c语言习题，输入一个正整数，按照从高位到低位的顺序输出各位数字。怎么做 C语言 输入一个正整数，按照从高位到低位的顺序输出各位数字
c\u8bed\u8a00\u4e60\u9898\uff0c\u8f93\u5165\u4e00\u4e2a\u6b63\u6574\u6570\uff0c\u6309\u7167\u4ece\u9ad8\u4f4d\u5230\u4f4e\u4f4d\u7684\u987a\u5e8f\u8f93\u51fa\u5404\u4f4d\u6570\u5b57\u3002\u8f9b\u82e6\u6253\u6765\uff0c\u671b\u91c7\u7eb3\uff0c\u8c22\u8c22\uff01
#includeint main(){int a;int flag=0;scanf("%d",&a);if(a/1000000000){printf("%d\t",a/1000000000);flag=1;}if(a%1000000000/100000000 || flag){printf("%d\t",a%1000000000/100000000);flag=1;}if(a%100000000/10000000 || flag){printf("%d\t",a%100000000/10000000);flag=1;}if(a%10000000/1000000 || flag){printf("%d\t",a%10000000/1000000);flag=1;}if(a%1000000/100000 || flag){printf("%d\t",a%1000000/100000);flag=1;}if(a%100000/10000 || flag){printf("%d\t",a%100000/10000);flag=1;}if(a%10000/1000 || flag){printf("%d\t",a%10000/1000);flag=1;}if(a%1000/100 || flag){printf("%d\t",a%1000/100);flag=1;}if(a%100/10 || flag){printf("%d\t",a%100/10);flag=1;}if(a%10 || flag){printf("%d\n",a%10);flag=1;}}\u4e0d\u8981\u8d85\u8fc7int\u7684\u8303\u56f4\u5c31\u884c\u4e86
\u56e0\u4e3a\u8981\u6c42\u4ece\u9ad8\u4f4d\u8f93\u51fa\uff0c\u7b2c\u4e00\u4e2a\u5faa\u73af\u6c42\u51fa\u8f93\u5165\u5f97\u6570\u591a\u5c11\u4f4d\uff0c\u5e76\u7528power\u4fdd\u5b58\u76f8\u5173\u4fe1\u606f\uff08\u5982\uff1a\u8f93\u51651\uff0cpower=1\uff0c\u8f93\u5165123\uff0cpower=100\uff0c\u8f93\u51651234\uff0cpower=10000\uff0c\u8f93\u516512345\uff0cpower=10000\uff09\u3002
\u5faa\u73af\u7ed3\u675f\u540e\u8fd8\u8981\u518d
power=power/10;//\u56e0\u4e3a\u5faa\u73af\u5c06\u8fd9\u4e2a\u6570\u4e3a\u4e00\u4f4d\u6570\u7684\u65f6\u5019\u591a\u6210\u4e8610,\u5373\u8f93\u51651\uff0c\u7b97\u51fapower=10,//\u4f46\u5b9e\u9645power\u5e94\u8be5\u4e3a1\u7b2c\u4e8c\u4e2a\u5faa\u73af\uff0cdigit=number/power;\u83b7\u5f97\u5f53\u524d\u7684\u6700\u9ad8\u4f4d\uff0c\u6700\u9ad8\u4f4d\u83b7\u5f97\u5230\u4e86\uff0c\u63a5\u4e0b\u6765\u5c31\u662f\u6c42\u6b21\u9ad8\u4f4d\uff0c\u6240\u4ee5
number%=power;//\u539f\u6765\u7684\u6570\u53bb\u6389\u6700\u9ad8\u4f4d\u6570\u5b57\u540e\u5f97\u5230\u7684\u6570 power/=10;//\u539f\u6765\u7684\u6570\u51cf\u5c11\u4e00\u4f4d\uff0cpower\u4fdd\u5b58\u7684\u6570\u4e5f\u5e94\u5f53\u7f29\u5c0f10
输入时由代码限制只能是正整数，并赋与int型变量n，否则退出；
用一个for循环计算输入之数的十进制长度，用1之后的0的个数表示并赋与临时变量t，如10000表示输入了一个4位十进制正整数；
用一个while循环先后由t/=10和n/t%10来求得从高位至低位的各位数字并输出。
代码如下：
#include "stdio.h"
int main(int argc,char *argv[]){
int n,t;
printf("Please enter a positive integer...
n=");
if(scanf("%d",&n)!=1 || n<1){//保证输入是正整数,否则退出
printf("Input error, exit...
");
return 0;
}
printf("The result are as follows:
");
for(t=10;n/t;t*=10);//求出十进制数n的长度,用1后0的个数表示,如1000表示3位数
while(t/=10)
printf("%d ",n/t%10);//t/=10与n/t%10配合从高至低输出各位上的数字
printf("
");
return 0;
}
运行样例如下：
//不要超过int的范围就行了
#include<stdio.h>
int main()
{
int a;
int flag=0;
scanf("%d",&a);
if(a/1000000000)
{
printf("%d",a/1000000000);
flag=1;
}
if(a%1000000000/100000000 || flag)
{
printf("%d",a%1000000000/100000000);
flag=1;
}
if(a%100000000/10000000 || flag)
{
printf("%d",a%100000000/10000000);
flag=1;
}
if(a%10000000/1000000 || flag)
{
printf("%d",a%10000000/1000000);
flag=1;
}
if(a%1000000/100000 || flag)
{
printf("%d",a%1000000/100000);
flag=1;
}
if(a%100000/10000 || flag)
{
printf("%d",a%100000/10000);
flag=1;
}
if(a%10000/1000 || flag)
{
printf("%d",a%10000/1000);
flag=1;
}
if(a%1000/100 || flag)
{
printf("%d",a%1000/100);
flag=1;
}
if(a%100/10 || flag)
{
printf("%d",a%100/10);
flag=1;
}
if(a%10 || flag)
{
printf("%d
",a%10);
flag=1;
}
}
辛苦打来，望采纳，谢谢！
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