有一串数,最前面的四个数依次是1、9、9、5,从第五个数起,每个数都是它前面四个数之和的个位数字,问这一 有一串数最前面四个数依次是1、9、8、7、从第5个数起,每一...

\u6709\u4e00\u4e32\u6570\uff0c\u6700\u524d\u9762\u7684\u56db\u4e2a\u6570\u4f9d\u6b21\u662f\u30011\u30019\u30018\u30017\u3001\u4ece\u7b2c\u4e94\u4e2a\u6570\u8d77\uff0c

\u7528\u53cd\u8bc1\u6cd5
\u8bc1\uff1a\u5047\u8bbe\u5b58\u5728\u4f9d\u6b21\u51fa\u73b0\u76841\u30019\u30018\u30018\u8fd9\u56db\u4e2a\u6570
\u5219 8\u2261x+1+9+8(mod10)
8\u2261x+8(mod10)
\u53c80<x<10\uff0cx\u2261x(mod10)
\u2234 8\u2261x+8(mod10)\u4e0d\u6210\u7acb
\u77db\u76fe
\u5047\u8bbe\u4e0d\u6210\u7acb\uff0c\u539f\u540d\u9898\u5f97\u8bc1\u3002

\u5199\u51fa\u8fd9\u6570\u5217\u7684\u524d\u51e0\u9879\uff1a
1\uff0c9\uff0c8\uff0c7\uff0c5\uff0c9\uff0c9\uff0c0\uff0c3\uff0c1\uff0c3\uff0c7\uff0c4\uff0c\u2026
\u628a\u8fd9\u4e32\u6570\u6309\u5947\u3001\u5076\u6570\u6765\u5206\u7c7b\uff0c\u53ef\u5f97\u4e0b\u9762\u6570\u4e32\uff1a
\u5947\uff0c\u5947\uff0c\u5076\uff0c\u5947\uff0c\u5947\uff0c\u5947\uff0c\u5947\uff0c\u5076\uff0c\u5947\uff0c\u5947\uff0c\u5947\uff0c\u5947\uff0c\u5076\uff0c\u2026
\u663e\u7136\u4ece\u7b2c\u56db\u4e2a\u6570\u5f00\u59cb\uff0c\u603b\u662f \u5947\uff0c\u5947\uff0c\u5947\uff0c\u5947\uff0c\u5076\u7684\u60c5\u51b5\u3002
\u56e0\u6b64\u4e4b\u540e\u7684\u6570\u4e32\u4e2d\u7edd\u4e0d\u53ef\u80fd\u51fa\u73b0\u5947\u5947\u5076\u5076\u7684\u60c5\u51b5\uff0c\u56e0\u6b64\u4e5f\u4e0d\u4f1a\u51fa\u73b01\u30019\u30018\u30018\u3002

考察这串数每个数字的奇偶性可知:
1995偶奇奇奇奇偶奇奇奇奇…
也就是从第5个数起,依次是偶奇奇奇奇循环,而1986是奇奇偶偶,故不可能依次出现1986

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