分别写出乙烯与,Br2,H2,Hcl,H2O的反应方程式
\u5206\u522b\u5199\u51fa\u5e76\u6ce8\u660e\u4e59\u70ef\u4e0eH2, Br2,HCL,H2O\u53cd\u5e94\u7684\u7ed3\u6784\u5f0f\u4e0e\u7ed3\u6784\u7b80\u5f0f \u6700\u597d\u53d1\u56fe\u7247\u5b9e\u9a8c\u5ba4\u7528\u4e59\u9187\u5728\u6d53\u786b\u9178\u7684\u50ac\u5316\u4f5c\u7528\u4e0b\uff0c\u52a0\u70ed\u81f3170\u2103\u65f6\u5236\u53d6\u4e59\u70ef\u3002
\u65b9\u7a0b\u5f0f\uff1aCH3CH2OH --(\u6d53\u786b\u9178\uff0c170\u2103)--> CH2=CH2\u2191 + H2O
\u548c\u6eb4CH2=CH2+Br2\u2192CH2Br\u2014CH2Br \u548c\u6c34CH2=CH2+H2O\u2192CH3CH2OH \u5236\u4f5c\u805a\u4e59\u70efnCH2=CH2\u2192 \u2014[\u2014CH2\u2014CH2\u2014]n\u2014 \u4f7f\u9ad8\u9530\u9178\u94be\u6eb6\u6db2\u892a\u82725C2H4+8KMnO4+12H2SO4======10HCOOH+8MnSO4+4K2SO4+12H2O \u4e59\u70ef\u71c3\u70e7 C2H4+3O2\u2192\u70b9\u71c3\u21922CO2+2H2O \u4e59\u70ef\u548c\u6c22\u6c14\u53cd\u6620CH2=CH2+H2---\u50ac\u5316\u5242\u52a0\u70ed---CH3CH3
\u548c\u6c2f\u5316\u6c22 CH2=CH2+HCl---\u50ac\u5316\u5242\u52a0\u70ed---CH3CH2Cl
\u548c\u8fc7\u6c27\u5316\u6c22 CH2=CH2+H2O2---\u50ac\u5316\u5242\u52a0\u70ed---HOCH2CH2OH
CH2=CH2+H2=CH3CH3
CH2=CH2+HCl=CH3CH2Cl
CH2=CH2+H2O=CH3CH2OH
绛旓細= 2 CO2 + 2 H2O 鍒涔欑儻锛欳2H5OH = C2H4 + H2O 锛堟祿纭吀浣滃偓鍖栧墏锛屽苟鍔犵儹锛変箼鐑姞鎴愶細 CH2=CH2 + H2 = CH3-CH3 锛堣鍌寲鍓傦級CH2=CH2 + CH2=CH2 = CH3-CH=CH-CH3 锛堣鍌寲鍓傦級鑱氬悎鍙嶅簲锛 n C2H4 = -[CH2-CH2]-n 锛堣鍌寲鍓傦級杩樻湁寰堝锛屽氨鍐杩欎簺 ...
绛旓細鏁呯瓟妗堜负锛欳H2=CH2+Br2鈫扖H2Br-CH2Br锛涳紙2锛夐摐涓庢祿纭吀鍦ㄥ姞鐑潯浠朵笅鍙嶅簲鐢熸垚纭吀閾溿佷簩姘у寲纭拰姘达紝鍙嶅簲鐨勬柟绋嬪紡涓篊u+2H2SO4锛堟祿锛夆柍 .CuSO4+SO2鈫+2H2O锛屾晠绛旀涓猴細Cu+2H2SO4锛堟祿锛夆柍 .CuSO4+SO2鈫+2H2O锛,3,锛1锛鍐欏嚭涔欑儻閫氬叆婧寸殑鍥涙隘鍖栫⒊婧舵恫涓彂鐢熷弽搴旂殑鍖栧鏂圭▼寮廮__锛涳紙2锛夊啓鍑...
绛旓細涔欑儻涓婧存槸鍙戠敓鍔犳垚鍙嶅簲鐨勶紝鍥涙隘鍖栫⒊浣滄憾鍓 CH2=CH2 + Br2鈫扖H2BrCH2Br 鍏跺疄杩樺彲鍙戠敓鍐嶅彇浠ｅ弽搴旂殑锛屼絾鏄潯浠舵病璇
绛旓細涔欑儻 + Br2 1,2-浜屾捍涔欑兎 鐜笝鐑 + Br2 1,2-浜屾捍鐜笝鐑 涔欑儻鍜鐜笝鐑蜂笌閰告ч珮閿伴吀閽炬憾娑插弽搴旀椂锛岄珮閿伴吀閽句細琚繕鍘熶负閿扮瀛愶紝鍚屾椂鐑冪被鍖栧悎鐗╄姘у寲涓虹浉搴旂殑閱涘拰閰傝繖鏄竴绉嶆哀鍖栧弽搴旓紝鍏蜂綋鍙嶅簲濡備笅锛氫箼鐑 + KMnO4 + H2SO4鐢熸垚涔欓啗 + CO2 + H2O + MnSO4 + K2SO4 鐜笝鐑 + KMnO4 + H...
绛旓細濡傛灉瑕佺悊璁轰笂鏉ュ垎鏋愶紝涓涓湁鍙岄敭锛屼竴涓笁閿紝鍙嶅簲涓婃ц川涓婇兘姣旇緝鐩镐技闅惧尯鍒嗭紝鍙彲浠ヤ粠鍔犳垚鍙嶅簲鐨勬瘮渚嬫潵鐪嬩簡銆備緥濡傚姞H2锛孊r2锛鐪嬫秷鑰楃墿璐ㄧ殑閲忥紝浣嗗墠鎻愯淇濊瘉浠栦滑缁撴瀯鐩镐技锛岄敭鏁扮瓑澶氫釜鍓嶆彁锛岃鐪嬪疄闄呫傛瘮濡:绛夌墿璐ㄧ殑閲涔欑儻涔欑倲灏卞彲浠ヤ粠鍔犳垚H2鎴朆r2鐨勯噺鏉ユ瘮杈冭绠楀垽鍒備箼鐐斾富瑕佺敤閫 涔欑倲涓昏鐢ㄩ旀槸鐢ㄤ簬鐓ф槑...
绛旓細瀹為獙瀹ゅ埗鐢茬兎 CH3COONa+NaOH鈫扤a2CO3+CH4(鏉′欢鏄疌aO 鍔犵儹)涔欑儻鐕冪儳 CH2=CH2+3O2鈫2CO2+2H2O(鏉′欢涓虹偣鐕)涔欑儻鍜婧存按 CH2=CH2+Br2鈫扖H2Br-CH2Br涔欑儻鍜屾按 CH2=CH2+H20鈫扖H3CH2OH (鏉′欢涓哄偓鍖栧墏)涔欑儻鍜屾隘鍖栨阿 CH2=CH2+HCl鈫扖H3-CH2Cl涔欑儻鍜屾阿姘 CH2=CH2+H2鈫扖H3-CH3 (鏉′欢涓哄偓鍖栧墏)涔欑儻鑱氬悎 nC...
绛旓細濡傛灉鏄珮涓敓鐨勮瘽锛屼箼鐑鍔犳垚鍙嶅簲鐨勬潯浠舵槸涓嶇敤璁扮殑锛屽啓 涓瀹氭潯浠讹紝鎴栬呬笉鍐欓兘鍙互 鍥犱负鏉′欢寰堝鏉傦紝姣斿鍜屾按鍙嶅簲鐨勬潯浠舵槸锛欻3PO4纭呰椈鍦熶綔鍌寲鍓傦紝280锛300鎽勬皬搴︼紝7.07锛8.08MPa.
绛旓細涔欑儻鏈4涓阿鍘熷瓙鐨勭害鏉燂紝纰冲師瀛愪箣闂翠互鍙岄敭杩炴帴銆傛墍鏈6涓師瀛愮粍鎴愮殑涔欑儻鏄叡闈侶-C-C瑙掓槸121.3掳锛汬-C-H瑙掓槸117.4 掳锛屾帴杩120 掳锛屼负鐞嗘兂sp 2娣锋垚杞ㄥ煙銆傝繖绉嶅垎瀛愪篃姣旇緝鍍电‖锛氭棆杞珻=C閿槸涓涓珮鍚哥儹杩囩▼锛岄渶瑕佹墦鐮聪閿紝鑰屼繚鐣櫹冮敭涔嬮棿鐨勭⒊鍘熷瓙銆俈SEPR妯″瀷涓哄钩闈㈢煩褰 绔嬩綋缁撴瀯涔熸槸骞抽潰鐭╁舰銆
绛旓細棰 鐪嬭鏈夋満鐗╂湁鍑犱釜涓嶉ケ鍜岄敭锛屾湁鍑犱釜涓嶉ケ鍜屽害涓鑸兘鍙互鍔犳阿锛屼絾閰敭鍜岀晶鍩轰笂涓嶅彲锛屽姞婧涓鑸槸鍙岄敭鍜屼笁閿姞锛岃嫰鐜笉琛
绛旓細CH2=CH2+H2===CH3-CH3 CH涓塁H+2H2===CH3-CH3 C6H6+3H2===C6H12 CH2=CH2+Br2===CH2Br-CH2Br CH涓塁H+2Br2===CH2Br2-CH2Br2 鏄繖涓槢~~~
