高一数学,如何化简三角函数,急!~

\u9ad8\u4e00\u6570\u5b66\uff01\uff01\u4e09\u89d2\u51fd\u6570\u5316\u7b80\uff01\uff01\uff01\uff01

\u8fd9\u4e2a\u5f97\u7528\u516c\u5f0f\u3002\u3002\u3002cos2X+1=2cos^2x-1+1=2cos^2x
tanx/2-cotx/2=sinx/(1+cosx)-sinx/(1-cosx)=-2cosx/sinx=-1/2sin2x
\u6253\u6570\u5b66\u7b26\u53f7\u90fd\u6655\u4e86\uff0c\u4f30\u8ba1\u5f97\u6709\u70b9\u9519\u8bef\u3002
\u4e0d\u8fc7\u697c\u4e3b\u8981\u638c\u63e1\u597d\u6570\u5b66\u516c\u5f0f\u5c31\u6ca1\u95ee\u9898\u4e86\u54e6\uff01

=(sin\u03b1)^2-(sin\u03b1)^2(sin\u03b2)^2+\uff08sin\u03b2\uff09^2+\uff08cos\u03b1\uff09^2\uff08cos\u03b2\uff09^2
=(sin\u03b1)^2[1-(sin\u03b2)^2]+\uff08sin\u03b2\uff09^2+\uff08cos\u03b1\uff09^2\uff08cos\u03b2\uff09^2
=(sin\u03b1)^2\uff08cos\u03b2\uff09^2+\uff08cos\u03b1\uff09^2\uff08cos\u03b2\uff09^2+\uff08sin\u03b2\uff09^2
=\uff08cos\u03b2\uff09^2[(sin\u03b1)^2+\uff08cos\u03b1\uff09^2]+\uff08sin\u03b2\uff09^2
=\uff08cos\u03b2\uff09^2+\uff08sin\u03b2\uff09^2
=1

解:1、原式=6根号5((根号3/2)sinx+(1/2)cosx)=6根号5(sinxcosπ/6+cosxsinπ/6)=6根号5sin(x+π/6)
2、2(根号3/2sin(x/2)+1/2cos(x/2))=2sin(x/2+π/6)
3、原式=sin(360-13)cos(180-32)+sin(90-13)cos(90-32)
=(-sin13)(-cos32)+cos13sin32
=sin13cos32+cos13sin32
=sin(13+32)=sin45=根号2/2

1、原式=6√5((√3/2)sinx+(1/2)cosx)=6√5(sinx cos π/6+cosx sinπ/6)=6√5sin(x+π/6)
3、原式=2(√3/2sin(x/2)+1/2cos(x/2))
=2(sinx cos π/6+cosx sinπ/6)
=2sin(x/2+π/6)
5、原式=sin(360°-13°)cos(180°-32°)+sin(90°-13°)cos(90°-32°)
=(-sin13°)(-cos32°)+cos13°sin32°
=sin13°cos32°+cos13°sin32°
=sin(13°+32°)=sin45°=√2/2

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