C语言习题中,编程实现从键盘任意输入20个整数,统计非负数个数,并计算非负数之和 c语言实现从键盘任意输入20个整数,统计非负数个数,计算非负...

\u4e00\u9053c\u8bed\u8a00\u7f16\u7a0b\u9898\uff0c\u6570\u7ec4\u8bfe\u540e\u4f5c\u4e1a\uff1a\u7f16\u7a0b\u5b9e\u73b0\u4ece\u952e\u76d8\u4efb\u610f\u8f93\u516520\u4e2a\u6574\u6570\uff0c\u7edf\u8ba1\u975e\u8d1f\u6570\u4e2a\u6570\uff0c\u5e76\u8ba1\u7b97\u975e\u8d1f\u6570\u53ea\u548c\u3002

#include
void main()
{
int s[20],a,n=0,i,sum=0;
printf("\u8bf7\u8f93\u516520\u4e2a\u6574\u6570:\n");
for(i=0;i<20;i++)
{
scanf("%d",&a);
s[i]=a;
}
for(i=0;i<20;i++)
{
if(s[i]>=0)
{
n++;
sum+=s[i];
}
}
printf("\u975e\u8d1f\u6574\u6570\u7684\u4e2a\u6570:%d\n\u975e\u8d1f\u6574\u6570\u7684\u548c:%d\n",n,sum);

}

scanf("%d",n[i]);\u5e94\u5f53
\u8be5\u4e3ascanf("%d",&n[i]);
\u8fd9\u662f\u521d\u5b66\u8005\u5e38\u72af\u9519\u8bef\u4e4b\u4e00\uff0cscanf\u540e\u9762\u7684\u53c2\u6570\u5e94\u5f53\u662f\u5730\u5740
printf("%d
%d",&a,&b);
\u5e94\u6539\u4e3a
printf("%d
%d",a,b);
\u8fd9\u4e2a\u6709\u70b9\u72af\u7684\u4e0d\u5e94\u8be5\uff0cprintf\u540e\u9762\u7684\u53c2\u6570\u4e0d\u662f\u5730\u5740

#include "stdio.h"
void main()
{
    int a[20],n=0,i,sum=0;
    for(i=0;i<20;i++)
    scanf("%d",&a[i]);//输入20个数
    for(i=0;i<20;i++)
    {
     if(a[i]>=0)
     {
     n++;//统计非负数的个数
     sum+=a[i];//非负数的和
     }
    }
    printf("个数:%d 和:%d",n,sum);
}


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