（2011?杨浦区一模）如图，图象所反映的物理情景是：物体以大小不变的初速度v0沿木板滑动，若木板倾角θ （2011?杨浦区一模）如图所示是A、B、C三个体积完全相同...

\u5982\u56fe\uff0c\u56fe\u8c61\u6240\u53cd\u6620\u7684\u7269\u7406\u60c5\u666f\u662f\uff1a\u7269\u4f53\u4ee5\u5927\u5c0f\u4e0d\u53d8\u7684\u521d\u901f\u5ea6v 0 \u6cbf\u6728\u677f\u6ed1\u52a8\uff0c\u82e5\u6728\u677f\u503e\u89d2\u03b8\u4e0d\u540c\uff0c\u7269\u4f53\u6cbf\u6728\u677f\u4e0a

\uff081\uff09\u5f53\u03b8=90º\u65f6\uff0c\u7269\u4f53\u505a\u7ad6\u76f4\u4e0a\u629b\u8fd0\u52a8\uff0c = =10 ="17.3m/s " \uff08\u5f974\u5206\uff09\uff082\uff09\u5f53\u03b8=0º\u65f6\uff0c\u6839\u636e\u52a8\u80fd\u5b9a\u7406\u5f97\uff0c 2 \uff08\u5f974\u5206\uff09\uff083\uff09\u52a0\u901f\u5ea6 \u5f97\u5230\uff0c\u5f53\u03b8=53º\u65f6\uff0c\u03b1\u6709\u6781\u5927\u503c \u7531\u52a8\u80fd\u5b9a\u7406\u5f97\uff0c \uff0c\u6240\u4ee5 \u6240\u4ee5P\u70b9\u5750\u6807\uff08 \uff09 \uff08\u5f976\u5206\uff09 \u7565

\u7531\u56fe\u77e5\uff0c\u4e09\u4e2a\u7269\u4f53\u6392\u5f00\u6c34\u7684\u4f53\u79ef\uff1avA\uff1cvB\uff1cvC\uff0c\u2235F\u6d6e=\u03c1\u6c34v\u6392g\uff0c\u2234\u4e09\u4e2a\u7269\u4f53\u53d7\u5230\u7684\u6d6e\u529b\uff1aFA\uff1cFB\uff1cFC\uff0e\u6545\u9009C\uff0e

（1）当θ=90°时，物体做竖直上抛运动，
由v²=2gx得：
物体初速度的大小v0＝

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