用1、2、3三个数字组成六位数，若每个数字用两次，相邻位不允许用相同的数字。有几个这种数？配过程，谢！ 用1.2.3三个数字组成六位数，一共多少种组合？求详细答案！
\u75281\uff0c2\uff0c3\u4e09\u4e2a\u6570\u5b57\u7ec4\u6210\u516d\u4f4d\u6570\uff0c\u82e5\u6bcf\u4e2a\u6570\u5b57\u7528\u4e24\u6b21\uff0c\u76f8\u90bb\u4f4d\u4e0d\u5141\u8bb8\u7528\u76f8\u540c\u7684\u6570\u5b57\uff0e\uff081\uff09\u8bd5\u5199\u51fa\u56db\u4e2a\u7b26\u5408\u4e0a\u8ff0\u6761\uff081\uff09\u4ee51\u5f00\u5934\u7684\u6570\u6709121323 131232 123123 123132 132123 132132 123213 132312 132321 123231 \u7b4910\u4e2a\u6570\uff1b\uff082\uff09121323\uff0c131232\uff0c123123\uff0c123132\uff0c121323\uff0c121332\uff0c132123\uff0c132132\uff0c123213\uff0c132312\uff0c213123\uff0c213132\uff0c312123\uff0c312132\uff0c212313\uff0c213213\uff0c312312\uff0c313212\uff0c213231\uff0c312321\uff0c231213\uff0c231312\uff0c321213\uff0c321312\uff0c231231\uff0c231321\uff0c321231\uff0c321321\uff0c232131\uff0c323121\u5219\u517130\u4e2a\u7b26\u5408\u6761\u4ef6\u7684\u516d\u4f4d\u6570\uff0e
2,1)=6\u4e2a\uff08\u53ea\u9700\u8003\u8651ABA\u8fd9\u4e09\u4f4d\u7684\u6570\u5b57\uff09\uff1b\u4e8c\u3001ABC\u00d7\u00d7\u00d7\uff0c\u8fd9\u6837\u7684\u6570\u6709\uff1aA\u6240\u4ee5\u6bcf\u4e2a\u6570\u5b57\u7528\u4e24\u6b21\uff0c\u76f8\u90bb\u4f4d\u4e0d\u5141\u8bb8\u7528\u76f8\u540c\u7684\u6570\u5b57\uff0c\u4e00\u5171\u67096+24=30\u4e2a\u3002
分两类：一、ABACBC，这样的数有：A(3,1)A(2,1)=6个（只需考虑ABA这三位的数字）；
二、ABC×××，这样的数有：A(3,1)A(2,1)A(2,1)A(2,1)=24个。
所以每个数字用两次，相邻位不允许用相同的数字，一共有6+24=30个。
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