C语言程序设计:2、输入一个由字母组成的字符串，并分别以大写字母和小写字母形式输出该字符串。 C语言编程题 输入一个由大写字母组成的字符串,求字符串中包含...
C\u8bed\u8a00\u7f16\u7a0b:\u8f93\u5165\u4e00\u4e2a\u7531\u5b57\u6bcd\u7ec4\u6210\u7684\u5b57\u7b26\u4e32,\u5206\u522b\u4ee5\u5927\u5199\u5b57\u6bcd\u548c\u5c0f\u5199\u5b57\u6bcd\u5f62\u5f0f\u8f93\u51fa\u8be5\u5b57\u7b26\u4e32#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <ctype.h>
// \u628a\u5b57\u7b26\u4e32\u8f6c\u6362\u4e3a\u5c0f\u5199
char* str2lower(char *str)
{
char *p = str;
while (*str){
*str = tolower(*str);
str++;
}
return p;
}
// \u628a\u5b57\u7b26\u4e32\u8f6c\u6362\u4e3a\u5927\u5199
char* str2upper(char *str)
{
char *p = str;
while (*str){
*str = toupper(*str);
str++;
}
return p;
}
/* \u4f7f\u7528\u65b9\u6cd5\uff1a
* command [A|a] string
* \u53c2\u6570\u8bf4\u660e\uff1a
* string\u662f\u8981\u8f6c\u6362\u7684\u5b57\u7b26\u4e32
* [A|a]\u8868\u793a\u5c06\u5b57\u7b26\u4e32string\u8f6c\u5316\u4e3a\u5927\u5199\u8fd8\u662f\u5c0f\u5199
*/
int main(int argc, char *argv[])
{
if (argc != 3 || strlen(argv[1]) != 1){
printf("usage: command [A|a] string\n");
return EXIT_FAILURE;
}
if (isupper(argv[1][0]))
printf("\u5b57\u7b26\u4e32\u7684\u5927\u5199\u662f\uff1a%s\n", str2upper(argv[2]));
else if (islower(argv[1][0]))
printf("\u5b57\u7b26\u4e32\u7684\u5c0f\u5199\u662f\uff1a%s\n", str2lower(argv[2]));
else
printf("\u539f\u59cb\u7684\u5b57\u7b26\u4e32\u662f\uff1a%s\n", argv[2]);
return EXIT_SUCCESS;
}
char str[99]="";int i,n=0,times[26]={0};gets(str);for(i=0;str[i];i++){ times[str[i]-'A']++;}for(i=0;i<26;i++) if(times[i])n++; printf("%d\u4e2a\u4e0d\u540c\u5b57\u6bcd\n",n);
代码：#include <stdio.h>
#define MAX_LENGTH 300
char toLower(char ch)
{
if('A' <= ch && ch <= 'Z')
return ch - 'A' + 'a';
return ch;
}
char toUpper(char ch)
{
if('a' <= ch && ch <= 'z')
return ch - 'a' + 'A';
return ch;
}
int main()
{
char buf[MAX_LENGTH];
scanf("%s", buf);
for(char* p = buf; *p; p++)
printf("%c", toUpper(*p));
printf("\n");
for(char* p = buf; *p; p++)
printf("%c", toLower(*p));
printf("\n");
return 0;
}
输入：
Right?
输出：
RIGHT?
right?
附加说明：
该程序只在 C++ 编译器下编译通过，用 C 编译器编译不知能否通过。
由于代码在发送时被去除了空格，所以代码显得很凌乱。但是LZ还是可以在 Visual Studio 下按 Alt + F8 来重新格式化这段代码。
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