甲醇在氧气中反应的化学方程式 甲醇(以X表示)在氧气中完全燃烧,反应的化学方程式为:2X+...
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2CH3OH+O2----Cu--->2HCHO+2H2O
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2CH3OH+3O2----->2CO2+4H2O
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完全燃烧:2CH3OH + 3O2 = 2CO2 + 4H2O部分氧化:2CH3OH + O2 = 2HCHO + 2H2O
CH3OH + O2 = HCOOH + H2O
氧气不足量下燃烧,得到CO最多的方程式是:CH3OH + O2 = CO + 2H2O
n(甲醇)=n(CO)=3.6/(2x18)=0.1 mol
2CH3OH+3O2=2CO2+4H2O(=上写点燃)2倍的甲醇与3倍的氧气反应生成2倍的二氧化碳和4倍的水
只有在氧气不足时才会生成一氧化碳,而且无论多么不足,也总要生成一部分二氧化碳的,所以一氧化碳的量不固定。
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