利用python，给定一个大小写混写的字符串，输出成大写在前的新字符串？ 编写python程序，用户输入一个英文字符，根据输入字符的大...
python\u5982\u4f55\u540c\u65f6\u628a\u5b57\u7b26\u4e32\u5927\u5199\u53d8\u5c0f\u5199\uff0c\u5c0f\u5199\u53d8\u5927\u5199\u53ef\u4ee5\u76f4\u63a5\u901a\u8fc7str\u7c7b\u7684swapcase\u65b9\u6cd5\u53ef\u4ee5\u5feb\u901f\u5b9e\u73b0\u5927\u5199\u4fbf\u5c0f\u5199\u3001\u5c0f\u5199\u53d8\u5927\u5199\u7684\u529f\u80fd\uff0c\u53c2\u8003\u4ee3\u7801\u5982\u4e0b\uff1a
In[1]:s='BaiduZhidao'
In[2]:s.swapcase()
Out[2]:'bAIDUzHIDAO'
Python\u5728\u8bbe\u8ba1\u4e0a\u575a\u6301\u4e86\u6e05\u6670\u5212\u4e00\u7684\u98ce\u683c\uff0c\u8fd9\u4f7f\u5f97Python\u6210\u4e3a\u4e00\u95e8\u6613\u8bfb\u3001\u6613\u7ef4\u62a4\uff0c\u5e76\u4e14\u88ab\u5927\u91cf\u7528\u6237\u6240\u6b22\u8fce\u7684\u3001\u7528\u9014\u5e7f\u6cdb\u7684\u8bed\u8a00\u3002
\u6269\u5c55\u8d44\u6599\uff1a
python\u53c2\u8003\u51fd\u6570
chr(i)\u628a\u4e00\u4e2aASCII\u6570\u503c,\u53d8\u6210\u5b57\u7b26
ord(i)\u628a\u4e00\u4e2a\u5b57\u7b26\u6216\u8005unicode\u5b57\u7b26,\u53d8\u6210ASCII\u6570\u503c
oct(x)\u628a\u6574\u6570x\u53d8\u6210\u516b\u8fdb\u5236\u8868\u793a\u7684\u5b57\u7b26\u4e32
hex(x)\u628a\u6574\u6570x\u53d8\u6210\u5341\u516d\u8fdb\u5236\u8868\u793a\u7684\u5b57\u7b26\u4e32
str(obj)\u5f97\u5230obj\u7684\u5b57\u7b26\u4e32\u63cf\u8ff0
list(seq)\u628a\u4e00\u4e2asequence\u8f6c\u6362\u6210\u4e00\u4e2alist
tuple(seq)\u628a\u4e00\u4e2asequence\u8f6c\u6362\u6210\u4e00\u4e2atuple
\u53c2\u8003\u8d44\u6599\u6765\u6e90\uff1a\u767e\u5ea6\u767e\u79d1-Python \uff08\u8ba1\u7b97\u673a\u7a0b\u5e8f\u8bbe\u8ba1\u8bed\u8a00\uff09
n=ord(input("input an english letter: "))if 65<=n<=90: print('\u5927\u5199\u5b57\u7b26')elif 97<=n<=122: print('\u5c0f\u5199\u5b57\u7b26')else: print('\u5176\u4ed6\u5b57\u7b26')
输入一个大小写混写的字符串，再输出成大写在前的新字符串的python代码如下，仅4行：
s=input("");
a=[i for i in s if i.capitalize()==i];
b=[i for i in s if i.capitalize()!=i];
print("".join(a+b));
直接使用sort排序就好了 sort排序字符串的时候默认按照ASCII码大小(从小到大)
只会最简单的
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