写一C程序实现:一班级有30名学生要求按他们姓名的顺序排列(按汉语拼音的字母顺序从小到大),并按序输出 编写一程序,一班级有n名学生要求按他们姓名的顺序排列(按汉语...

\u5199\u4e00C\u7a0b\u5e8f\uff1a\u4e00\u73ed\u7ea7\u670930\u540d\u5b66\u751f\u8981\u6c42\u6309\u4ed6\u4eec\u59d3\u540d\u7684\u987a\u5e8f\u6392\u5217\uff08\u6309\u6c49\u8bed\u62fc\u97f3\u7684\u5b57\u6bcd\u987a\u5e8f\u4ece\u5c0f\u5230\u5927\uff09\uff0c\u5e76\u6309\u5e8f\u8f93\u51fa\uff0c

\u4e0a\u9762\u7684\u7a0b\u5e8f\u524d\u534a\u90e8\u5206\u5728\u63a5\u6536\u7528\u6237\u8f93\u5165\uff0c\u5c31\u662f\u628a30\u4e2a\u5b66\u751f\u7684\u4fe1\u606f\u8f93\u8fdb\u6765\u2026\u4e2d\u95f4\u5927\u6982\u5728\u6392\u5e8f\u2026\u6700\u540e\u8f93\u51fa\u2026\u6700\u540e\u9762\u662f\u4e00\u4e2a\u5c06\u6240\u6709\u5b57\u6bcd\u90fd\u8f6c\u6362\u4e3a\u5927\u5199\u5b57\u6bcd\u7684\u51fd\u6570\u2026

#include
#include
#define N 5
void main(void)
{
char a[N][10],c[10];
int i,j;
printf("\u8f93\u5165%d\u4e2a\u5b66\u751f\u7684\u59d3\u540d\u62fc\u97f3\uff1a\n",N);
for(i=0;i<N;i++)
scanf("%s",a+i);
printf("\u6392\u5217\u540e\u7684\u59d3\u540d:\n");
for(i=0;i<N-1;i++)
for(j=i+1;j<N;j++)
{
if(strcmp(a[i],a[j])>0)
{
strcpy(c,a[j]);
strcpy(a[j],a[i]);
strcpy(a[i],c);
}
}
for(i=0;i<N;i++)
printf("%s\n",a+i);
}
\u6211\u5b9a\u4e49\u7684\u59d3\u540d\u62fc\u97f3\u6700\u957f\u4e3a10\uff0c\u5b66\u751f\u4e2a\u6570N\uff0c\u4f60\u53ef\u4ee5\u5728#define N 5\u8bed\u53e5\u91cc\u9762\u6539\uff0c\u53ea\u652f\u6301\u62fc\u97f3\u59d3\u540d\uff0c\u4f60\u770b\u770b\u80fd\u4e0d\u80fd\u5b8c\u6210\u4f60\u8981\u7684\u529f\u80fd\uff01

阿诺- -,2B哈哈。
#include “stdio.h”
void strup(char str[])
main()
{ char str[20];
char name[20][20];
int i,j,t,n=30;
printf(“Please input name number of sorting\n”);
scanf(“%d”,&n);
printf(“Please input name\n”);
for(i=0;i<n;i++)
{ gets(name[i]);
strup(name[i]);
}
for(i=0;i<n;i++)
{for(j=i+1;j<n;j++)
{ for(k=0;;k++)
if(name[i][k]<name[j][k])
break;
else if(name[i][k]>name[j][k])
{strcpy(str,name[j]);
srycpy(name[j],name[i]);
strcpy(name[i],str);
break;;
}
}
}
for(i=0;i<n;i++)
printf(“%s”,name[i]);
}
void strup(char str[])
{ int i;
for(i=0;str[i]!=’\o’;i++)
if(str[i]>=’a’&&str[i]<=’z’)
str[i]=str[i]+’A’-‘a’;
}



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