c语言程序中怎样用rand函数编写一个从1到33中任选6个不同的数的程序 c语言，使用随机函数rand（）编写一个猜数字的游戏程序
c\u8bed\u8a00\u600e\u4e48\u4f7f\u7528\u968f\u673a\u51fd\u6570rand\u7f16\u5199\u4e00\u4e2a\u731c\u6570\u5b57\u7684\u6e38\u620f\u7a0b\u5e8f?#include
#include
#include
#define N 10
main()
{
int i,a,b;
srand(time(0)); /*\u8bbe\u7f6e\u79cd\u5b50,\u5e76\u751f\u6210\u4f2a\u968f\u673a\u5e8f\u5217*/
while(~scanf("%d",&b))
{
for(i=0;i<N;++i)rand()%10;
a = rand()%100;
while(1)
{
if(a == b){puts(" \u606d\u559c\u4f60 \u731c\u5bf9\u4e86 !\n***************\n");break;}
elseif(a > b)puts("\u4f60\u8f93\u5165\u7684\u6570 \u5c0f\u4e86!");
else puts("\u4f60\u8f93\u5165\u7684\u6570 \u5927\u4e86!");
scanf("%d",&b);
}
}
system("pause");
}
\u6d4b\u8bd5\u6570\u636e\uff1a
\u8bf7\u8f93\u5165\u60a8\u731c\u7684\u90a3\u4e2a\u6570:
10
\u7b2c1\u6b21\u731c\u6d4b\uff0c\u5f88\u9057\u61be\u60a8\u731c\u5c0f\u4e86\uff01
\u8bf7\u8f93\u5165\u60a8\u731c\u7684\u90a3\u4e2a\u6570:
15
\u7b2c2\u6b21\u731c\u6d4b\uff0c\u5f88\u9057\u61be\u60a8\u731c\u5927\u4e86\uff01
\u8bf7\u8f93\u5165\u60a8\u731c\u7684\u90a3\u4e2a\u6570:
12
\u7b2c3\u6b21\u731c\u6d4b\uff0c\u606d\u559c\u60a8\u731c\u5bf9\u4e86,\u7535\u8111\u968f\u673a\u6570\u662f12\uff01
\u4ee3\u7801\uff1a
#include "stdio.h"
#include "conio.h"
#include
#include
#include
main()
{
int randnum,count=0;
int n,isRight;
time_t t;
srand((unsigned)time(&t));
randnum=(int)(rand()%1000);
while(1)
{
printf("\n\u8bf7\u8f93\u5165\u60a8\u731c\u7684\u90a3\u4e2a\u6570:\n");
scanf("%d",&n);
count++;
if(n==randnum)
{
printf("\u7b2c%d\u6b21\u731c\u6d4b\uff0c\u606d\u559c\u60a8\u731c\u5bf9\u4e86,\u7535\u8111\u968f\u673a\u6570\u662f%d\uff01\n",count,randnum);
break;
}
else if(n>=randnum)
{
printf("\u7b2c%d\u6b21\u731c\u6d4b\uff0c\u5f88\u9057\u61be\u60a8\u731c\u5927\u4e86\uff01\n",count);
}
else
{
printf("\u7b2c%d\u6b21\u731c\u6d4b\uff0c\u5f88\u9057\u61be\u60a8\u731c\u5c0f\u4e86\uff01\n",count);
}
}
getch();
}
getch();
}
\u697c\u4e3b\u597d\u8fd0\uff01
首先，了解rand()/33 即是从0-32中任选一个数
则第一个数a = *(p+rand()/33)
然后，从剩下32数中任选一个数b，过程如下：
for(int i = a; i<33;i++){
p+a = p+a+1;
}
令b = *(p+rand()/32)
如此循环到6，自己写吧
先建一个
数组
ay=
{1,……33},
指针*p
=
ay
首先，了解rand()/33
即是从0-32中任选一个数
则第一个数a
=
*(p+rand()/33)
然后，从剩下32
数中
任选一个数b，过程如下：
for(int
i
=
a;
i<33;i++){
p+a
=
p+a+1;
}
令b
=
*(p+rand()/32)
如此循环到6，自己写吧
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