关于高一物理。 高一物理必修一所有公式

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1、向上的速度V=VoSin30°=400m/s;上升时间为t=Vo/g=40s
炮弹能上到的最高高度是h=1/2gt^2=8000m;所以最少为8000m。
2、先假设初速度为Vo,方向为与地面成的角度为O则有:
1/2gt^2=h代入数据有1/2*10*t^2=20解得时间t=2s;
向上初速度为:V=VoSinO-gt,由刚好到达20m处得,到达20m处时V=0;
则有VoSinO=gt=10*2=20m/s;
水平方向速度为匀速运动速度为VoCosO,水平位移为30m,则有VoCosOt=30即VoCosO=15
由VoCosO=15、VoSinO=20可求出Vo=25,O=53°

1.vsin30=400m/s
(vsin30)*2=2gh
解得 h=8000m
2.(vsinθ)*2=2gh
vsinθ=gt
x=vcosθt
解得tanθ=3
v=20(15)*1/2/3m/s

打点计时器的工作原理是利用交流电的频率50HZ,振针频率也是50HZ,这与电压无关。。。。3min汽车行了3*60*20=3600m再加上相隔1000m共计4600m。设加速度为a、加速行了x用时t、匀速行了s用时3*610-t。。。。则:{x=(1/2)at^2,at=30,s=30*(3*60-t),x+s=4600}联立解得:t=60,所以a=0.5

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