七年级下解方程一题。（求过程）
\u4e03\u5e74\u7ea7\u89e3\u65b9\u7a0b\u7ec3\u4e60\u98987(2x-1)-3(4x-1)=4(3x+2)-1;
(5y+1)+ (1-y)= (9y+1)+ (1-3y);
[ ( )-4 ]=x+2;
20%+(1-20%)(320-x)=320\u00d740%
2(x-2)+2=x+1
2(x-2)-3(4x-1)=9(1-x)
11x+64-2x=100-9x
15-(8-5x)=7x+(4-3x)
3(x-7)-2[9-4(2-x)]=22
3/2[2/3(1/4x-1)-2]-x=2
1 2x-10.3x=15
2 0.52x-(1-0.52)x=80
3 x/2+3x/2=7
4 3x+7=32-2x
5 3x+5(138-x)=540
6 3x-7(x-1)=3-2(x+3)
7 18x+3x-3=18-2(2x-1)
8 3(20-y)=6y-4(y-11)
9 -(x/4-1)=5
10 3[4(5y-1)-8]=6
10/3 (x/5+3/7)=9x/2
5/3\uff08x+0.5)+2=3x-6
5x+2(2x/3+2)=2/3(x-6)+2
(2x-7)/2-(6x-5)/3=2x+3
(3x+2)/5-(x-6)=x/3
6x-(x/3+2)=2(x/5+5/2)-3
3(x/11-2)-5=2+3x/3
10/3(2x-6)=3/5
x/2-(x/3-2)=3
2/3(x+3)-3=5x/3
5/3(2x-5/3)=2x/5-8/9
25(x/3-x/2+2/5)-2=3/5(x-2/7)+4/9
(2x-1)-3(4x-1)=4(3x+2)-1
(5y+1)+ (1-y)= (9y+1)+ (1-3y)
[ ( )-4 ]=x+2
20%+(1-20%)(320-x)=320\u00d740%
2(x-2)+2=x+1
2(x-2)-3(4x-1)=9(1-x)
11x+64-2x=100-9x
15-(8-5x)=7x+(4-3x)
3(x-7)-2[9-4(2-x)]=22
3/2[2/3(1/4x-1)-2]-x=2
2x-10.3x=15
0.52x-(1-0.52)x=80
x/2+3x/2=7
\u76f8\u5173\u6982\u5ff5
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2.\u4f7f\u7b49\u5f0f\u6210\u7acb\u7684\u672a\u77e5\u6570\u7684\u503c\uff0c\u79f0\u4e3a\u65b9\u7a0b\u7684\u89e3\uff0c\u6216\u65b9\u7a0b\u7684\u6839\u3002
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4.\u65b9\u7a0b\u4e00\u5b9a\u662f\u7b49\u5f0f\uff0c\u7b49\u5f0f\u4e0d\u4e00\u5b9a\u662f\u65b9\u7a0b\u3002\u4e0d\u542b\u672a\u77e5\u6570\u7684\u7b49\u5f0f\u4e0d\u662f\u65b9\u7a0b\u3002
5.\u9a8c\u8bc1\uff1a\u4e00\u822c\u89e3\u65b9\u7a0b\u4e4b\u540e\uff0c\u9700\u8981\u8fdb\u884c\u9a8c\u8bc1\u3002\u9a8c\u8bc1\u5c31\u662f\u5c06\u89e3\u5f97\u7684\u672a\u77e5\u6570\u7684\u503c\u4ee3\u5165\u539f\u65b9\u7a0b\uff0c\u770b\u770b\u65b9\u7a0b\u4e24\u8fb9\u662f\u5426\u76f8\u7b49\u3002\u5982\u679c\u76f8\u7b49\uff0c\u90a3\u4e48\u6240\u6c42\u5f97\u7684\u503c\u5c31\u662f\u65b9\u7a0b\u7684\u89e3\u3002
3x+2y=12. (2)
(1)x3
3x+9y=33 (3)
(3)-(2)得
7y=21
解得 y=3
把y=3代入(1)得
x=2
所以方程租的解为x=2 y=3
原方程可化为x+3y=11. (1)
3x+2y=12. (2)
(1)x3
3x+9y=33 (3)
(3)-(2)得
7y=21
解得 y=3
把y=3代入(1)得
x=2
所以方程租的解为x=2 y=3
将第二个有分数的每一项×6
绛旓細2x+y-z=-4 (2)3x+y+2z=4 (3)锛1)+(2)寰3x-z=-6 (4)(3)-(2)寰梮+3z=8 (5)(4)*3+(5)寰10x=-10 x=-1 鎶妜=-1浠ｅ叆锛1锛 寰梱=1 鎶妜=-1 y=1浠ｅ叆锛2锛 寰 z=3 (3瑙ｏ細{ 4a-3b=5 (1)2a+b=5 (2)瑙ｆ柟绋 (2)*2-(1) 寰 5b=5...
绛旓細[1]2-锛1-y锛=-2 2-1+y=-2 y=-2-2+1=-3 锛2锛5-锛坸-1锛=3-3x 5-x+1=3-3x 2x=3-1-5 2x=-3 x=-1.5 锛3锛3-2锛2x+1锛=2锛坸-3锛3-4x-2=2x-6 6x=3-2+6 6x=7 x=7/6 锛4锛4x-3锛20-x锛=6x-7锛9-x锛4x-60+3x=6x-63+7x 7x-60=13x-63 6x=3...
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绛旓細瑙ｅ緱:x=9/13,y=1/13 8.5*(1/3)+5*X=15*X x=1/6 9.(1/3)x/12=(1/3)x/[12*(5/4)]+1 鍖栫畝寰楋細(5/3)x=(4/3)x+60 (1/3)x=60 x=180 10.2X+5X=14000 7X=14000 X=2000 2X=4000 5X=10000 11. x+(35-20)*1.5%x=1323 x=1080 12 . 2x-10.3x=15 13 ....
绛旓細瑙ｏ細锛1锛銆佹柟妗堜竴锛歽1=锛7.50+3锛*10*5=525锛堝厓锛夋墍浠=y1+6=531锛堝厓锛夋柟妗堜簩锛歽1=7.50*50*锛1+0.15锛=431.25锛堝厓锛夋墍浠=y1+5=436.25锛堝厓锛夛紙2锛夎鎬诲叡闇璐拱鏈暟涓簒锛屽垯 瀵规柟妗堜竴锛氶渶鍒嗭紙x/10)娆¤喘涔般倅1=锛7.50+3锛*10*(x/10)y=y1+y1/100+1=1.01y1+1=10....
绛旓細锛7x-1锛/0.024=锛1-0.2x锛/0.018-锛5x+1锛/0.012 瑙ｏ細锛7x-1锛/4=锛1-0.2x锛/3-锛5x+1锛/2 3锛7x-1锛=4锛1-0.2x锛-6锛5x+1锛21x-3=4-0.8x-30x-6 21x+0.8x+30x=4-6+3 51.8x=1 x=1梅51.8 x=5/259 ...
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绛旓細7y+6=6y;y=-6 5x+2=7x+8;2x=-6;x=-3 5鍒嗕箣2-8=4鍒嗕箣1-0.2x;8-160=5-4x;4x=157;x=39鍙4鍒嗕箣1 1-2鍒嗕箣1x=x+3鍒嗕箣1;6-3x=2x+2;5x=4;x=5鍒嗕箣4 18=5-x锛泋=-13 4鍒嗕箣3x+2=3-4鍒嗕箣1x;3x+8=12-x;4x=4;x=1 3x-7+4x=6x-2;x=5 10y+5=11y-5-2y;...
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