed9\u5b9a\u5217\u88685,8,-7,4,6,2,-3,0\u4e2d\uff1f[code]
def maxNum(nums):
max = nums[0]
for i in range(0, len(nums) - 1):
if nums[i] > max:
max = nums[i]
return max
def delMinNum(nums):
minNum = nums[0]
for i in nums:
if i < minNum:
minNum = i
index = nums.index(minNum)
del nums[index]
return nums
def abs(nums):
absNumbs = []
for i in nums:
if i < 0:
i = -i
absNumbs.append(i)
return absNumbs
if __name__ == '__main__':
li = [5, 8, -7, 4, 6, 2, -3, 0]
print(maxNum(li))
print(delMinNum(li))
print(abs(delMinNum(li)))
[/code]
\u6709\u4e24\u4e2a\u65b9\u6cd5\uff1a
\u4f7f\u7528\u5217\u8868\u7684count\u65b9\u6cd5\uff0c\u56e0\u4e3acount\u65b9\u6cd5\u53ef\u4ee5\u505a\u5bf9\u8c61\u5185\u7684\u5143\u7d20\u8fdb\u884c\u51fa\u73b0\u6b21\u6570\u53e0\u52a0\u8ba1\u7b97
list1=[1,2,3,4,4,5,6,7]list1.count(1) #\u7ed3\u679c\u4e3a1list1.count(4) #\u7ed3\u679c\u4e3a2for i in list1: if list1.count(i)>=2: print('\u8be5\u5143\u7d20%s\u91cd\u590d'%i)#\u7ed3\u679c\uff1a\u8be5\u5143\u7d204\u91cd\u590d\u8be5\u5143\u7d204\u91cd\u590d #\u56e0\u4e3a\u8fed\u4ee3\u4e86\u4e24\u6b214\u6240\u4ee5\u6709\u4e24\u6b21\u8f93\u51fa\uff0c\u529f\u80fd\u662f\u5b9e\u73b0\u4e86\uff0c\u4f46\u662f\u5374\u6253\u5370\u4e86\u4e24\u6b21\uff0c\u6709\u70b9\u4e0d\u7406\u60f32.\u501f\u7528\u5de5\u5382\u51fd\u6570set()\u628a\u5bf9\u8c61\u8f6c\u4e3a\u96c6\u5408\u548c\u5217\u8868\u7684copy\u65b9\u6cd5\uff08\u6d45\u590d\u5236\uff09\uff0c\u96c6\u5408\u4f1a\u9ed8\u8ba4\u628a\u91cd\u590d\u5143\u7d20\u53bb\u6389
list1=[1,2,3,4,4,5,6,7]list2=list1.copy() #\u4e3a\u4e86\u4e0d\u7834\u574f\u539f\u6570\u636e\uff0c\u4e34\u65f6\u6d45\u590d\u5236\u7ed9\u53d8\u91cflist2list3=list(set(list2)) #\u4f7f\u7528set()\u51fd\u6570\u5c06list2\u8f6c\u4e3a\u96c6\u5408\u53bb\u6389\u91cd\u590d\u5143\u7d20\u53c8\u7528list()\u8f6c\u56de\u5217\u8868 for i in list3: #\u5bf9\u65e0\u91cd\u590d\u5143\u7d20\u7684\u5217\u8868list3\u8fed\u4ee3 if i in list2: list1.remove(i) #\u5f53list3\u5185\u7684\u5143\u7d20\u5b58\u5728\u4e8elist2\u4e2d,\u5219\u628a\u5176\u5143\u7d20\u4ecelist2\u4e2d\u5220\u9664\uff0c\u6700\u540e\u5c31\u4f1a\u7559\u4e0b\u91cd\u590d\u5143\u7d20print('list1:%s\u4e2d\u7684\u91cd\u590d\u5143\u7d20\u6709\uff1a%s'%(list1,list2)) #\u7ec4\u540e\u8f93\u51fa\u539f\u6570\u636elist1\u548c\u6700\u7ec8\u7ed3\u679clist2#\u7ed3\u679c\uff1alist1:[1, 2, 3, 4, 4, 5, 6, 7]\u4e2d\u7684\u91cd\u590d\u5143\u7d20\u6709\uff1a[4] #\u6548\u679c\u5b9e\u73b0\u4e86\uff0c\u4e5f\u6ca1\u95ee\u9898\uff0c\u5c31\u662f\u53d8\u91cf\u4f7f\u7528\u6709\u70b9\u591a\u3002\u770b\u4f60\u9009\u62e9\u4e86
return max(nums)
def maxNumberWithOutFunc(nums):
maxNumber = nums[0]
for n in nums:
if n > maxNumber:
maxNumber = n
return maxNumber
if __name__ == '__main__':
nums = [5, 8, -7, 4, 6, 2, -3, 0]
print("max is %d" % maxNumber(nums))
print("max is %d" % maxNumberWithOutFunc(nums))
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