c语言从键盘输入一字符串 C语言编程：从键盘中输入一个英文字符串

C\u8bed\u8a00\u7f16\u7a0b \u7531\u952e\u76d8\u4efb\u610f\u8f93\u5165\u4e00\u4e2a\u5b57\u7b26\u4e32\u548c\u4efb\u4e00\u4e2a\u5b57\u7b26\uff0c\u8981\u6c42\u4ece\u8be5\u5b57\u7b26\u4e32\u4e2d\u5220\u9664\u6240\u6307\u5b9a\u7684\u5b57\u7b26

#include

int main(void)
{
int i, j = 0;
char ch;
char str[100];

printf("\u8bf7\u8f93\u5165\u5b57\u7b26\u4e32:\n");
scanf("%s", str);

printf("\u8bf7\u8f93\u5165\u4e00\u4e2a\u5b57\u7b26:\n");
scanf(" %c", &ch);

for (i=0; str[i]!='\0'; i++)
{
if (str[i] != ch)
{
str[j++] = str[i];
}
}
str[j] = '\0';

printf("%s\n", str);

return 0;
}

#include
#include

int main()
{
int strSize = 100;
char *str = (char *)malloc(sizeof(char) * strSize);
int charNum = 0;
char input;
//\u9010\u4e2a\u5b57\u7b26\u8f93\u5165\u5b57\u7b26\u4e32\uff0c\u53ef\u4ee5\u8f93\u5165int\u53ef\u4ee5\u8868\u793a\u7684\u6700\u5927\u503c\u4e2a\u5b57\u7b26
printf("\u8bf7\u8f93\u5165\u4efb\u610f\u4e2a\u5b57\u7b26:\n");
while(true)
{
scanf("%c",&input);
if(input != '#')
{
if((input >= 'A' && input = 'a' && input <= 'z'))
{
if(charNum > strSize)
{
strSize += 100;
str = (char *)realloc(str,strSize);
}
str[charNum] = input;
charNum++;
}
}
else
{
break;
}
}
//\u8f93\u5165\u7ed3\u679c\u5206\u6790
int i = 0,j = 0;
char *tempChar = (char *)malloc(sizeof(char) * charNum);
int *tempCharNum = (int *)malloc(sizeof(int) * charNum);
int charType = 0;
bool exist = false;
for(i = 0; i < charNum; i++)
{
exist = false;
tempChar[i] = '#';
tempCharNum[i] = 0;
for(j = 0; j < charNum; j++)
{
if(tempChar[j] == '#')
{
break;
}
if(tempChar[j] == str[i])
{
exist = true;
tempCharNum[j] += 1;
}
}
if(exist == false)
{
tempChar[charType] = str[i];
tempCharNum[charType] = 1;
charType++;
}
}
int t1;
char t2;
for(j = 0; j < charType - 1; j++)
{
for(i = 0; i < charType; i++)

if(tempCharNum[i] > tempCharNum[i+1])//\u5982\u679ca[i]\u5927\u4e8ea[i+1]
{
//\u4ea4\u6362a[i]\u548ca[i+1]\u7684\u503c\uff0c\u5373\u628a\u8f83\u5927\u7684\u5143\u7d20\u5f80\u540e\u6392
t1 = tempCharNum[i];
tempCharNum[i] = tempCharNum[i+1];
tempCharNum[i+1] = t1;

t2 = tempChar[i];
tempChar[i] = tempChar[i+1];
tempChar[i+1] = t2;
}
}
for(i = 0; i < charNum; i++)
{
if(tempChar[i] != '#')
{
printf("\u5355\u8bcd:%c,\u6b21\u6570:%d\n",tempChar[i],tempCharNum[i]);
}
}
free(str);
free(tempChar);
free(tempCharNum);
return 0;
}

#include <stdio.h>
int main()
{
char str[100];
long long an[100];
int cnt=0,i=0,f=0;
printf("Please input a string:");
gets(str);
while(str[i])
{
if(str[i]>='0'&&str[i]<='9')
{
if(f==1)
{
an[cnt]=an[cnt]*10+str[i]-'0';
}
if(f==0)
{
cnt++;
f=1;
an[cnt]=str[i]-'0';
}
}
else
{
f=0;
}
i++;
}
if(cnt==0)
{
printf("None\n");
}
else
{
printf("Total number: %d\n",cnt);
for(i=1;i<=cnt;i++)
{
printf("%lld*2=%lld\n",an[i],an[i]*2);
}
}
return 0;
}

#include "stdio.h"

void main()
{
char str[81];
long num[40];
long n;
int cnt=0;
int i;
gets(str);
for(i=0;str[i];i++)
{
n=0;
if(str[i]>='0' && str[i]<='9')
{
while(str[i] && str[i]>='0' && str[i]<='9')
{
n=n*10+str[i]-'0';
i++;
}
num[cnt++]=n*2;
}
}
if(cnt)
{
printf("%d个数\n",cnt);
for(i=0;i<cnt;i++)
printf("%ld ",num[i]);
}
else
printf("None.\n");
}

#include<stdio.h>

void print_num(char *str)
{
char string[20][20];
int i=0,num=0,new_num=0,counter=0;
while(*(str+i))//即*(str+i)!='\0'
{
if(*(str+i)>='0'&&*(str+i)<='9'&&new_num==0)
{
string[num][counter]=*(str+i);
counter++;
new_num=1;
}
else if(*(str+i)>='0'&&*(str+i)<='9'&&new_num==1)
{
string[num][counter]=*(str+i);
counter++;
}
else if((*(str+i)<'0'||*(str+i)>'9')&&new_num==1)
{
string[num][counter]='\0';
new_num=0;
num++;
counter=0;
}
else if((*(str+i)<'0'||*(str+i)>'9')&&new_num==0);
i++;
}
string[num][counter]='\0';
num=num+1;
printf("there are %d num.\nthere are:\n",num);
for(i=0;i<num;i++)
puts(string[i]);
}

int main()
{
char string[100],*str;
printf("Please enter a string:\n");
gets(string);
str=string;
print_num(str);
return 0;
}
至于每个整数*2，可以作为练习来做，可以好好看一下这个代码，值得思考的

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
void main()
{
char str[80];
int i;
int j = 0;
int nFlag = 0;
int count = 0;
int a[20];
scanf("%s", str);
for (i = 0; i < strlen(str); i++)
{
if (str[i] >= '0' && str[i] <= '9' && nFlag == 0)
{
count++;
a[j] = atoi(str + i);
j++;
nFlag = 1;
}
else
{
nFlag = 0;
}
}
if (count == 0)
{
printf("None\n");
}
printf("%d ", count);
for (i = 0; i < j; i++)
{
printf("%d ", 2 * a[i]);
}
}

/*
12 31 534 77 91
2 × 12 = 24
2 × 31 = 62
2 × 534 = 1068
2 × 77 = 154
2 × 91 = 182
n

n = 5
Press any key to continue
*/
#include <stdio.h>

int main() {
int num,n = 0;
while(scanf("%d",&num) == 1) {
++n;
printf("2 × %d = %d\n",num,2*num);
}
if(n == 0) printf("None.\n");
else printf("\nn = %d\n",n);
return 0;
}

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