数学建模（选修课) 飞机货运问题？只求一个懂数学建模会用LINGO软件的大神来帮我计算下。只求结果。急急

\u6570\u5b66\u5efa\u6a21 \u6c42LINGO\u7a0b\u5e8f\u89e3\u51b3 \u65c5\u884c\u7ebf\u8def\u95ee\u9898\uff0c \u8c22\u8c22\u5927\u795e\uff0c\u6025\uff01

\u6709\u5f88\u591a\u65b9\u6cd5\u53ef\u4ee5\u5b9e\u73b0\uff0c\u6bd4\u5982\u628a\u6574\u4e2a\u7f51\u7edc\u770b\u4f5c\u51e0\u4e2a\u4e0d\u540c\u7684\u9636\u6bb5\uff0c\u4f5c\u4e3a\u52a8\u6001\u89c4\u5212\u95ee\u9898\u6c42\u89e3\u3002

\u4f60\u628a\u5206\u53f7\u540e\u9762\u90a3\u4e9b\u7a7a\u767d\u5b57\u7b26\u5220\u4e86\u5c31\u884c\u4e86 \u91cc\u9762\u53ef\u80fd\u6709\u975e\u6cd5\u5b57\u7b26

结果中x(i,j)表示第i个舱中应该装j吨货物 最高利润 137258.8
X( 1, 1) 10.55556 0.000000
X( 1, 2) 0.000000 0.000000
X( 1, 3) 0.000000 11.76471
X( 1, 4) 4.444444 0.000000
X( 2, 1) 0.000000 0.000000
X( 2, 2) 9.461538 0.000000
X( 2, 3) 0.000000 11.76471
X( 2, 4) 6.538462 0.000000
X( 3, 1) 5.503268 0.000000
X( 3, 2) 3.479638 0.000000
X( 3, 3) 0.000000 11.76471
X( 3, 4) 1.017094 0.000000

model:
sets:
s1/1..3/:tw,tv;
s2/1..4/:w,v,p;
ss(s1,s2):x;
endsets
data:
tw=15 16 10;
tv=6800 8700 5300;
w=18 15 23 12;
v=480 650 580 390;
p=3200 3900 3600 2950;
enddata
max=@sum(ss(i,j):x(i,j)*p(j));
@for(s1(i):@sum(s2(j):x(i,j))<=tw(i));
@for(s1(i):@sum(s2(j):v(j)*x(i,j))<=tv(i));
@for(s2(j):@sum(s1(i):x(i,j))<=w(j));
@for(s1(m):@for(s1(n)|n#gt#m:@sum(s2(j):x(m,j))/tw(m)=@sum(s2(j):x(n,j))/tw(n)));
end

Lindo程序：
MAX 3200 X11 + 3200 X12 + 3200 X13 + 3900 X21 + 3900 X22 + 3900 X23 + 3600 X31 + 3600 X32 + 3600 X33 + 2950 X41 + 2950 X42 + 2950 X43
SUBJECT TO
2) X11 + X21 + X31 + X41 < 15
3) X12 + X22 + X32 + X42 < 16
4) X13 + X23 + X33 + X43 < 10
5) 480 X11 + 650 X21 + 580 X31 + 390 X41 < 6800
6) 480 X12 + 650 X22 + 580 X32 + 390 X42 < 8700
7) 480 X13 + 650 X23 + 580 X33 + 390 X43 < 5300
8) 16 X11 + 16 X21 + 16 X31 + 16 X41 - 15 X12 - 15 X22 - 15 X32 - 15 X42 = 0
9) 10 X12 + 10 X22 + 10 X32 + 10 X42 - 16 X13 - 16 X23 - 16 X33 - 16 X43 = 0
10) 15X13 + 15X23 + 15X33 + 15X43 - 10 X11 - 10 X21 - 10 X31 - 10 X41 = 0
11) X11 + X12 + X13 < 18
12) X21 + X22 + X23 < 15
13) X31 + X32 + X33 < 23
14) X41 + X42 + X43 < 12
END

lingo在这个基础上改下格式就好

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