怎样用C语言将字符转化成十六进制整数 C语言怎么将一个十进制的整数转换成十六进制的字符串？
C\u8bed\u8a00\u5982\u4f55\u628a11\u4f4d16\u8fdb\u5236\u5b57\u7b26\u4e32\u8f6c\u621016\u8fdb\u5236\u6570\uff1f#include
#include
voidmain()
{
char*p="0x1b";
char*str;
longi=strtol(p,&str,16);
printf("%d\r\n",i);
}
//\u8f93\u51fa\u503c\u4e3a27
\u53c2\u6570base\u4ee3\u8868\u91c7\u7528\u7684\u8fdb\u5236\u65b9\u5f0f\uff0c\u5982base\u503c\u4e3a10\u5219\u91c7\u752810\u8fdb\u5236\uff0c\u82e5base\u503c\u4e3a16\u5219\u91c7\u752816\u8fdb\u5236\u7b49\u3002\u5f53base\u503c\u4e3a0\u65f6\u5219\u662f\u91c7\u752810\u8fdb\u5236\u505a\u8f6c\u6362\uff0c\u4f46\u9047\u5230\u5982\u20190x\u2019\u524d\u7f6e\u5b57\u7b26\u5219\u4f1a\u4f7f\u752816\u8fdb\u5236\u505a\u8f6c\u6362\u3001\u9047\u5230\u20190\u2019\u524d\u7f6e\u5b57\u7b26\u800c\u4e0d\u662f\u20190x\u2019\u7684\u65f6\u5019\u4f1a\u4f7f\u75288\u8fdb\u5236\u505a\u8f6c\u6362\u3002
\u6269\u5c55\u8d44\u6599
C\u8bed\u8a00\u5341\u8fdb\u5236\u8f6c2\uff5e16\u8fdb\u5236
#include
voidtrans(intdata,intbase)
{
intx[64],k,i=0;
while(data)
{
x[i]=data%base;
data/=base;
i++;
}
for(k=i-1;k>=0;k--)
if(x[k]<10)
printf("%d",x[k]);
elseif(x[k]<=16)
printf("%c",'A'+x[k]-10);
}
intmain(void)
{
intnum,base;
scanf("%d%d",&num,&base);
if(base16)
{
printf("dataerror\n");
return;
}
printf("number=%dbase=%d\n",num,base);
trans(num,base);
printf("\n");
return0;
}
\u8981\u8f6c\u6210\u5b57\u7b26\u4e32 \u5176\u5b9e\u4e0d\u9700\u8981\u81ea\u5df1\u5199\u591a\u5c11\u7a0b\u5e8f \u501f\u7528sprintf\u5c31\u53ef\u4ee5\u4e86
char s[20];
int a;
scanf("%d",&a);
sprintf(s, "%x", a);
\u8fd9\u6837 s\u4e2d\u5c31\u662fa\u768416\u8fdb\u5236\u5b57\u7b26\u4e32\u4e86\u3002
#include<stdio.h>
void main()
{
char c='A';
printf("十六进制：%0x\n十进制：%d\n",c,c);
}
写个MAIN 方法
ASC标准，直接找
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绛旓細i]>='A' && str[i]<='F') temp[i]=str[i]-'A'+0x0A;else if(str[i]>='a' && str[i]<='f') temp[i]=str[i]-'a'+0x0a;else { printf("闈16杩涘埗瀛楃锛岀▼搴忛鍑篭n");return;} } buf[0] = temp[0]*16 + temp[1];printf("buf[0] 涓 0x%x\n",buf[0]);} ...
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