BGP实验的问题:R1 R2 R3 R4 R5全部都是互联,R1属于AS100,R2R3R4属于AS200,R6属于AS300,然后R1有个环回 R1 R2 R3 R4都为300欧姆 R5为600欧姆是求开...

\u7269\u7406\uff1aR1=R2=R3=R4=30\u03a9,R5=60\u3002\u6c42\u5f00\u5173\u6253\u5f00\u4e0e\u95ed\u5408\u65f6a\uff0cb\u4e4b\u95f4\u7684\u7b49\u6548\u7535\u963b\u3002

\u5f00\u5173\u65ad\u5f00\u65f6\uff1a R1,R2,R5\u5e76\u8054\uff0cR2\u4e0eR4\u4e32\u8054\uff0cR1\u4e0eR3\u4e32\u8054\uff0c\u5f97Rab=20\u03a9
\u5f00\u5173\u95ed\u5408\u65f6\uff1a R1,R2\u5e76\u8054\uff0cR3,R4\u5e76\u8054\uff0c\u56db\u4e2a\u7535\u963b\u4e24\u4e24\u4e32\u8054\u540e\u4e0eR5\u5e76\u8054\uff0c\u5f97Rab=300/11\u03a9

\u6269\u5c55\u8d44\u6599
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\u7b49\u6548\u7535\u8def\u662f\u5c06\u4e00\u4e2a\u590d\u6742\u7684\u7535\u8def\uff0c\u901a\u8fc7\u7535\u963b\u7b49\u6548\u3001\u7535\u5bb9\u7b49\u6548\uff0c\u7535\u6e90\u7b49\u6548\u7b49\u65b9\u6cd5\uff0c\u5316\u7b80\u6210\u5177\u6709\u4e0e\u539f\u7535\u8def\u529f\u80fd\u76f8\u540c\u7684\u7b80\u5355\u7535\u8def\u3002\u8fd9\u4e2a\u7b80\u5355\u7684\u7535\u8def\uff0c\u79f0\u4f5c\u539f\u590d\u6742\u7535\u8def\u7684\u7b49\u6548\u7535\u8def \u3002
\u53c2\u8003\u8d44\u6599\u767e\u5ea6\u767e\u79d1-\u7b49\u6548\u7535\u963b

\u5f00\u5173\u65ad\u5f00\u65f6\uff1a R1,R2,R5\u5e76\u8054\uff0cR2\u4e0eR4\u4e32\u8054\uff0cR1\u4e0eR3\u4e32\u8054\uff0c\u5f97Rab=20\u03a9
\u5f00\u5173\u95ed\u5408\u65f6\uff1a R1,R2\u5e76\u8054\uff0cR3,R4\u5e76\u8054\uff0c\u56db\u4e2a\u7535\u963b\u4e24\u4e24\u4e32\u8054\u540e\u4e0eR5\u5e76\u8054\uff0c\u5f97Rab=300/11\u03a9
\u51e0\u4e2a\u8fde\u63a5\u8d77\u6765\u7684\u7535\u963b\u6240\u8d77\u7684\u4f5c\u7528\uff0c\u53ef\u4ee5\u7528\u4e00\u4e2a\u7535\u963b\u6765\u4ee3\u66ff\uff0c\u8fd9\u4e2a\u7535\u963b\u5c31\u662f\u90a3\u4e9b\u7535\u963b\u7684\u7b49\u6548\u7535\u963b\u3002\u4e5f\u5c31\u662f\u8bf4\u4efb\u4f55\u7535\u56de\u8def\u4e2d\u7684\u7535\u963b\uff0c\u4e0d\u8bba\u6709\u591a\u5c11\u53ea\uff0c\u90fd\u53ef\u7b49\u6548\u4e3a\u4e00\u4e2a\u7535\u963b\u6765\u4ee3\u66ff\u3002

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\u7b49\u6548\u7535\u8def\u53c8\u4e3a\u7b49\u503c\u7535\u8def\uff0c\u5728\u540c\u6837\u7ed9\u5b9a\u6761\u4ef6\u4e0b\uff0c\u53ef\u4ee3\u66ff\u53e6\u4e00\u7535\u8def\u4e14\u5bf9\u5916\u6027\u80fd\u4e0d\u53d8\u7684\u7535\u8def\uff0c\u7535\u673a\u3001\u53d8\u538b\u5668\u7b49\u7535\u6c14\u8bbe\u5907\u7684\u7535\u78c1\u8fc7\u7a0b\u53ef\u7528\u5176\u76f8\u5e94\u7684\u7b49\u6548\u7535\u8def\u6765\u5206\u6790\u7814\u7a76\u3002
\u7b49\u6548\u7535\u8def\u5c06\u4e00\u4e2a\u590d\u6742\u7684\u7535\u8def\uff0c\u901a\u8fc7\u7535\u963b\u7b49\u6548\u3001\u7535\u5bb9\u7b49\u6548\u548c\u7535\u6e90\u7b49\u6548\u7b49\u65b9\u6cd5\uff0c\u5316\u7b80\u6210\u5177\u6709\u4e0e\u539f\u7535\u8def\u529f\u80fd\u76f8\u540c\u7684\u7b80\u5355\u7535\u8def\u3002\u8fd9\u4e2a\u7b80\u5355\u7684\u7535\u8def\uff0c\u79f0\u4f5c\u539f\u590d\u6742\u7535\u8def\u7684\u7b49\u6548\u7535\u8def \u3002
\u53c2\u8003\u8d44\u6599\u6765\u6e90\uff1a\u767e\u5ea6\u767e\u79d1-\u7b49\u6548\u7535\u963b

R2和R4都将各自学习到的EBGP重发布都OSPF中。然后再将OSPF重发布回BGP。就可以了!!!
另外,你的R2R4之间应该没有起邻居关系,只要把R2R4起邻居,也可以学到。

是什么互联 是全互联?没图没真相
BGP传递路由的规则:BGP学来的路由的下一跳如果不可达 那么这条路由不可用 也不会传递
iBGP学来的路由不会传递给iBGP邻居
eBGP学来的路由 如果该路由也不存在于IGP表中 那么不可用 也不会传递

R2和R4之间建立ibgp邻居,同时要更改下一跳,华为命令为peer xxx next-hop-local,思科为
neighbor xxx next-hop-self

R2和R4之间起ibgp应该可以学到

23522222

扩展阅读:扫一扫题目出答案 ... bgp综合配置实验 ... 固态硬盘用mbr还是gpt ... bgp ibgp实验ensp ... 一键修复丢失dll的方法 ... bgp路由协议配置实验 ... 华为bgp配置实例 ... ensp实验bgp路由注入 ... bgp基本配置实验 ...

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