用python编程,输入一串字符串只有数字和字母,找出所有不重复的元素,并入一个列表输出结果 python2.7，输入一个字符串，统计其中每个字符出现的次...
\u7528python\u600e\u4e48\u5b9e\u73b0\uff0c\u627e\u51fa\u4e00\u4e2a\u5b57\u7b26\u4e32\u4e2d\u7684\u91cd\u590d\u5b57\u7b26\u5b50\u4e32\u548c\u5b57\u7b26\u4e32\u6570\u91cf?\u4ee3\u7801\u5982\u4e0b:
\u3010\u5907\u6ce8\u3011:
1. \u7528str.split(',')\u53ea\u80fd\u5206\u9694\u9017\u53f7\u4e00\u79cd\uff1b\u5982\u679c\u6d89\u53ca\u5230\u591a\u91cd\u5206\u9694\u7684\u8bdd\u5c31\u9700\u8981\u4f7f\u7528re.split(',|:')\u3002
2. \u539f\u5b57\u7b26\u4e32\u4ee5\u9017\u53f7\u5206\u9694\u7684\uff0c\u540e\u9762\u6709\u4e00\u4e2a\u6216\u591a\u4e2a\u5b57\u7b26\u4e32\uff0c\u6240\u4ee5re.split(', | ')\u3002
3. \u6267\u884cre.split(r', | ', S)\u64cd\u4f5c\u4e4b\u540e\uff0c\u5217\u8868\u4e2d\u4f1a\u4ea7\u751f\u5927\u91cf\u7684''\uff0c\u5c31\u9700\u8981\u5c06filter\u8fc7\u6ee4\u6389\u3002
4. \u4f7f\u7528L.count(x) == 1 \u6216\u8005 L.count(x) > 1\u6765\u4fdd\u7559\u91cd\u590d\u9879\u6216\uff0c\u975e\u91cd\u590d\u9879\u3002
5. set(L)\u5219\u662f\u4fdd\u7559\u5217\u8868\u4e2d\u7684\u552f\u4e00\u9879\uff0c\u518d\u7528list()\u5c06\u5176\u8f6c\u6362\u4e3a\u5217\u8868\u3002
6. \u4f7f\u7528', '.join(L)\uff0c\u5c06\u5217\u8868\u62fc\u63a5\u6210\u6211\u4eec\u60f3\u8981\u7684\u5b57\u7b26\u4e32\u3002
str=input("\u8bf7\u8f93\u5165\u4e00\u4e32\u5b57\u7b26")
str1=str.lower()
str2={}
for i in str1:
str2[i]=str1.count(i)
print(str2)
print([e for e in s if 1==s.count(e)])
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绛旓細owel = ['a','e','i','o','u']s = 'hello world'for i in s:if i in owel:s2 = s2 + i.capitalize()else:s2 = s2 +i print(s2)
绛旓細寰堟槑鏄惧崟璇嶆槸浠ョ┖鏍煎尯鍒嗙殑濡傛灉鐩哥粺璁″緢绠鍗曪紝浠ョ┖鏍煎垎鍓叉垚鍒楄〃锛屽幓闄ょ┖椤癸紝鍒楄〃闀垮害灏辨槸鍗曡瘝涓暟浜 def word_len(s): return len([i for i in s.split(' ') if i])浣跨敤 s = 'I am a boy!'print word_len(s)
