6X2+7X+2=0，求X 因式分解法解方程 6x^2+7x-3=0
6x2+7x+2\u56e0\u5f0f\u5206\u89e3\u539f\u5f0f
=6x \u00d7 x+\uff081+6\uff09x+2
=\uff086x+1\uff09\uff08x+1\uff09
\u5f88\u9ad8\u5174\u4e3a\u4f60\u89e3\u7b54\uff0c\u795d\u4f60\u5b66\u4e60\u8fdb\u6b65\uff01\u4e00\u523b\u6c38\u8fdc523 \u4e3a\u4f60\u89e3\u7b54~~
\u5982\u679c\u4f60\u8ba4\u53ef\u6211\u7684\u56de\u7b54\uff0c\u8bf7\u70b9\u51fb\u4e0b\u9762\u7684\u3010\u9009\u4e3a\u6ee1\u610f\u56de\u7b54\u3011\u6309\u94ae\uff0c\u8c22\u8c22~~
\u5982\u679c\u8fd8\u6709\u5176\u5b83\u95ee\u9898\uff0c\u8bf7\u53e6\u5916\u5411\u6211\u6c42\u52a9\uff0c\u7b54\u9898\u4e0d\u6613\uff0c\u656c\u8bf7\u7406\u89e3~~
6x²+7x-3=0
(3x-1)(2x+3)=0
3x-1=0
2x+3=0
x=1/3\u6216x=-3/2
解：（3x+2）（2x+1）=0
所以：X=-2/3或X=-1/2
这样的一元二次方程要用公式法解。
6x^2+7x+2=0
解：a=6,b=7,c=2
△(b^2-4ac)=7^2-6×2×4=1
x=(-b±△)/2a=(-7±1)/12
x=-0.5或-(2/3)
-(2/3)读作负三分之二。
（2x+1)(3x+2)=0
所以：x=-0.5 x=-2/3
-2
绛旓細绛旀鏄1鍜1/6 杩囩▼濡備笅 b²-4ac=7²-4x6=25 -b卤鈭歜²-4ac 7卤5 鈥斺斺 =鈥斺斺2a 2x6 ,7+5 7-5 1 鈥斺 =1, 鈥斺=鈥斺12 12 6 鈭磝1=1,x2=1/6
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