2x平方－5x－3＝0解得过程 解方程2x的平方+5x=-3（要过程）
2x^2-5x+3=0\u7528\u914d\u65b9\u6cd52x^2-5x+3=0
2(x²-5x/2)+3=0
2(x-5/4)²+3-25/8=0
2(x-5/4)²=1/8
(x-5/4)²=1/16
x-5/4=\u00b11/4
x=1\u6216x=3/2
\u5341\u5b57\u76f8\u4e58\u6cd5
2x^2-5x+3=0
(2x-3)(x-1)=0
x=1\u6216x=3/2
\u7528\u914d\u65b9\u6cd5\u89e3\u65b9\u7a0b\uff1a2x\u7684\u5e73\u65b9+5x-3=0
2x²+5x=3
x²+5x/2=3/2
x²+5x/2+25/16=49/16
(x+5/4)²=49/16
x+5/4=7/4 x+5/4=-7/4
x=1/2 x=-3
\uff08x+3)(x+1)=6x+18
\uff08x+3)(x+1)-(6x+18)=0
(x+3)(x+1)-6(x+3)=0
(x+3)(x-5)=0
x=-3 x=5
因式分解
（2x+1）（x-3）=0
解得x=-1/2或x=3
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（2X+1）*（X-3）=0，X=-0.5，3
绛旓細2x²-5x-3=0 寰椼2x+1銆戙恱-3銆=0 x=-1/2鎴3 婊℃剰璇烽噰绾崇瓟妗堚濄
绛旓細2x鐨勫钩鏂-5x-3=0 寰 (x-3)(2x+1)=0 鎵浠 x=3 鎴 x = -1/2
绛旓細2x2 - 5x -3 =0 x2 - 5/2 x = 3/2 x2 - 5/2x + 25/16 = 3/2 + 25/16 (x- 5/4)2 = 49/16 x - 5/4 =姝ｈ礋 7/4 x = 3鎴栬厁=- 1/2
绛旓細2x²-5x-3=0 锕檟-3锕氾箼2x锛1锕=0 鈭磝1=3,x2=-½
绛旓細浣犱綘鏄湪瑙2鍏冧竴娆℃柟绋嬪惂锛屽洜寮忓垎瑙ｆ病鏈夌瓑鍙(^_^)锛2x+1锛(x-3)
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