求解数学题！！
\u6c42\u89e3\u6570\u5b66\u9898\uff01\u89e3\uff1a\u8bbe\u7b2c\u4e00\u5929\u751f\u4ea7\u4e86x\u53f0\u673a\u5668.
400/x - 1 -\uff08400-x\uff09/3x=2
\u89e3\u5f97\uff1ax=100
\u7ecf\u68c0\u9a8c\uff1ax=100\u662f\u7528\u65b9\u7a0b\u7684\u89e3\u3002
\u7b54\uff1a\u7b2c\u4e00\u5929\u751f\u4ea7\u4e86100\u53f0\u673a\u5668.
tan\u03b1=2
\u6240\u4ee5sina/cosa=2
\u53c8\u56e0\u4e3a sina^2+cos^2=1
\u6240\u4ee5sina=2/\u221a5,cosa=1/\u221a5
\u6216\u8005sina=-2/\u221a5,cosa=-1/\u221a5
\u6240\u4ee5sin2a=2sinacosa=4/5
cos4Pi=1，结果很明显了，1/25
cos0也等于1，它是以2Pi为周期的函数。
绛旓細璁惧叕姣旀槸q锛屽垯鐢盿2=-1/25鍜宎5=-5寰楋細a5/a2=q^3=125,瑙寰楋細q=5锛屼粠鑰宎2=5a1=-1/25锛宎1=-1/125锛屾墍浠ワ細an=锛-1/125)*5^(n-1),浠n=-125锛屽嵆锛氾紙-1/125)*5^(n-1)=-125锛岃В寰楋細n=7锛屾晠 -125鏄鏁板垪鐨勭7椤
绛旓細瑙ｏ細宸茬煡 x+y-z = 2 鎵浠 y-z = 2-x 鍥犱负 x鏄潪璐熸湁鐞嗘暟 鎵浠 x 鈮0 鍙堝洜涓 3x锛2y锛媧锛5 鎵浠ュ綋y = 0 , z = 0鏃 x鏈夋渶澶у间负 xmax = 5/3 鍒檚 = 2x+y-z = 2x+(y-z) = 2x+(2-x) = 2+x 鈮2+0 = 2 s = 2+x 鈮 2+5/3 = 11/3 缁间笂锛 s鐨勬渶澶...
绛旓細1宸茬煡x骞虫柟-5x+1=0,姹倄骞虫柟+x骞虫柟鍒嗕箣1鐨勫 姹倄4娆℃柟+x4娆℃柟鍒嗕箣1鐨勫 x^2-5x+1=0 鍥犱负x=0涓嶆槸瀹冪殑瑙ｏ紝鎵浠ョ瓑寮2杈归兘闄や互x,寰 x-5+1/x=0 x+1/x=5 x^2+(1/x^2)=(x+1/x)^2-2 =5^2-2 =23 x^4+1/x^4=(x^2+1/x^2)^2-2=23^2-2=527 2宸茬煡abc涓轰笁瑙掑舰...
绛旓細涓閬鏁板棰樻眰瑙锛岃姝ラ 锛坅鐨2娆℃柟脳b鐨3娆℃柟锛夌殑m娆℃柟 =a鐨2m娆℃柟脳b鐨3m娆℃柟 =(a鐨刴娆℃柟)²脳(b鐨刴娆℃柟)³ =5²脳2³ =200 鎬ワ紒绾夸笂绛夛紒涓閬撴暟瀛﹂锛屾眰姝ｇ‘瑙ｇ瓟锛佽鏈夋楠ゅ晩锛 瑙ｏ細鈭典簩娆″嚱寮弝=f锛坸锛夌殑鏈澶у肩瓑浜13锛屼笖f锛3锛=f锛-1锛=5锛...
绛旓細锛3锛夐鍏堟眰鍑簒鐨勫彇鍊艰寖鍥达紝鐒跺悗鎶妛=-10x2+1300x-30000杞寲鎴恲=-10锛坸-65锛2+12250锛岀粨鍚坸鐨勫彇鍊艰寖鍥达紝姹傚嚭鏈澶у埄娑︼紟璇曢瑙ｆ瀽锛氾紙1锛夐攢鍞崟浠凤紙鍏冿級x 閿鍞噺y锛堜欢锛1000-10x 閿鍞帺鍏疯幏寰楀埄娑锛堝厓锛-10x2+1300x-30000 锛2锛-10x2+1300x-30000=10000 瑙ｄ箣寰楋細x1=50锛寈2=80 绛旓細...
绛旓細淇婄嫾鐚庤嫳鍥㈤槦涓烘偍瑙ｇ瓟锛氳澶ц溅X鍏冿紝灏忚溅Y鍏冿紝鍒 X+2Y=1000 2X+Y=1100 瑙寰楋細X=400锛孻=300 鈶(234+6)梅45=5.33锛岃嚦灏戣鐢6杈嗚溅銆傝屾暀甯堝彧鏈6鍚嶏紝姣忚締杞﹀繀椤绘湁涓浣嶆暀甯堬紝鎵浠ヨ溅杈嗗氨鏄6杈嗐傚厛鑰冭檻绗溅閰1淇濇暀甯堛傚垯 44X+29(6-X)鈮234 400X+300(6-X)鈮2300 瑙ｅ緱锛4鈮鈮5,鈭碭...
绛旓細瑙ｏ細鈭燘O1C =180掳-(鈭燨1BC+鈭燨1CB)=180掳-(2/3鈭燗BC+2/3鈭燗CB)=180掳-2/3(鈭燗BC+鈭燗CB)=180掳-2/3(180掳-鈭燗)=180掳-2/3*120掳 =100掳 鈭燘O2C =180掳-(鈭燨2BC+鈭燨2CB)=180掳-(1/3鈭燗BC+1/3鈭燗CB)=180掳-1/3(鈭燗BC+鈭燗CB)=180掳-1/3(180掳-鈭燗)=180掳-1...
绛旓細瑙ｏ細鍥犱负鍥涜竟褰BCD鏄鏂瑰舰 鎵浠涓夎褰DC=1/2S姝ｆ柟褰BCD AB=DC AB骞宠DC 鎵浠ヨFAE=瑙扚CD 瑙扚EA=瑙扚DC 鎵浠ヤ笁瑙掑舰AEF鍜屼笁瑙掑舰CDF鐩镐技锛圓A)鎵浠E/DC=AF/FC 鍥犱负AE=2BE AE+BE=AB 鎵浠E=2/3AB 鎵浠E/DC=2/3 鎵浠F/FC=2/3 鍥犱负AF+FC=AC 鎵浠C/AC=3/5 鍥犱负S涓夎褰DF/S...
绛旓細绗竴棰 1+2+3+4+鈥︹+n =200 5003锛屾垜浠兘鐭ラ亾锛1+2+3+4+鈥︹+100 =101X100/2 =5050锛岃繖鏍凤紝200 5003= n(n+1)/2 401 0006= n(n+1)= n" + n 鎴戜滑鍏堢湅鐪 n" 锛401 0006鏄竴涓7浣嶆暟锛1000鈥 =100 0000锛岃繖鏍峰氨鏄 2000鈥 =400 0000锛屾帴涓嬫潵鐪嬬湅 n(n+1) 锛屼釜浣嶆暟鏄6锛...
绛旓細瑙锛(1)姣忓皬鏃堕『娴佽椹剁殑璺濈锛岀瓑浜庤埞琛岃窛绂诲姞涓婇『姘存紓娴佺殑璺濈锛氶嗘祦琛岄┒鐨勮窛绂伙紝绛変簬鑸硅璺濈鍑忓幓鐢变簬姘寸殑杩庨潰鍐插嚮鑰岄嗗悜婕傛祦鐨勮窛绂伙紟1/6-1/x=1/8锛1/x 瑙ｄ箣锛屽緱x锛48锛庣粡妫楠寈=48绗﹀悎棰樻剰锛庢晠灏忚埞鎸夋按娴侀熷害鐢盇娓紓娴佸埌B娓渶瑕48灏忔椂锛(2)璁炬晳鐢熷湀鏄湪y鐐归挓钀戒笅姘翠腑鐨勶紝鐢(1)灏忛缁撴灉...
