高二数学难题!!! 高中数学难题七道求高手！！！！！悬赏很多.。。。。。。跪求解...
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\u94fe\u63a5\uff1ahttps://pan.baidu.com/s/1znmI8mJTas01m1m03zCRfQ
?pwd=1234
\u63d0\u53d6\u7801\uff1a1234
\u7b80\u4ecb\uff1a\u9ad8\u4e2d\u6570\u5b66\u4f18\u8d28\u8d44\u6599\u4e0b\u8f7d\uff0c\u5305\u62ec\uff1a\u8bd5\u9898\u8bd5\u5377\u3001\u8bfe\u4ef6\u3001\u6559\u6750\u3001\u89c6\u9891\u3001\u5404\u5927\u540d\u5e08\u7f51\u6821\u5408\u96c6\u3002
\u4ee4t=-x\uff0c\u4ee3\u5165g(x)=f(x-1)\uff0c\u5f97g(-t)=f(-t-1)\u3002\u56e0\u4e3af(x)\u4e3a\u5076\u51fd\u6570\uff0cg(x)\u4e3a\u5947\u51fd\u6570\uff0c\u6240\u4ee5\u4e0a\u5f0f\u5316\u4e3a-g(t)=f(t+1)\uff0c\u5373g(x)=-f(x+1)\u3002\u6240\u4ee5f(x-1)=-f(x+1)\uff0c\u5373f(x-1)+f(x+1)=0\u3002x=2014\u65f6\uff0cf(2013)+f(2015)=0\u3002
\u56e0\u4e3af(x)\u5076\u51fd\u6570\uff0c\u6240\u4ee5f(x)=f(-x) f(x-1)\u5947\u51fd\u6570\uff0c\u6240\u4ee5f(x-1)= -f(-x-1)= -f[-(x+1)]= -f(x+1)\u4ea6\u5373\uff1af(x)=-f(x+2)=f(x+4)=-f(x+6)=...=(-1)^(n/2)f(x+n)\u51e1\u53d6\u503c\u6bcf\u76f8\u5dee2\uff0c\u51fd\u6570\u503c\u5c31\u53d8\u4e00\u6b21\u7b26\u53f70.5\u52308.5\u76f8\u5dee\u4e864\u4e2a2\uff0c\u6240\u4ee5\u53d84\u6b21\u7b26\u53f7\u6240\u4ee5f(8.5)=f(0.5)=9
\u2235y=f\uff08x\uff09\u7684\u56fe\u8c61\u662f\u7531y=f\uff08x+2\uff09\u7684\u56fe\u8c61\u5411\u53f3\u5e73\u79fb\u4e24\u4e2a\u5355\u4f4d\u800c\u5f97\u5230\u7684\u800cy=f\uff08x+2\uff09\u662f\u5076\u51fd\u6570\uff0c\u5373y=f\uff08x+2\uff09\u7684\u56fe\u8c61\u5173\u4e8ey\u8f74\u5bf9\u79f0\uff0c\u6240\u4ee5y=f\uff08x\uff09\u7684\u56fe\u8c61\u5173\u4e8ex=2\u5bf9\u79f0\uff0c f\uff084\uff09=f (0)\uff0cf\uff085.5\uff09=f (-1.5)
\u6240\u4ee5f\uff085.5\uff09\u5c0f\u4e8ef\uff08-1\uff09\u5c0f\u4e8ef\uff084\uff09
f(x)\u662f\u8fde\u7eed\u7684\u5076\u51fd\u6570\uff0c\u4e14\u5f53x>0\u65f6\uff0cf(x)\u662f\u5355\u8c03\u51fd\u6570\u6240\u4ee5\u5f53x<0,f(x)\u4e5f\u662f\u5355\u8c03\u51fd\u6570\uff0c\u5373Y\u8f74\u5de6\u53f3\u4e24\u8fb9\u76f8\u7b49\u7684\u503c\u662f\u552f\u4e00\u4f8b\u5982f(a)=a,\u90a3\u53ea\u6709f(-a)=f(a)=a\u8981\u4f7f\u5f97f(x)=f((x+3)/(x+4))\u53c8f(x)=f(-x)\u6240\u4ee5\u53ef\u5f97\u4e24\u4e2a\u65b9\u7a0bx=(x+3)/(x+4)\uff0c\u5373x^2+3x-3=0-x=(x+3)/(x+4),\u5373x^2+5x+3=0\u7531\u97e6\u8fbe\u5b9a\u7406\u5f97 \u6240\u6709x\u7684\u548c\u4e3a\uff08-3\uff09+\uff08-5\uff09=-8
\u4ee4F\uff08x\uff09=f\uff08x\uff09+x\u2235F\uff08x\uff09=f\uff08x\uff09+x\u4e3a\u5947\u51fd\u6570\u2234-F\uff08x\uff09=F\uff08-x\uff09\uff0c\u5373-f\uff08x\uff09-x=f\uff08-x\uff09-x\uff0c\u5f97f\uff08-x\uff09=-f\uff08x\uff09\uff0c\u5219f\uff08x\uff09\u4e3a\u5947\u51fd\u6570\u2234f\uff08-1\uff09=-f\uff081\uff09=-1g\uff08-1\uff09=f\uff08-1\uff09+2=-1+2=1
g\uff08x\uff09\u4e3aR\u4e0a\u5468\u671f\u4e3a1\u7684\u51fd\u6570\uff0c\u5219g\uff08x\uff09=g\uff08x+1\uff09\u51fd\u6570f\uff08x\uff09=x+g\uff08x\uff09\u5728\u533a\u95f4[0\uff0c1]\u3010\u6b63\u597d\u662f\u4e00\u4e2a\u5468\u671f\u533a\u95f4\u957f\u5ea6\u3011\u7684\u503c\u57df\u662f[-2\uff0c5]\u2026\uff081\uff09\u4ee4x+1=t\uff0c\u5f53x\u2208[0\uff0c1]\u65f6\uff0ct=x+1\u2208[1\uff0c2]\u6b64\u65f6\uff0cf\uff08t\uff09=t+g\uff08t\uff09=\uff08x+1\uff09+g\uff08x+1\uff09=\uff08x+1\uff09+g\uff08x\uff09 =[x+g\uff08x\uff09]+1 \u6240\u4ee5\uff0c\u5728t\u2208[1\uff0c2]\u65f6\uff0cf\uff08t\uff09\u2208[-1\uff0c6]\u2026\uff082\uff09\u540c\u7406\uff0c\u4ee4x+2=t\uff0c\u5728\u5f53x\u2208[0\uff0c1]\u65f6\uff0ct=x+2\u2208[2\uff0c3]\u6b64\u65f6\uff0cf\uff08t\uff09=t+g\uff08t\uff09=\uff08x+2\uff09+g\uff08x+2\uff09=\uff08x+2\uff09+g\uff08x\uff09 =[x+g\uff08x\uff09]+2\u6240\u4ee5\uff0c\u5f53t\u2208[2\uff0c3]\u65f6\uff0cf\uff08t\uff09\u2208[0\uff0c7]\u2026\uff083\uff09\u7531\u5df2\u77e5\u6761\u4ef6\u53ca\uff081\uff09\uff082\uff09\uff083\uff09\u5f97\u5230\uff0cf\uff08x\uff09\u5728\u533a\u95f4[0\uff0c3]\u4e0a\u7684\u503c\u57df\u4e3a[-2\uff0c7]\u6545\u7b54\u6848\u4e3a\uff1a[-2\uff0c7]\uff0e
\u7531f(x+2)=f(x)\uff0c\u77e5f(-1/2)=f(3/2)\u4ece\u800c\u7531\u3000f(1/2)=f(3/2)\u5f97f(-1/2)=f(1/2)\u6240\u4ee5\u3000-a/2 +1=(b/2 +2)/(3/2)\u6574\u7406\uff0c\u5f973a+2b=-2\u53c8f(-1)=f(1)\uff0c\u5373\u30001-a=(b+2)/2\uff0c\u6574\u7406\uff0c\u5f972a+b=0\u4ece\u800c\u3000a=2\uff0cb=-4a+3b=-10
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见图
错误如下图：sin2B和 sinB是有差别的，不能简单约除。
是sin2B/sinB=根号3
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绛旓細锛1锛夌敱鍙屾洸绾挎柟绋嬬煡a=3,b=2 鏍规嵁浠庡渾澶栦竴鐐瑰紩鍦嗙殑涓ゆ潯鍒囩嚎闀跨浉绛夊強鍙屾洸绾垮畾涔夊彲寰 |PF1|-|PF2|=2a.鐢变簬|NF1|-|NF2|=|PF1|-|PF2|=2a. 鈶 |NF1|+|NF2|=2c. 鈶 鐢扁憼鈶″緱|NF1|==a+c.鈭磡ON|=|NF1|-|OF1|=a+c-c=a=3.鏁呭垏鐐筃鐨勫潗鏍囦负锛3锛0锛.鏍规嵁瀵圭О鎬э紝褰揚...
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绛旓細1.璁綧锛坸锛寉锛夊彸鐒︾偣F锛4锛0锛夆垰[锛坸-4锛塣+y^2]=6-x 鍖栫畝锛屽緱y^2=20锛坸+1锛夊嵆涓烘墍姹傜偣M鐨勮建杩规柟绋嬨2.鍙屾洸绾縳2/5-y2/3=1娓愯繎绾挎柟绋嬫槸y=姝ｈ礋(b/a)x=(鈭3/鈭5)x 鍗砨/a=鈭3/鈭5 b^2/a^2=3/5 c^2=a^2+b^2=64 瑙ｅ緱a^2=40,b^2=24 鎵浠ュ弻鏇茬嚎鏂圭▼鏄痻^2...
绛旓細f(x)=ax^4+bx^3+cx^2+dx+e f(-x)=a(-x)^4+b(-x)^3+c(-x)²+d(-x)+e 鍥犱负鏄伓鍑芥暟,鎵浠(x)=f(-x)鏄撳緱鍒,b=0,d=0 f(x)=ax^4+cx²+e 鍥犱负杩囩偣(0,1),鎵浠(0)=0+0+e=1,e=1 鍦▁=1,y=x-2=1-2=-1 璇ュ鐨勫垏鐐瑰潗鏍囦负(1,-1),鎵浠 f(...
绛旓細1.鎹㈠厓娉曪紝璁総=x^2,鍐嶉厤鏂瑰嵆鍙 2.鐪嬪浘锛寈=a,b鏃讹紝f'(x)=0,鍗砯(x)鍥惧儚鍒囩嚎鏂滅巼涓0锛屽彧鏈夌4涓弧瓒 3.璁炬洸绾夸笂涓鐐(a,e^a)鍒扮洿绾胯窛绂绘渶鐭紝璺濈涓篸=|a-e^a-3|/鈭2 娉細鈭氫唬琛ㄦ牴鍙凤紝鍐呯殑鍗充负鏍瑰彿涓嬬殑鏁 褰揹鏈灏忔椂锛屽嵆|a-e^a-3|鏈灏忥紝璁緎=x-e^x-3,鍒檚'=1-e^x锛...
绛旓細绗1棰樹技涔庣己涓涓潯浠讹紝鏃犳硶鐩存帴瑙ｅ嚭锛涚2棰橈細鐢憋紙X+Y+Z)/3鈮ワ紙xyz)^(1/3)寰楋紝X+Y+Z鈮3(xyz)^(1/3)=3*100^(1/3)鍗炽x=y=z鏃讹紝X+Y+Z鍙栨渶灏忓3*100^(1/3)锛屾棤鏈澶у硷紱绗3棰橈細鐢辨寮﹀畾鐞嗗拰浣欏鸡瀹氱悊寰椼c=(a+b)/[(b^2+c^2-a^2)/(2bc)+(a^2+c^2-b^2)/(...
绛旓細鏍规嵁鎶涚墿绾跨殑鎬ц川锛屾姏鐗╃嚎涓婄殑鐐瑰埌鍑嗙嚎鐨勮窛绂讳笌鍒扮劍鐐圭殑璺濈鐩哥瓑锛屾墍浠ヨA锛孊鍒板噯绾跨殑鎽勫奖鐐逛负A鈥橈紝B鈥 锛屾墍浠F=AA鈥橈紝BF=BB鈥欙紝 M涓篈B涓偣锛屾墍浠M鈥=1/2锛圓A鈥+BB鈥橈級锛屾墍浠ュ皢闂杞寲涓轰竴涓湁鐫60搴﹁鐨勪笁瑙掑舰锛60搴﹁鐩搁偦鐨勪袱杈逛箣鍜屼笌60搴﹁瀵硅竟鐨勬瘮鍊奸棶棰橈紝鏍规嵁浣欏鸡瀹氱悊锛孉B^2=AF^2...
绛旓細19锛氳BM=x锛孉N=y锛屛擜BM锛岀敤浣欏鸡瀹氱悊锛欰M²=1+x²-2脳1脳xcosABC =1+x²-2x脳1/2 =x²-x+1 |AM|=鈭氾紙x²-x+1锛堿M.AN=|AM||AN|cos30掳 =y鈭氾紙x²-x+1锛夆垰3/2=3 y=2鈭3/鈭氾紙x²-x+1锛夛紙1锛墆=4 浠ｅ叆锛4=2鈭3/鈭氾紙x&#...
绛旓細x+4c²-1>0鎭掓垚绔 鍙渶螖=(1-4c)²-4(4c²-1)<0 瑙ｅ緱c>5/8 p鎴杚鏄湡锛宲涓攓鏄亣锛屽嵆p鍜宷涓鐪熶竴鍋 (1)p鐪焣鍋囷紝1/2<c<1涓攃鈮5/8 寰1/2<c鈮5/8 (2)p鍋噏鐪燂紝(c>1鎴0<c鈮1/2)涓攃>5/8 寰梒>1 缁间笂c鐨勮寖鍥存槸1/2<c鈮5/8鎴朿>1 ...
