用sql语句处理下列问题。求解答!! 用SQL语句完成下列问题。

\u7528sql\u8bed\u53e5\u89e3\u51b3\u4e0b\u5217\u95ee\u9898\uff0c\u6c42\u89e3\u7b54\uff01\uff01\uff01

1\u3001\u5206\u6790\uff1a
\u6700\u540e\u8f93\u51fa\u7684\u7ef4\u5ea6\u5305\u542b\uff1a\u6838\u7b97\u5355\u4f4d\uff08\u91c7\u8d2d\u7c7b\u522b\uff09\u3001\u6708\u4efd\u3001\u4f9b\u5e94\u5546\u3001\u5b9e\u9645\u5165\u5e93\u6570\u91cf\u3001\u5b9e\u9645\u5165\u5e93\u5747\u4ef7\u3001\u5b9e\u9645\u5165\u5e93\u91d1\u989d
2\u3001\u65b9\u6848\uff1a\u6309\u7167\u524d\u4e09\u4e2a\u7ef4\u5ea6\u8fdb\u884cgroup by\u5373\u53ef\u3002
select
\u6838\u7b97\u5355\u4f4d\uff08\u91c7\u8d2d\u7c7b\u522b\uff09,
\u6708\u4efd,
\u4f9b\u5e94\u5546,
sum(\u5b9e\u9645\u5165\u5e93\u6570\u91cf) as \u5b9e\u9645\u5165\u5e93\u6570\u91cf,
sum(\u5b9e\u9645\u5165\u5e93\u91d1\u989d) as \u5b9e\u9645\u5165\u5e93\u91d1\u989d,
sum(\u5b9e\u9645\u5165\u5e93\u91d1\u989d) / sum(\u5b9e\u9645\u5165\u5e93\u6570\u91cf) as \u5b9e\u9645\u5165\u5e93\u5747\u4ef7
from PurchaseAnalys\uff08\u91c7\u8d2d\u8fdb\u8d27\u660e\u7ec6\u8868\uff09
where \u6708\u4efd between '2016-07-01' and '2016-12-31'
GROUP BY \u6838\u7b97\u5355\u4f4d\uff08\u91c7\u8d2d\u7c7b\u522b\uff09,\u6708\u4efd,\u4f9b\u5e94\u5546
ORDER BY \u6708\u4efd,\u6838\u7b97\u5355\u4f4d\uff08\u91c7\u8d2d\u7c7b\u522b\uff09,\u4f9b\u5e94\u5546;

1\u3001\u7b2c\u4e00\u9898\uff0c\u662f\u67e5\u8be2\u603b\u548c\uff0c\u603b\u548c\u5728SQL\u4e2d\u4f7f\u7528sum\uff0c\u5982\uff1aselect sum(\u6210\u7ee9) from \u8868\u540d
2\u3001\u7b2c\u4e8c\u9898\uff0c\u67e5\u8be2\u5e73\u5747\u503c\uff0cSQl\uff1aselect \u5b66\u53f7\uff0cAvg(sum(\u6210\u7ee9)) from \u8868\u540d group by \u5b66\u53f7

3\u3001\u7b2c\u4e09\u9898\uff0c\u67e5\u8be2\u6bcf\u8bfe\u7a0b\u5b66\u751f\u4eba\u6570\uff0cSQL : select \u8bfe\u7a0b\u540d\u79f0,count(\u5b66\u53f7) from \u8868\u540d group by \u8bfe\u7a0b\u540d\u79f0
4\u3001\u7b2c\u56db\u9898\uff0c\u67e5\u8be2\u6700\u9ad8\u5206\uff0c\u4e5f\u5c31\u662f\u6700\u5927\u503c,select max(\u6210\u7ee9),\u5b66\u53f7 from \u8868\u540d group by \u5b66\u53f7
5\u3001\u7b2c\u4e94\u9898\uff0c\u67e5\u8be2\u6bcf\u79d1\u7684\u6700\u9ad8\u5206\uff0cSQL:select max(\u6210\u7ee9),\u8bfe\u7a0b from \u8868\u540d group by \u8bfe\u7a0b \u6700\u4f4e\u5206 select min(\u6210\u7ee9),\u8bfe\u7a0b from \u8868\u540d group by \u8bfe\u7a0b \u5e73\u5747\u5206 select Avg(sum(\u6210\u7ee9)),\u8bfe\u7a0b from \u8868\u540d group by \u8bfe\u7a0b
6\u3001\u7b2c\u516d\u9898 \u663e\u793a\u7efc\u5408\u5927\u4e8e250\u5206\u7684\u4fe1\u606f SQL: select \u5b66\u751fID,sum(\u6210\u7ee9) \u603b\u5206 from \u8868\u540d where sum(\u6210\u7ee9)>250 group by \u5b66\u751fID
7\u3001\u7b2c\u4e03\u9898 \u663e\u793a\u5e73\u5747\u5206 SQL:select \u5b66\u751fID,Avg(sum(\u6210\u7ee9)),\u8bfe\u540d from \u8868\u540d where sum(\u6210\u7ee9)>250 group by \u5b66\u751fID,\u8bfe\u540d order by Avg(sum(\u6210\u7ee9)) asc
8\u3001\u7b2c\u516b\u9898 \u67e5\u8be2\u4eba\u6570 SQL:select \u8bfe\u7a0bID,sum(\u5b66\u751fID) from \u8868\u540d where sum(\u5b66\u751fID)>=30 group by \u8bfe\u7a0bID
9\u3001\u7b2c\u4e5d\u9898 \u67e5\u8be2\u6700\u9ad8\u5206 SQL:select max(\u6210\u7ee9),\u8bfe\u7a0b,\u5b66\u751f\u540d\u5b57 from \u8868\u540d where max(\u6210\u7ee9)>=90 group by \u8bfe\u7a0b,\u5b66\u751f\u540d\u5b57
10\u3001\u7b2c\u5341\u9898 \u6210\u7ee9>=60,\u5e73\u5747\u5206>85 SQL:select \u5b66\u751f from \u8868\u540d where avg(sum(\u6210\u7ee9))>85 and min(\u6210\u7ee9)>=60 order by avg(sum(\u6210\u7ee9)) desc

\u597d\u8f9b\u82e6\uff0c\u671b\u91c7\u7eb3

在查询的名称字段里面再添加一个子查询,截取编号的前六位作为条件,用left函数截取,将结果用concat函数与自身的名称拼接即可

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