设系统特征方程为s４＋6s３+12s２+10s+3＝0 试用劳斯－赫尔维茨稳定判据判别该系统的稳定 跪求：“设系统闭环特征方程为0.02S3+0.3S2+S+K...
\u8bbe\u7cfb\u7edf\u7279\u5f81\u65b9\u7a0b\u5f0f\u4e3aS^4+3S^3+S^2+3S+1=0\u8bd5\u7528\u52b3\u65af\u5224\u636e\u5224\u65ad\u7cfb\u7edf\u7684\u7a33\u5b9a\u6027\uff0c\u82e5\u7cfb\u7edf\u4e0d\u7a33\u5b9a\u4e0d\u7a33\u5b9a\uff0c\u4e24\u4e2a\u6839
\u56e0\u4e3a3\uff08\u03b5-3\uff09/\u03b5\u5c0f\u4e8e\u96f6\uff0c\u4e0d\u7a33\u5b9a\uff0c\u7b2c\u4e00\u5217\u53d8\u53f7\u4e24\u6b21\u6240\u4ee5\u6709\u4e24\u4e2a\u6839
\u8fd9\u4e2a\u95ee\u9898\u662f\u5f88\u7b80\u5355\u554a
\u7a33\u5b9a\u6027\u5224\u636e\u9759\u6001\u8bef\u5dee\u7cfb\u6570
1\u3002\u95ed\u73af\u7279\u5f81\u65b9\u7a0bD\uff08S\uff09= S\uff080.1S +1\uff09\uff080.2S +1\uff09+ K = 0.02\u79d2^ 3 +0.3 ^ 2 + + K
\u53ea\u6709\u4e09\u9636\u8d6b\u5c14\u7ef4\u8328\u884c\u4e86\uff0c\u4e0d\u8981\u6709\u52b3\u65af\u5224\u636e\u3002
\u7a33\u5b9a\u6027\u8981\u6c42\u7684\u5fc5\u8981\u6761\u4ef6K> 0
D3 =
| 0.3 K 0 |
| 0.02 1 0 |
0 0.3 | K |
= K\u53e0\u52a0\u5b9a\u7406\uff080.3-0.02K\uff09> 0
0 <K <15
2\u7cfb\u7edf\u4e3aI\u578b\u7cfb\u7edf
\u7136\u540e\u4e3a\u4e86\u66f4\u591a\u7684\u4fe1\u53f7\u9519\u8bef0\u5bf92T\u8fd9\u90e8\u5206\u5761\u5ea6\u8bef\u5dee\u4e3a2 / K
2 / K = 0.2 K = 10
\u8bf7\u6ce8\u610f\uff0c\u53ea\u6709\u7b2c\u4e8c\u4e2a\u95ee\u9898\uff0c\u5fc5\u987b\u5728\u524d\u9762\u7684\u53e5\u5b50\u7a33\u5b9a\u7684\u5185\u5bb9\u5199\u7684\u7b2c\u4e00\u90e8\u5206\uff0c\u56e0\u4e3a\u4e0d\u7a33\u5b9a\u7684\uff0c\u5982\u679c\u6ca1\u6709\u5728\u6240\u6709\u7684\u7a33\u6001\u8bef\u5dee\u3002
\u8865\u5145\u8bf4\uff1a
\u52b3\u65af
^ 3 0.02 1
^ 2 0.3 K
^ 1\uff080.3-0.02K\uff09/ 0.3 0 S ^ 0 K
\u7a33\u5b9a\uff0c\u76f8\u540c\u6570\u91cf\u5927\u4e8e0\u7684\u7b2c\u4e00\u5217
\uff080.3-0.02K\uff09/ 0.3>
K\u8868>
0 <K <15
s4; 1 12 3
s3; 6 10 0
s2; (6*12-1*10)/6>0 3
s1; {10*(6*12-1*10)-6平方*3}/6*12-1*10>0
s0; 3
系统第一列都大于0故系统是稳定的
表示，专业性很强，看不懂啊。
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