怎么在C++中用Vector存放不同类型的数据.. C++的vector存储数据的问题
C++vector\u5bb9\u5668\u5bb9\u7eb3\u4e0d\u540c\u7ed3\u6784\u7684\u6570\u636evector vec1;
vector vec2;
vector vec3;
vector vec4;
vector vec5;
vector vec6;
vector vec7;
vector vec8;
......
\u5982\u679c\u4f60\u7684\u6307\u9488\u5185\u5b58\u7a7a\u95f4\u5206\u914d\u5728\u5806\u4e0a\uff0c\u76f4\u63a5\u5b9a\u4e49std::vector v; v.push_back(p); //\u5b58\u653e\u7684\u662f\u6307\u9488
\u5982\u679c\u5206\u914d\u5728\u6808\u4e0a\uff0c\u53ef\u4ee5\u5b9a\u4e49std::vector v; v.push_back(*p); //\u5b58\u653e\u7684\u662f\u7c7b\u7684\u5b9e\u4f8b
template<class T,class A = allocator<T> > struct vector {
typedef typename A::value_type value_type;
typedef typename A::reference reference;
typedef A allocator_type;
typedef typename A::pointer pointer;
typedef typename A::size_type size_type;
// ...
explicit vector() throw() : sz(0), random_ptr() { }
// ...
void push_back(const value_type& v) {
!random_ptr ? random_ptr = new T(v): new(random_ptr+sz) T(v);
sz++;
}
reference operator[](size_type ind) { return *(random_ptr+ind); }
size_type size() const { return sz; }
// ...
private:
size_type sz;
pointer random_ptr;
};
}
在此我并没有考虑到push_back()牵涉到的reserve()，只是大致上如此。如果你要想这段代码能在main()下运行，请定义一个合适的析构函数。
vector<anything_t *>
其中
typedef struct taganything
{
void *data;
int length;
} anything_t;
boost.any我不懂。
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