(1)写出抛物线y=x 2 -2x-1的开口方向、对称轴和与x轴的交点坐标;(2)将此抛物线向下平移2个单位,再
\u5c06\u629b\u7269\u7ebfy\uff1d2x^2\uff0b6x\uff0b1\u7684\u5bf9\u79f0\u8f74\u5411x\u8f74\u7684\u6b63\u65b9\u5411\u5e73\u79fb2\u4e2a\u5355\u4f4d\uff0c\u5f97\u5230\u7684\u629b\u7269\u7ebf\u662fy=2(x+3/2)²-7/2
y'=2(x-1/2)²-7/2
y=2x^2-2x-1
(1)抛物线y=x 2 -2x-1的开口向上,对称轴为x=1, 令y=0,则x 2 -2x-1=0,由求根公式得: x 1 =1+
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