c语言 随机输入一个字符串,统计该串中每个数字字符(0,1,2,3,4,5,6,7, 8,9)出现的次数。 输入一串字符,以“ !”结束,分别统计其中每个数字字符0,1...

c\u8bed\u8a00 \u968f\u673a\u8f93\u5165\u4e00\u4e2a\u5b57\u7b26\u4e32\uff0c\u7edf\u8ba1\u8be5\u4e32\u4e2d\u6bcf\u4e2a\u6570\u5b57\u5b57\u7b26(0\uff0c1\uff0c2\uff0c3\uff0c4\uff0c5\uff0c6\uff0c7\uff0c 8\uff0c9)\u51fa\u73b0\u7684\u6b21\u6570\u3002

\u601d\u8def\uff1a\u7edf\u8ba1\u5b57\u7b26\u4e32\u4e2d\u6bcf\u4e2a\u6570\u5b57\u5b57\u7b26\u51fa\u73b0\u7684\u4e2a\u6570\u53ef\u4ee5\u5148\u5b9a\u4e49\u4e00\u4e2a\u6574\u6570\u6570\u7ec4a\u5927\u5c0f\u662f10\uff0c\u4f9d\u6b21\u4fdd\u5b580-9\u5b57\u7b26\u51fa\u73b0\u4e2a\u6570\uff0c\u904d\u5386\u5b57\u7b26\u4e32\uff0c\u5224\u65ad\u8be5\u5b57\u7b26\u662f\u5426\u662f\u6570\u5b57\u5b57\u7b26\uff0c\u5982\u679c\u662f\u5bf9\u5e94\u7684\u6570\u7ec4\u5143\u7d20\u81ea\u52a01\u3002\u53c2\u8003\u4ee3\u7801\uff1a#include#includeint main(){ char a[100];int i,n,num[10];gets(a);n=strlen(a);for(i=0;i='0'&&a[i]<='9')num[a[i]-'0']++;for(i=0;i<10;i++)printf("%d ",num[i]); return 0;}/*\u8f93\u51fa\uff1aads51df0a3df9d87f89ads4fd0f3adsf21sdf47d89f9adsf65as1d2f3asd2 3 2 3 2 2 1 2 3 4*/

#include
int main(int argc, char* argv[])
{
char ch;
int counter[10];
for (int i=0;i<10;i++)
{
counter[i]=0;
}
while((ch = getchar()) != '!')
{
switch (ch)
{
case '0':
counter[0]++;
break;
case '1':
counter[1]++;
break;
case '2':
counter[2]++;
break;
case '3':
counter[3]++;
break;
case '4':
counter[4]++;
break;
case '5':
counter[5]++;
break;
case '6':
counter[6]++;
break;
case '7':
counter[7]++;
break;
case '8':
counter[8]++;
break;
case '9':
counter[9]++;
break;
default:
break;
}
}
for (i=0;i<10;i++)
{
//cout<<"\u6570\u5b57"<<i<<"\u7684\u4e2a\u6570\u662f:"<<counter[i]<<endl;//\u5982\u679c\u7528C++;
printf("\u6570\u5b57");
printf("%d",i);
printf("\u7684\u4e2a\u6570\u662f:%d\n",counter[i]);
}
return 0;
}

\u6ce8\u91ca\uff1a
VC6.0\u6d4b\u8bd5\u901a\u8fc7\uff1b

#include<stdio.h>
#include<string.h>
void main()
{
char s[100];
int i;
static int num[10];
scanf("%s",s);
for(i=0;i<strlen(s);i++)
if(s[i]>='0'&&s[i]<='9')
num[s[i]-'0']++;
for(i=0;i<=9;i++)
printf("%d出现的次数为:%d\n",i,num[i]);
}

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