sql 查询一个月中每天最后一条记录,MYSQL,要可行的哦,我想了半天都没写出来,网上找的不靠谱,别复制啊 在mysql中有下面一张表,我想查询有大于一条记录的名字数量...
mysql\u6570\u636e\u5e93\u4e2dsql\u8bed\u53e5\u53d6\u4e00\u6bb5\u65f6\u95f4\u7684\u6bcf\u4e00\u5929\u7684\u6700\u540e\u4e00\u6761\u6570\u636e\uff1fsql\u8bed\u53e5\u600e\u4e48\u5199select aa.datetemp,max(aa.datetime) from (select date_format(datetime,'%Y-%m-%d') datetemp,datetime from \u8868\u540d ) aa group by aa.datetemp \u8fd9\u6837\u5e94\u8be5\u53ef\u4ee5\u83b7\u53d6\u5230\u6bcf\u5929\u6700\u5927\u65f6\u95f4\u7684\u8fd9\u4e00\u6761\u6570\u636e\u4e86\u3002\u5177\u4f53\u5c0f\u90e8\u5206\u4fee\u6539\u4f60\u6839\u636e\u81ea\u5df1\u9700\u6c42
SELECT COUNT(*) FROM (SELECT \u59d3\u540d FROM \u8868\u540d GROUP BY \u59d3\u540d HAVING COUNT(*)>1) A
select convert(varchar(12),时间,111 ) tim,* into #e from 表1declare mycur cursor for select DISTINCT tim from #e
declare @tim varchar(20)
declare @t table (时间 datetime,栏位1char(12))
open mycur
fetch next from mycur into @tim
while @@fetch_status=0
begin
insert into @t
select TOP 1 时间,栏位1from #e
where tim=@tim
ORDER BY 时间desc
fetch next from mycur into @tim
end
close mycur
deallocate mycur
select * from @t
select * from 表 b where exists
(
select 编号,max(日期) from 表 a
where month(a.日期)=查找的月份 and a.编号=b.编号
group by a.编号,convert(varchar(11),a.日期,120)
)
假设天字段为day ,格式为:"2012年03月09日"
select * from table where to_char(day,'yyyymmdd') = (select max(to_char(day,'yyyymmdd')) last_day from table);
select top 1 * from table where date='日期' order by ‘时间’desc
select max(字段) group by 天
天这里可能需要你把时间转成天的数据库日期函数
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