化学 。。。请问4mol/L的NaOH怎么配制。急、在线等 。。谢谢。。。
\u9ad8\u4e2d\u5316\u5b66\u9898\u6c42\u52a9\uff0c\u5728\u7ebf\u7b49\uff0c\u6025\uff0c\u8c22\u8c221\u3001\u6c42\u4e0b\u5217\u6eb6\u6db2\u7684PH\u503c
\uff081\uff090.005mol/L\u7684\u786b\u9178
c(H+)=0.01mol/L
PH= -lg 0.01 =2
\uff082\uff090.01mol/L\u7684NaOH
c(H+)=10^-14/0.01=10^-12mol/L
PH=12
\uff083\uff090.0005mol/L\u7684Ba(OH)2
C(OH-)=0.001 mol/L
PH=11
2\u3001\u6c42\u4e0b\u5217\u6eb6\u6db2\u7684C(H+)
\uff081\uff09PH=4\u7684\u918b\u9178
10^-4 mol/L
\uff082\uff090.0005mol/LCa(OH)2
C(OH-)=0.001 mol/L
c(H+)=10^-11mol/L
\uff083\uff090.02mol/L\u7684\u786b\u9178300mL\u4e0e0.01mol/L\u7684\u76d0\u9178200mL\u6df7\u5408
c(H+)=(0.02\u00d72 \u00d70.3+0.01 \u00d70.2)/(0.3+0.2)
=0.028 mol/L
\u56e0\u4e3aPH\uff1d7\uff0c\u6240\u4ee5[H+]=[OH-]\uff0c\u2460\u5f0f\uff1b
\u53c8\u636e\u7535\u8377\u5b88\u6052\u5f97[Na+]+[H+]=[OH-]+[Cl-]+[ClO-]\uff0c\u2461\u5f0f\uff1b
\u636e\u65b9\u7a0b\u5f0fCl2+H2O=HCl+HClO\uff0c\u751f\u6210\u7684HCl\u548cHClO\u7684\u603b\u91cf\u76f8\u7b49\uff0c\u4e0eNaOH\u53cd\u5e94\u540e\u751f\u6210Cl-\u548cClO-\uff0c\u6b64\u65f6\u4e8c\u8005\u7684\u91cf\u76f8\u7b49\u3002\u6c34\u89e3\u540eClO-\u90e8\u5206\u8f6c\u53d8\u6210HClO\uff0c\u4f46ClO-\u548cHClO\u7684\u603b\u91cf\u4e0e\u6c34\u89e3\u524dClO-\u7684\u603b\u91cf\u76f8\u7b49\uff0c\u6240\u4ee5\u4ecd\u4e0eCl-\u91cf\u76f8\u7b49\uff0c\u6240\u4ee5[Cl-]=[ClO-]+[HClO]\uff0c\u2462\u5f0f\u3002
\u5c06\u2460\u5f0f\u548c\u2462\u5f0f\u4ee3\u5165\u2461\u5f0f\u4e2d\uff0c\u5373\u53ef\u5f97\u7b54\u6848\u3002
\u7b2c\u4e8c\u95ee\u4e2d\u6c22\u6c27\u5316\u94a0\u6d53\u5ea6\u4e3a0\uff0c\u5373\u6ca1\u52a0\u6c22\u6c27\u5316\u94a0\uff0c\u6240\u4ee5\u4e3a\u6c2f\u6c34\u672c\u8eab\u3002\u56e0HClO\u9178\u6027\u5f88\u5f31\uff0c\u6240\u4ee5\u7535\u79bb\u7684\u5f88\u5c11\uff0c\u6240\u4ee5\u5e94\u8be5\u662fC\uff08Hclo\uff09\u5927\u4e8eC\uff08clo-\uff09\u3002\u5373\u4f7f\u662f\u5f31\u9178\u4e2d\u76f8\u5bf9\u8f83\u5f3a\u7684\u918b\u9178\uff0c\u7535\u79bb\u5ea6\u4e5f\u53ea\u67091.32%\u3002
称取4克氢氧化钠固体,倒在小烧杯里,加少量水溶解,转入100毫升容量瓶里,洗涤烧杯二三次,转入容量瓶,加水定容。注意3/4 10+2
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