4个5相加怎么等于2 4个5相加怎么等于555?

4\u4e2a5\u76f8\u52a0\u7b49\u4e8e2O\u8bfb\u4f5c\u4ec0\u4e48

4\u4e2a5\u76f8\u52a0\u7b49\u4e8e2O\u8bfb\u4f5c\uff1a\u4e94\u52a0\u4e94\u52a0\u4e94\u52a0\u4e94\u7b49\u4e8e\u4e8c\u5341\u3002
\u7b97\u5f0f\u5199\u4f5c\uff1a5+5+5+5=20\u3002
\u7b97\u5f0f\u4e2d\u7684\u201c5\u201d\u51fa\u73b0\u4e86\u56db\u6b21\uff0c\u79f0\u4e3a\u76f8\u540c\u52a0\u6570\uff0c\u6570\u91cf\u4e00\u5171\u67094\u4e2a\uff0c\u8fd9\u79cd\u7279\u6b8a\u7684\u76f8\u540c\u52a0\u6570\u7684\u52a0\u6cd5\u7b97\u5f0f\u53ef\u4ee5\u5199\u505a\u4e58\u6cd5\u7b97\u5f0f\uff0c\u8bb0\u505a\uff1a4\u00d75=20\u3002
\u6269\u5c55\u8d44\u6599\uff1a

\u4e58\u6cd5\u7b97\u5f0f\u7684\u5199\u6cd5\u548c\u8bfb\u6cd5\uff1a
1\u3001\u8fde\u52a0\u7b97\u5f0f\u6539\u5199\u4e3a\u4e58\u6cd5\u7b97\u5f0f\u7684\u65b9\u6cd5\u3002\u6c42\u51e0\u4e2a\u76f8\u540c\u52a0\u6570\u7684\u548c\uff0c\u53ef\u4ee5\u7528\u4e58\u6cd5\u8ba1\u7b97\u3002\u5199\u4e58\u6cd5\u7b97\u5f0f\u65f6\uff0c\u53ef\u4ee5\u7528\u4e58\u6cd5\u8ba1\u7b97\u3002\u5199\u4e58\u6cd5\u7b97\u5f0f\u65f6\uff0c\u53ef\u4ee5\u5148\u5199\u76f8\u540c\u7684\u52a0\u6570\u3002
\u7136\u540e\u5199\u4e58\u53f7\uff0c\u518d\u5199\u76f8\u540c\u52a0\u6570\u7684\u4e2a\u6570\uff0c\u6700\u540e\u5199\u7b49\u53f7\u4e0e\u8fde\u52a0\u7684\u548c\uff1b\u4e5f\u53ef\u4ee5\u5148\u5199\u76f8\u540c\u52a0\u6570\u7684\u4e2a\u6570\uff0c\u7136\u540e\u5199\u4e58\u53f7\uff0c\u518d\u5199\u76f8\u540c\u52a0\u6570\uff0c\u6700\u540e\u5199\u7b49\u53f7\u4e0e\u8fde\u52a0\u7684\u548c\u3002
\u5982\uff1a4+4+4=12\u6539\u5199\u6210\u4e58\u6cd5\u7b97\u5f0f\u662f4\u00d73=12\u62163\u00d74=12
2\u3001\u4e58\u6cd5\u7b97\u5f0f\u7684\u8bfb\u6cd5\u3002\u8bfb\u4e58\u6cd5\u7b97\u5f0f\u65f6\uff0c\u8981\u6309\u7167\u7b97\u5f0f\u987a\u5e8f\u6765\u8bfb\u3002\u5982\uff1a6\u00d73=18\u8bfb\u4f5c\uff1a\u201c6\u4e583\u7b49\u4e8e18\u201d\u3002

4)+1/2)(x+3/]
=2(x+3/\u5b9e\u7cfb\u6570\u65b9\u7a0b\u5219\u6839\u5f0f\u5171\u8f6d\u865a\u6570
\u6240\u4ee5\u53e6\u4e00\u6839\u662f\u221a2+\u221a3i
\u7531\u97e6\u8fbe\u5b9a\u7406
x1+x2=-b/2
x1x2=c/2-i/2+i/y²2)²
=(x+\u221a5iy)(x-\u221a5iy)
(2)2x^2-6x+5
=2(x²2)
=2[(x²-3x+9/2)²-3x+5/-(i/4]
=2[(x+3/-5i²2
\u6240\u4ee5b=-(x1+x2)=-2\u221a2
c=2x1x2=2(2+3)=10
\uff081\uff09
\u539f\u5f0f=x²

要答案等于2的话可以这样算 5/5+5/5=2
要是都相加的话答案应该是 5+5+5+5=20

呵呵,四个零点五呗

5/5+5/5=2

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