四个阻值相同的电阻并联,则这四个电阻并联后的总阻值是R总/4? 有4个阻值都是R的电阻，每两个串联后再并联，并联后的总电阻是...
\u67094\u4e2a\u963b\u503c\u90fd\u662fR\u7684\u7535\u963b\uff0c\u6bcf\u4e24\u4e2a\u4e32\u8054\u540e\u518d\u5e76\u8054\uff0c\u5e76\u8054\u540e\u7684\u603b\u7535\u963b\u662f\u591a\u5c11\uff1f\u5148\u7b97\u4e32\u8054\u7684 \u4e00\u5171\u662f2R\u963b\u503c\uff0c\u8fd9\u4e24\u4e2a2R\u5e76\u8054\u5e94\u8be5\u662f\u4e00\u534a\uff0c\u4e5f\u5c31\u662fR
\u7535\u963b1\u30012\u4e32\u8054\u540e\u7684\u7535\u963b\u4e4b\u548c\u662f2R\uff0c
\u7535\u963b3\u30014\u4e32\u8054\u540e\u7684\u7535\u963b\u4e4b\u548c\u4e5f\u662f2R\uff0c
\u518d\u5e76\u8054\u540e\u7684\u603b\u7535\u963b\uff1aR\u603b=\uff082R*2R)/(2R+2R) = R
1/R总=1/R+1/R+1/R+1/R=4/R
R总=R/4
绛旓細鍥涗釜骞惰仈锛屽洓涓涓茶仈锛1涓3骞讹紝2涓2骞讹紝涓や袱鐩镐覆鍐嶅苟锛屽厛3涓覆鑱斿悗骞1涓
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绛旓細鐢甸樆1銆2涓茶仈鍚鐨勭數闃涔嬪拰鏄2R锛岀數闃3銆4涓茶仈鍚庣殑鐢甸樆涔嬪拰涔熸槸2R锛屽啀骞惰仈鍚庣殑鎬荤數闃伙細R鎬=锛2R*2R)/(2R+2R) = R
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绛旓細1.褰揝闂悎锛孲'鏂紑鏃讹紝R1銆丷3涓茶仈鍚庢瀯鎴愪竴鏉℃敮璺锛岀數闃涓篟'=R1+R3=4娆,R2銆丷4涓茶仈鍚庢瀯鎴愪竴鏉℃敮璺紝鐢甸樆涓篟"=R2+R4=6娆э紝鏍规嵁骞惰仈鐢佃矾鍚勬敮璺袱绔數鍘鐩哥瓑寰桰1:I2=R":R'=3:2.2.褰揝鍜孲'閮介棴鍚堟椂锛孯1銆丷2骞惰仈锛闃诲涓2/3锛夊悗鍐嶄笌R3銆丷4缁勬垚鐨勫苟鑱锛堥樆鍊间负12/7锛夌數璺覆鑱旓紝鎬婚樆鍊间负...
