高一化学题 1.在标准状况下，224ml某气体的质量为0.64g，则该气体的摩尔质量为？ 2.配制 (高一化学)5．化合物A、B、C都只含有两种元素，且A、B均...

\u9ad8\u4e00\u5fc5\u4fee\u4e00\u5316\u5b66\u5173\u4e8e\u94a0\u7684\u6240\u6709\u65b9\u7a0b\u5f0f

\u5982\u4e0b\uff1a
\uff081\uff094Na+O2=2Na2O
\uff082\uff092Na+O2=Na2O2
\uff083\uff092Na\uff0b2H2O\uff1d2NaOH\uff0bH2\u2191
\uff084\uff092Na\uff0bCl2\uff1d2NaCl\uff0c4Na\uff0bTiCl4 = Ti\uff0b4NaCl
\uff085\uff092Na2O2\uff0b2CO2\uff1d2Na2CO3\uff0bO2
\uff086\uff092Na2O2\uff0b2H2O\uff1d4NaOH\uff0bO2\u2191

\uff087\uff09Na2O\uff0bCO2\uff1dNa2CO3
\uff088\uff09Na2O\uff0bH2O\uff1d2NaOH
\uff089\uff09\u9002\u91cf2NaOH \uff0bCO2\uff1dNa2CO3\uff0bH2O
\uff0810\uff09\u8fc7\u91cfNaOH \uff0bCO2\uff1dNaHCO3
\uff0811\uff09NaOH \uff0bHCl\uff1dNaCl\uff0bH2O
\uff0812\uff092NaCl\uff0b2H2O = 2NaOH\uff0bH2\u2191\uff0bCl2\u2191
\uff0813\uff09Na2CO3\uff0bCO2\uff0bH2O\uff1d2NaHCO3
\uff0814\uff092NaHCO3 = Na2CO3\uff0bCO2\u2191\uff0bH2O
\uff0815\uff09Na2CO3\uff0b2HCl\uff1d2NaCl\uff0bH2O\uff0bCO2\u2191\uff08\u53cd\u5e94\u76f8\u5bf9NaHCO3\u6162\uff09
\uff0816\uff09NaHCO3\uff0bHCl\uff1dNaCl\uff0bH2O\uff0bCO2\u2191 \uff08\u53cd\u5e94\u76f8\u5bf9Na2CO3 \u5feb\uff09
\uff0817\uff092Na\uff0bCuSO4\uff0b2H2O\uff1dCu(OH)2\u2193\uff0bNa2SO4\uff0bH2\u2191
\uff0818\uff09NaH\uff0bH2O\uff1dNaOH\uff0bH2\u2191
\uff0819\uff092Na\uff0bS = Na2S

C

标况下体积224ml即0.224L即0.01mol,0.64g/0.01mol,所以标况下此气体摩尔量为64g/mol,

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