python中如何统计字符串中各个字母的个数 怎样统计字符串中各字母的个数?

Python3.4 \u5206\u522b\u7edf\u8ba1\u5b57\u7b26\u4e32\u4e2d26\u4e2a\u5b57\u6bcd\u7684\u4e2a\u6570

import stringdef letter_frequency(s): s = s.lower() #\u5168\u90e8\u8f6c\u5c0f\u5199 l = [] for i in string.lowercase: l.append(s.count(i)) #\u7edf\u8ba1\u4e2a\u6570 return l #\u8fd4\u56de \u8fd0\u884c >>> print(letter_frequency('Asdasdad')) \u7ed3\u679c [3, 0, 0, 3, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 0]

\u8fd9\u4e2a\u6709\u70b9\u56f0\u96be\u54e6,\u4e3b\u8981\u662f\u95ee\u9898\u5f88\u7b80\u5355\u5566.\u8981case 26\u6b21\u5c31\u884c\u4e86.
\u60f3\u4e86\u4e00\u4e0b,\u8981CASE\u6765\u89e3\u51b3\u7684\u8bdd,\u898126\u4e2a\u5927\u5199\u4e0e26\u4e2a\u5c0f\u5199,\u517152\u4e2aCASE.\u4e0b\u9762\u662f\u7528\u6307\u9488\u6765\u64cd\u4f5c,\u5728VC6\u91cc\u9762\u6d4b\u8bd5\u53ef\u4ee5\u901a\u8fc7.
#include
#include
#include
const int N=50;
void main()
{
char array[N],*p;
int i,letter[52]={0},*pw;//52\u4e2a\u5b58\u50a8\u5927\u5199\u4e0e\u5c0f\u5199\u5b57\u6bcd
cout<<"Input a string:"<<endl;
p=gets(array);pw=letter;//1
for(;(p-array)<int(strlen(array));pw=letter,p++)//2
if(*p>='a'&&*p<='z') (*(pw+*p-'a'))++;
else if(*p>='A'&&*p<='Z') (*(pw+26+*p-'A'))++;
for(i=0;i<52;i++)//\u8fd9\u91cc\u8f93\u51faletter[0]-letter[51],\u5927\u4e8e\u96f6\u4e2a\u7684\u5c31\u8f93\u51fa
if(i0) cout<<"small letter: "<<char(i+'a')<<"="<<letter[i]<<endl;
else if(letter[i]>0) cout<<"Strong letter: "<<char(i+'A'-26)<<"="<<letter[i]<<endl;
}
//1 //2\u662f\u6307\u6307\u9488\u4ecearray[0]\u5230\u6d89\u730e\u5b57\u7b26\u4e32\u5c3e\u5927\u5199\u4e0e\u5c0f\u5199\u7684\u7edf\u8ba1.\u52a0A\u51cf26\u7b49\u662f\u8ddf\u636e\u5b57\u7b26\u5728ASCII\u4e2d\u7684\u503c\u6765\u8ba1\u7b97\u7684.\u6570\u636e\u7684\u8de8\u8d8a\u5e45\u5ea6\u5f88\u5927,\u6307\u9488\u904d\u5386\u4e5f\u5f88\u591a\u4e0d\u77e5\u9053\u8fd9\u6837\u89e3\u91ca\u80fd\u4e0d\u80fd\u770b\u5f97\u61c2.

用字符串count函数计算出现次数,防止重复,可以用字典来搜集结果:

代码

运行结果:


运行结果



import sys
vowel = ['a', 'e', 'i','o', 'u']

str = sys.argv[1]
sum = 0
for i in str:
if i in vowel:
sum+=1
print(sum)
使用方法:
将上面代码放入文件,例如test.py文件中
如果是linux或mac下给test.py加上可执行权限 //chmod +x test.py
执行格式: python test.py 字符串:

可以直接用collections里的Counter()

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