C程序中怎样输入多行字符 c中如何读入多行字符串
c\u8bed\u8a00\u4e2d\u53ef\u4ee5\u8f93\u5165\u591a\u4e2a\u5b57\u7b26\u7684\u662f\u4ec0\u4e48\u7528\u5b57\u7b26\u6570\u7ec4\u4fdd\u5b58\uff0c\u8f93\u5165\u65f6\u7528gets\u6216\u8005scanf ("%s", str);\u5176\u4e2d\u524d\u8005\u53ef\u4ee5\u83b7\u53d6\u7a7a\u683c\uff0c\u540e\u8005\u4e0d\u80fd\u83b7\u53d6\u7a7a\u7a7a\u683c\u3002
\u5982:
char str[256];
gets(str);\u6216scanf ("%s", str);
\u7b80\u5355\uff0c\u7528fgets\uff0b\u5faa\u73af\u5c31\u53ef\u4ee5\u4e86\u3002 \u4e00\u822c\u4e0d\u8981\u7528scanf\uff0c\u56e0\u4e3a\u4f7f\u7528\u4e0d\u597d\u5c31\u4e0d\u5b89\u5168\uff1b \u4e5f\u5c3d\u91cf\u4e0d\u8981\u7528gets\uff0c \u5177\u4f53\u53c2\u770bC-FAQ 7.1\u3002
\u4f8b\u5b50\u5982\u4e0b\uff1a
#include
#include
#define BUFF_SIZE 128
int main(int argc, char **argv)
{
int N = 3;
char buffer[N][BUFF_SIZE];
char *p;
int i;
printf("Total input %d times.\n",N);
for (i = 0; i < N; i++)
{
printf("%d: ", i);
fgets(buffer[i], BUFF_SIZE, stdin);
if((p = strchr(buffer[i], '\n')) != NULL)
*p = '\0';
}
printf("\nOutput:\n");
for (i=0; i<N;i++)
printf("%s\n", buffer[i]);
return 0;
}
具体算法：
if(strcmp(string, "\0") != 0)
strcat(string, "\n");
#include<stdlib.h>
# include<stdio.h>
# include<string.h>
int main()
{
char str[10][100];
int i=0,j=0;
while(1)
{
gets(str[i]);
if(strcmp(str[i],"q")==0)
break;
++i;
}
}
用二维数组实现 输入q退出
输入？ 多行？
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