【化学-选修5：有机化学基础】某有机化合物A的结构简式为：是一种重要的化工原料．A、B、C、D、E之间的转 【化学——选修5：有机化学基础】（15分）已知某有机物A为烃...
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A与新制氢氧化铜发生氧化反应生成B为，B发生还原反应生成C，由C与碳酸钠反应产物的结构可知C为，C在浓硫酸、加热条件下反应生成D，而D发生加聚反应生成E，故C发生消去反应生成D，则D为，E为，（1）由上述分析可知，C的结构简式为：，其中含有的含氧官能团是：羧基、羟基，
故答案为：；羧基、羟基；
（2）反应⑤中有气体二氧化碳生成，反应①属于氧化反应，反应②属于还原反应，反应③属于消去反应，反应④属于加聚反应，反应⑤属于复分解反应，
故答案为：⑤；①；
（3）反应③的化学方程式是：，
故答案为：；
（4）与B（）为同分异构体，且含有甲基、能够发生银镜反应的有机化合物的结构简式为等，
故答案为：等；
（5）D生成E的化学方程式为：，故答案为：．
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绛旓細鈶稤鐨勬懇灏旇川閲廙锛6.25脳16锛100g/mol锛岀敱姝ゅ彲纭畾鍏跺垎瀛愪腑鎵鍚殑鍘熷瓙鏁板垎鍒负N锛圕锛夛紳 锛孨锛圚锛夛紳 锛孨锛圤锛夛紳 锛屽垎瀛愬紡涓篊 5 H 8 O 2 锛屽垎瀛愮殑涓嶉ケ鍜屽害涓2锛岀粨鍚堟祦绋嬪浘鐨勪俊鎭彲纭畾D鐨勭粨鏋勭畝寮忎负CH 2 =C(CH 3 )-COOCH 3 锛屽叾鎵鍚畼鑳藉洟涓虹⒊纰冲弻閿拰閰熀銆傗懜鏍规嵁鍚墤鐑伅...
