甲烷和氧气的混合气体在标准状况下的密度为1.25克/升，求混合气体中甲烷的体积分数？ 在标准状况下，氧气的密度是1.43克/升，氮气的密度为1.2...
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\uff081\uff09\u5df2\u77e5\u7a7a\u6c14\u4e2d\u6c27\u6c14\u7684\u4f53\u79ef\u7ea6\u5360\u7a7a\u6c14\u603b\u4f53\u79ef\u7684\u4e94\u5206\u4e4b\u4e00\uff0c\u6c27\u6c14\u7ea6\u5360\u7a7a\u6c14\u8d28\u91cf\u7684\u767e\u5206\u6bd4\u662f1\u00d71.43g/L5\u00d71.29g/L\u00d7100%=22%\uff082\uff09100L\u7a7a\u6c14\u4e2d\uff0c\u6c2e\u6c14\u7684\u4f53\u79ef\u4e3a100L\u00d745=80L\uff0c\u6c2e\u6c14\u7684\u8d28\u91cf\u4e3a80L\u00d71.25g/L=100g\u6545\u7b54\u6848\u4e3a\uff1a\uff081\uff0922%\uff082\uff09100g
混合气体在标准状况下的密度为1.25克/升，则平均摩尔质量M=ρ·Vm=1.25×22.4=28g/mol用十字交叉法即得二者的物质的量之比，也就是体积之比为1：3，
甲烷的体积分数为1/1+3×100%=25%
1mol混合气体的质量m=1.25*22.4=28g
设甲烷x:
16x+32(1-x)=28
16x+32-32x=28
16x=4
x=1/4=25%
绛旓細瑙ｆ瀽锛娣峰悎姘斾綋骞冲潎寮忛噺M= Vm*d= 22.4* 1.00= 22.4 M= M1*1% +M2*2* = 32[V1/锛圴1+V2锛塢 + 16* [V2/锛圴1+V2锛塢 = 22.4 瑙ｅ緱锛歏1/V2=3/2 鎵浠ヤ釜鏁版瘮锛屼篃鏄3锛2
绛旓細22.4g 1mol 32 6.4 2 22.4 16 9.6 3 閲忎箣姣 姘ф皵:鐢茬兎=2:3 绗簩绉嶆柟娉曪細棣栧厛鎴戜滑蹇呴』姹傚嚭娣峰悎姘斾綋涓紝姘ф皵鍜岀敳鐑鎵鍗犵殑姣斾緥銆傚啀鏍规嵁闃夸紡浼藉痉缃楀畾寰嬬煡閬撲綋绉箣姣斻傛爣鍐垫椂锛1mol姘斾綋22.4L锛屾墍浠ュ彲浠ユ眰寰楁皵浣撶殑瀵嗗害锛姘ф皵鐨瀵嗗害=32g/22.4L,鐢茬兎鐨勫瘑搴=16g/22.4L.璁炬哀姘...
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