用C语言编写一个将数组由小到大顺序排列,范围为5到10,数组由键盘输入,显示排列后的数组,跪求高手! c语言问题,把一维数组的N(N=10)个元素按由小到大的顺序...

\u7f16\u5199C\u8bed\u8a00\u7a0b\u5e8f\uff0c\u628a\u4e00\u4e2a\u6570\u7ec4\u6309\u4ece\u5c0f\u5230\u5927\u7684\u6b21\u5e8f\u6392\u5217\u8d77\u6765

\u6e90\u7a0b\u5e8f\u4ee5\u53ca\u7b97\u6cd5\u6ce8\u91ca\u5982\u4e0b\uff1a
#define _CRT_SECURE_NO_WARNINGS//VS\u7f16\u8bd1\u73af\u5883\u9700\u8981\u8fdb\u884c\u5b8f\u5b9a\u4e49\uff0cVC6.0\u53ef\u5ffd\u7565
#include//\u8f93\u5165\u8f93\u51fa\u5934\u6587\u4ef6
int main()
{
int number[10], New_number[10];//\u5b9a\u4e49\u6570\u7ec4\u7684\u6570\u636e\u7c7b\u578b\u4e3a\u6574\u578b
int i, j, m, n, k;//\u5b9a\u4e49\u53d8\u91cf\u7684\u6570\u636e\u7c7b\u578b\u4e3a\u6574\u578b
printf("input 10 number\uff1a");//\u6587\u5b57\u63d0\u793a
for (i = 0; i <= 9; i++)//\u7528\u5faa\u73af\u8f93\u5165\u6570\u503c\u7ed9\u6570\u7ec4number\u5e76\u8d4b\u7ed9\u6570\u7ec4New_number
{
scanf("%d", &number[i]);//\u8f93\u516510\u4e2a\u6574\u5f62\u6570\u5b57\u5230\u6570\u7ec4\u4e2d
New_number[i] = number[i];//\u6570\u7ec4number\u5143\u7d20\u8d4b\u7ed9\u6570\u7ec4New_number
}
for (n = 0; n <= 8; n++)//\u8981\u8fdb\u884c(10-1)\u7ec4\u6bd4\u8f83
for (j = 0; j <= 8 - n; j++)//\u6bcf\u7ec4\u8fdb\u884c(10\u51cf\u7b2c\u51e0\u7ec4)\u6b21\u6bd4\u8f83
{
if (number[j] > number[j + 1])//\u6bd4\u8f83\u5927\u5c0f\u5e76\u5c06\u5c0f\u7684\u8d4b\u7ed9\u524d\u9762\u7684\u6570\u7ec4
{
k = number[j];//\u5c06\u76f8\u5bf9\u8f83\u5927\u7684\u5143\u7d20\u8d4b\u503c\u7ed9\u4e2d\u95f4\u5143\u7d20
number[j] = number[j + 1];//\u5c06\u76f8\u5bf9\u8f83\u5c0f\u7684\u5143\u7d20\u9001\u8fbe\u524d\u9762\u4e00\u4e2a\u4f4d\u7f6e
number[j + 1] = k;//\u5c06\u4e2d\u95f4\u53d8\u91cf\u5143\u7d20\u9001\u7ed9\u540e\u9762\u4e00\u4e2a\u4f4d\u7f6e
}
if (New_number[j] < New_number[j + 1])//\u6bd4\u8f83\u5927\u5c0f\u5e76\u5c06\u5927\u7684\u8d4b\u7ed9\u524d\u9762\u7684\u6570\u7ec4
{
k = New_number[j + 1];//\u5c06\u76f8\u5bf9\u8f83\u5c0f\u7684\u5143\u7d20\u8d4b\u503c\u7ed9\u4e2d\u95f4\u5143\u7d20
New_number[j + 1] = New_number[j];//\u5c06\u76f8\u5bf9\u8f83\u5927\u7684\u5143\u7d20\u9001\u8fbe\u524d\u9762\u4e00\u4e2a\u4f4d\u7f6e
New_number[j] = k;//\u5c06\u4e2d\u95f4\u53d8\u91cf\u5143\u7d20\u9001\u7ed9\u540e\u9762\u4e00\u4e2a\u4f4d\u7f6e
}
}
printf("min-->max\uff1a\n");//\u6587\u5b57\u63d0\u793a
for (m = 0; m <= 9; m++)//\u4f9d\u6b21\u4ece\u5c0f\u5230\u5927\u8f93\u51fa
printf("%d ", number[m]);//\u8f93\u51fa\u5143\u7d20
printf("\n");
printf("max-->min\uff1a\n");//\u6587\u5b57\u63d0\u793a
for (m = 0; m <= 9; m++)//\u4f9d\u6b21\u4ece\u5927\u5230\u5c0f\u8f93\u51fa
printf("%d ", New_number[m]);//\u8f93\u51fa\u5143\u7d20
printf("\n");
return 0;
}
\u7a0b\u5e8f\u8fd0\u884c\u7ed3\u679c\u5982\u4e0b\uff1a



\u6269\u5c55\u8d44\u6599\uff1a
\u5176\u4ed6\u7b80\u5355\u5b9e\u73b0\u7a0b\u5e8f\uff1a
#include
int main()
{
int a[10]={0};
int i,j,temp;
for(i = 0;i<10;i++)
{
scanf("%d",&a[i]);
}
for(i = 0;i<10;i++)
{
for(j = 0;j<10-i-1;j++)
{
if(a[j]>a[j+1])
{
temp = a[j];
a[j] = a[j+1];
a[j+1] = temp;
}
}
}
for(i = 0;i<10;i++)
printf("%d ",a[i]);
return 0;
}

\u6839\u636e\u9898\u610f\u53ef\u5f97\u4ee3\u7801\uff1a
#include#define N 10int main(){ int a[N], i, j, k; //\u8f93\u5165 for(i = 0; i a[j]){ k = j; } } if (k != i){ j = a[k]; a[k] = a[i]; a[i] = j; } } //\u8f93\u51fa for (i = 0; i < N; ++i){ printf ("%d ", a[i]); } printf ("\n"); return 0;}

已测试,结果如图所示

#include<stdio.h>

int main()

{

int a[6]={0,0,0,0,0,0},temp,i,j;

char ch;

scanf("%d",&temp);

ch=getchar();

  while(ch!='
'){

a[temp-5]++;

scanf("%d",&temp);

ch=getchar();

}

a[temp-5]++;

for(i=0;i<6;i++)

for(j=0;j<a[i];j++)

printf("%d ",i+5);

printf("
");

return 0;

}



#include<stdio.h>
int main()
{
int a[5];
int i,j,min;
printf("原数列:");
for(i=0;i<5;i++)
{
scanf("%d",&a[i]);
}

for(i=0;i<5;)
{
min=a[i];
for(j=i+1;j<5;j++)
{
if(min>a[j])
{
min=a[j];
a[j]=a[i];
}
a[i]=min;
}
printf("%d\t",a[i]);
i++;
}

return 0;
}

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