金属氧化物和酸反应的化学方程式 酸与金属及氧化物反应的化学方程式及现象
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Fe3O4+8HCl==2FeCl3+FeCl2+4H2O
ZnO+2HCl==ZnCl2+H2O
Fe2O3+6HCl==2FeCl3+3H2O
FeO+2HCl==FeCl2+H2O
CuO+2HCl==CuCl2+H2O
MgO+2HCl==MgCl2+H2O
Al2O3+6HCl==2AlCl3+3H2O
CaO+2HCl==CaCl2+H2O
Na2O+2HCl==2NaCl+H2O
ZnO+H2SO4==ZnSO4+H2O
Fe2O3+3H2SO4==Fe2(SO4)3+3H2O
FeO+H2SO4==FeSO4+H2O
CuO+H2SO4==CuSO4+H2O
MgO+H2SO4==MgSO4+H2O
Al2O3+3H2SO4==Al2(SO4)3+3H2O
CaO+H2SO4==CaSO4+H2O
Na2O+H2SO4==Na2SO4+H2O
ZnO+2HNO3==Zn(NO3)2+H2O
Fe2O3+6HNH3==2Fe(NO3)3+3H2O
FeO+2HNO3==Fe(NO3)2+H2O
CuO+2HNO3==Cu(NO3)2+H2O
MgO+2HNO3==Mg(NO3)2+H2O
Al2O3+6HNO3==2Al(NO3)3+3H2O
CaO+2HNO3==Ca(NO3)2+H2O
Na2O+2HNO3==2NaNO3+H2O
「化学实验」酸与金属氧化物反应
MeO + HCl = MeCl + H2O
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绛旓細閰稿拰閲戝睘姘у寲鐗鍙嶅簲浼氱敓鎴愮洂鍜屾按锛岃繖灞炰簬澶嶅垎瑙ｅ弽搴斻傚鍒嗚В鍙嶅簲鎸囩殑鏄袱绉嶅寲鍚堢墿浜掔浉浜ゆ崲鎴愬垎锛岀敓鎴愬彟澶栦袱绉嶅寲鍚鐗╃殑鍙嶅簲銆傛瘮濡傦紝绋鐩愰吀鍜屾哀鍖栭摐鐨勫彂鐢鍙嶅簲鐨勫寲瀛︽柟绋嬪紡涓猴細CuO+2HCl=CuCl2+H2O銆傞噾灞炴哀鍖栫墿鏄粈涔堥噾灞炴哀鍖栫墿鏄閲戝睘鍖栧鍏冪礌涓庢哀鍏冪礌缁勬垚鐨勪簩鍏冨寲鍚堢墿锛屽姘у寲閾併佹哀鍖栭挔绛夛紝閲戝睘姘у寲鐗╁湪鏃ュ父...
绛旓細CuO+2HCl=CuCl2+H2O CuO+H2SO4=CuSO4+H2O Fe2O3+3H2SO4=Fe2(SO4)3+3H2O Al2O3+3H2SO4=Al2(SO4)3+3H2O Al2O3+3HCl=AlCl3+3H2O MgO+2HCl=MgCl2+2H2O MgO+H2SO4+MgSO4+2H20 甯哥敤鐨勫氨杩欎箞鍑犱釜锛屽儚浠涔圢aO鍔閰锛堝垵涓ぇ閮ㄥ垎鏄憾娑诧級浼氬厛涓嶩2O鍙嶆槧鐢熸垚鐩稿簲鐨勭⒈锛屽氨鏄腑鍜鍙嶅簲浜 ...
绛旓細闅炬憾浜庢按鐨勯噾灞炴哀鍖栫墿涓庢煇浜涢吀鍙嶅簲鏄吀纰卞弽搴斻傚綋闅炬憾浜庢按鐨閲戝睘姘у寲鐗╀笌閰稿弽搴鏃讹紝瀹冧滑浼氬彂鐢熶腑鍜屽弽搴旓紝鐢熸垚鐩稿簲鐨勭洂鍜屾按銆備緥濡傦紝閾(III)姘у寲鐗╋紙Fe2O3锛夊拰鐩愰吀锛圚Cl锛鍙嶅簲鐨勫寲瀛︽柟绋嬪紡濡備笅锛欶e2O3 + 6HCl 2FeCl3 + 3H2O 鍦ㄨ繖涓弽搴斾腑锛岄搧(III)姘у寲鐗╀綔涓虹⒈锛屽畠鐨勬哀鍖栫墿绂诲瓙锛圤2-锛夋帴鍙椾簡...
绛旓細姘у寲閾佷笌鐩愰吀鍙嶅簲鐢熸垚姘寲閾佸拰姘达紝涔熷氨鏄锛閲戝睘姘у寲鐗╀笌閰稿弽搴鐢熸垚鐩愬拰姘达紝鍦ㄨ繖涓繃绋嬩腑鍖栧悎浠蜂笉鏀瑰彉 Fe2O3+6HCl=2FeCl3+3H2O
绛旓細閿屽拰绋鐩愰吀Zn + 2HCl === ZnCl2 + H2鈫 閾佸拰绋鐩愰吀Fe + 2HCl === FeCl2 + H2鈫 闀佸拰绋鐩愰吀Mg+ 2HCl === MgCl2 + H2鈫 閾濆拰绋鐩愰吀2Al + 6HCl == 2AlCl3 + 3H2鈫 閲戝睘姘у寲鐗 +閰 --- 鐩 + 姘 姘у寲閾佸拰绋鐩閰稿弽搴锛欶e2O3 + 6HCl === 2FeCl3 + 3H2O 姘у寲閾佸拰绋纭...
绛旓細Fe+2HCl=FeCl2+H2 鏈夋皵娉′骇鐢燂紝婧舵恫鐢辨棤鑹插彉娴呯豢銆侳e2O3+6HCl=2FeCl3+3H2O 閾侀攬閫愭笎婧惰В锛屾憾娑茬敱鏃犺壊鍙橀粍鑹层侰uO+H2SO4=CuSO4+H2O 榛戣壊绮夋湯閫愭笎婧惰В锛屾憾娑茬敱鏃犺壊鍙樻垚钃濊壊銆
绛旓細閰+閲戝睘姘у寲鐗鈥旂洂+H2O锛屾敞鎰忛噾灞炲厓绱犲墠鍚庡寲鍚堜环涓嶅彉
绛旓細姘у寲閾佸拰绋鐩愰吀鍙戠敓鍙嶅簲鐨勫寲瀛︽柟绋嬪紡涓篎e2O3+6HCl===2FeCl3+3H2O銆傛哀鍖栭搧鍙敤浜庢补婕嗐佹补澧ㄣ佹鑳剁瓑宸ヤ笟涓紝鍙仛鍌寲鍓傦紝鐜荤拑銆佸疂鐭炽閲戝睘鐨勬姏鍏夊墏锛屽彲鐢ㄤ綔鐐奸搧鍘熸枡銆
