一道高一的化学题，，帮帮忙，在线等。。only you~~~~~~~~~~~~~~~~~~~~~
\u7ed9\u621110\u9053\u9ad8\u4e00\u7ecf\u5178\u5316\u5b66\u9898Thank you\u4f8b1\uff1a\u53d6ag\u67d0\u7269\u8d28\u5728\u6c27\u6c14\u4e2d\u5b8c\u5168\u71c3\u70e7\uff0c\u5c06\u5176\u4ea7\u7269\u8ddf\u8db3\u91cf\u7684\u8fc7\u6c27\u5316\u94a0\u56fa\u4f53\u5b8c\u5168\u53cd\u5e94\uff0c\u53cd\u5e94\u540e\u56fa\u4f53\u7684\u8d28\u91cf\u6070\u597d\u589e\u52a0\u4e86ag\u3002\u4e0b\u5217\u7269\u8d28\u4e2d\u4e0d\u80fd\u6ee1\u8db3\u4e0a\u8ff0\u7ed3\u679c\u7684\u662fA H2 B CO C C6H12O6 D C12H22O11
\u89e3\u6790\uff1a\u7531CO+Na2O2 Na2CO3\u53ef\u77e5agCO\u6ee1\u8db3\u9898\u610f\uff0cagH2\u4e5f\u6ee1\u8db3\uff0c\u53ef\u4ee5\u62d3\u5c55\u5316\u5b66\u5f0f\u80fd\u6539\u5199\u4e3a(CO)m(H2)n\u5c31\u6ee1\u8db3\u9898\u610f\u3002\u800cC6H12O6\u53ef\u6539\u5199\u6210(CO)6(H2)6\uff0cC12H22O11\u4e0d\u80fd\u6539\u5199\u6210(CO)m(H2)n\u7684\u5f62\u5f0f\uff0c\u5373C12H22O11\u5b8c\u5168\u71c3\u70e7\u7684\u4ea7\u7269\u4e0d\u6ee1\u8db3\u9898\u610f\uff0c\u7b54\u6848\u4e3aD\u3002
\u4f8b2\uff1a\u6709Na2CO3\u3001NaHCO3\u3001CaO\u548cNaOH\u7ec4\u6210\u7684\u6df7\u5408\u726927.2 g\uff0c\u628a\u5b83\u4eec\u6eb6\u4e8e\u8db3\u91cf\u6c34\u4e2d\uff0c\u5145\u5206\u53cd\u5e94\u540e\uff0c\u6eb6\u6db2\u4e2dCa2+\u3001CO32\u2014\u3001HCO3¬\u5747\u8f6c\u5316\u4e3a\u6c89\u6dc0\u3002\u5c06\u53cd\u5e94\u540e\u5bb9\u5668\u5185\u6c34\u5206\u84b8\u5e72\uff0c\u6700\u540e\u5f97\u5230\u767d\u8272\u56fa\u4f5329 g\uff0c\u5219\u539f\u6df7\u5408\u7269\u4e2dNa2CO3\u7684\u8d28\u91cf\u662f
A 21.2 g B 10.6 g C 17.2 g D 14.5 g
\u89e3\u6790\uff1a\u672c\u9898\u6d89\u53ca\u53cd\u5e94\u4e3b\u8981\u6709\uff1a\u2460CaO\uff0bH2O\uff1dCa(OH)2
\u2461Na2CO3\uff0bCa(OH)2\uff1dCaCO3\u2193\uff0b2NaOH
\u2462NaHCO3\uff0bCa(OH)2\uff1dCaCO3\u2193\uff0bNaOH\uff0bH2O
\u2460+\u2461\u52a0\u5408\u7ea6\u7b80\u5f97\uff1a\u2463Na2CO3\uff0bCaO\uff0bH2O\uff1dCaCO¬3\u2193\uff0b2NaOH
\u2460+\u2462\u52a0\u5408\u7ea6\u7b80\u5f97\uff1a\u2464NaHCO3\uff0bCaO\uff1dCaCO3\u2193\uff0bNaOH
\u636e\u9898\u610f\uff0c\u6700\u540e\u5f97\u5230\u768429 g\u767d\u8272\u56fa\u4f53\u4e3aCaCO3\u548cNaOH\u7684\u6df7\u5408\u7269\uff0c\u6839\u636e\u8d28\u91cf\u5b88\u6052\uff0c\u7531\u2463\u2464\u4e24\u5f0f\u53ef\u77e5\uff1a\u56fa\u4f53\u753127.2g\u589e\u81f329g\uff0c\u6240\u589e\u8d28\u91cf\u4e3a\u53cd\u5e94\u2463\u4e2d\u53c2\u52a0\u53cd\u5e94\u7684H2O\u7684\u8d28\u91cf\u3002\u636e\u53cd\u5e94\u2463\u8ba1\u7b97\u6709m(Na2CO3)\uff1d10.6g\u3002
\u4e00\u3001\u5b88\u6052\u6cd5
\u4f8b1\uff0e\u6709\u4e00\u5728\u7a7a\u6c14\u91cc\u66b4\u9732\u8fc7\u7684NaOH\u56fa\u4f53\uff0c\u7ecf\u5206\u6790\u77e5\u5176\u542b\u6c347.65%\uff0c\u542bNa2CO34.32%\uff0c\u5176\u4f59\u662fNaOH\u3002\u82e5\u5c061 g\u8be5\u6837\u54c1\u653e\u5165\u542b\u67093.65g\u7684\u76d0\u9178\u4e2d\u4f7f\u5176\u5b8c\u5168\u53cd\u5e94\u540e\uff0c\u6b8b\u9178\u518d\u752850g2%\u7684NaOH\u6eb6\u6db2\u6070\u597d\u4e2d\u548c\u5b8c\u5168\u3002\u84b8\u53d1\u6240\u5f97\u6eb6\u6db2\u81f3\u5e72\uff0c\u8ba1\u7b97\u6240\u5f97\u56fa\u4f53\u8d28\u91cf\u662f\u591a\u5c11\u514b\uff1f
\u89e3\u6790\uff1a\u6700\u540e\u6240\u5f97\u56fa\u4f53\u7269\u8d28\u4e3aNaCl\uff0c\u800c\u6c2f\u5143\u7d20\u5168\u90e8\u6765\u81ea\u76d0\u9178\uff0c\u4e14\u76d0\u9178\u5b8c\u5168\u53cd\u5e94\uff0c\u5219\u53ef\u7531\u6c2f\u5143\u7d20\u5b88\u6052\u5feb\u901f\u89e3\u9898\u3002
HCl \uff5e NaCl
36.5 58.5
3.65g m(NaCl) \u89e3\u5f97\uff1am(NaCl)=5.85g
\u7b54\u6848\uff1a5.85g
\u4e8c\u3001\u5dee\u91cf\u6cd5
\u4f8b2\uff0e\u5728\u4e00\u5b9a\u6761\u4ef6\u4e0b\uff0c\u4f7fH2\u548cO2\u7684\u6df7\u5408\u6c14\u4f5326 g\u5145\u5206\u53d1\u751f\u53cd\u5e94\u3002\u6240\u5f97\u4ea7\u7269\u5728\u9002\u5f53\u6e29\u5ea6\u4e0b\u8ddf\u8db3\u91cf\u7684\u56fa\u4f53Na2O2\u53cd\u5e94\uff0c\u4f7f\u56fa\u4f53\u589e\u91cd2 g \u3002\u6c42\u539f\u6df7\u5408\u6c14\u4f53\u4e2dO2\u548cH2\u7684\u8d28\u91cf\u3002
\u89e3\u6790\uff1a\u5148\u6839\u636e\u5dee\u91cf\u6cd5\uff0c\u6c42\u51fa\u4f7f\u56fa\u4f53\u589e\u91cd2 g\u6240\u9700\u6c34\u7684\u8d28\u91cf\uff0c\u518d\u6c42O2\u548cH2\u7684\u8d28\u91cf\u3002
\u8bbe\u53cd\u5e94\u751f\u6210\u6c34\u7684\u8d28\u91cf\u4e3ax
2Na2O2+2H2O\uff1d4NaOH+O2\u2191 \u25b3m
156g 36g 160g 4g
x 2g
36\u22364=x\u22362g x=18g
\u6839\u636e2H2+O2=2H2O\uff0c\u8981\u751f\u621018 g\u6c34\u9700\u8981\u6c27\u6c1416 g\uff0c\u6c22\u6c142 g \uff0c\u5269\u4f59\u6c14\u4f53\u53ef\u80fd\u662f\u6c22\u6c14\uff0c\u4e5f\u53ef\u80fd\u662f\u6c27\u6c14\u3002
\u7b54\u6848\uff1a16 g\u300110 g\u62162 g\u300124 g
\u4e09\u3001\u65b9\u7a0b\u5f0f\u53e0\u52a0\u6cd5
\u4f8b3\uff0e\u5c067.2 g CO\u548cH2\u7684\u6df7\u5408\u6c14\u4f53\u4e0e\u8db3\u91cfO2\u5145\u5206\u71c3\u70e7\u540e\uff0c\u7acb\u5373\u901a\u5165\u8db3\u91cf\u7684Na2O2\u56fa\u4f53\u4e2d\uff0c\u56fa\u4f53\u7684\u8d28\u91cf\u589e\u52a0
A\uff0e2.1 g B\uff0e3.6 g C\uff0e7.2 g D\uff0e\u65e0\u6cd5\u786e\u5b9a
\u89e3\u6790\uff1a\u6b64\u9898\u5229\u7528\u201c\u65b9\u7a0b\u53e0\u52a0\u6cd5\u201d\u975e\u5e38\u7b80\u4fbf\uff0c\u9898\u4e2d\u6574\u4e2a\u8fc7\u7a0b\u53d1\u751f\u56db\u4e2a\u53cd\u5e94\uff1a
\u24602H2\uff0bO2\uff1d2H2O \u24612H2O\uff0b2Na2O2\uff1d4NaOH\uff0bO2\u2191
\u24622CO\uff0bO2\uff1d2CO2 \u24632CO2\uff0b2Na2O2\uff1d2Na2CO3\uff0bO2\u2191
\u7531\u2460\u3001\u2461\u53e0\u52a0\u5f972H2\uff0b2Na2O2\uff1d4NaOH\uff0c\u7531\u2462\u3001\u2463\u53e0\u52a0\u5f972CO\uff0b2Na2O2\uff1d2Na2CO3\uff0c\u7531\u53e0\u52a0\u65b9\u7a0b\u5f0f\u4e0d\u96be\u770b\u51fa\uff0cNa2O2\u5c06\u5168\u90e8\u7684CO\u548cH2\u5438\u6536\uff0c\u56e0\u6b64\u589e\u91cd\u7684\u8d28\u91cf\u4e3aCO\u4e0eH2\u7684\u8d28\u91cf\u4e4b\u548c\u3002\u672c\u9898\u56fd\u201cO2\u201d\u8d77\u5230\u4e86\u201c\u50ac\u5316\u201d\u4f5c\u7528\u3002
\u7b54\u6848\uff1aC
\u56db\u3001\u4e2d\u503c\u5047\u8bbe\u6cd5
\u4f8b4\uff0e 18.4gNaOH\u548cNaHCO3\u56fa\u4f53\u6df7\u5408\u7269\uff0c\u5728\u5bc6\u95ed\u5bb9\u5668\u4e2d\u52a0\u70ed\u5230\u7ea6250\u2103\uff0c\u7ecf\u5145\u5206\u53cd\u5e94\u540e\u6392\u51fa\u6c14\u4f53\uff0c\u51b7\u5374\u540e\u79f0\u5f97\u5269\u4f59\u56fa\u4f53\u8d28\u91cf\u4e3a15.73g\u3002\u8bd5\u8ba1\u7b97\u539f\u6df7\u5408\u7269\u4e2dNaOH\u7684\u8d28\u91cf\u5206\u6570\u3002
\u89e3\u6790\uff1a\u4e2d\u503c\u5047\u8bbe\u6cd5\u662f\u9009\u5b9a\u53d8\u5316\u8fc7\u7a0b\u4e2d\u67d0\u70b9(\u5982\u6070\u597d\u5b8c\u5168\u53cd\u5e94)\u7684\u91cf\u503c\u4e3a\u53c2\u7167\uff0c\u5206\u6790\u3001\u63a8\u7406\u53d8\u5316\u7684\u5173\u7cfb\uff0c\u8fdb\u800c\u6c42\u89e3\u7684\u65b9\u6cd5\u3002\u672c\u9898\u7684\u5173\u952e\u662f\u5206\u6790\u51fa\u8d28\u91cf\u51cf\u5c11\u7684\u539f\u56e0\uff0c\u7531\u539f\u56e0\u518d\u786e\u5b9a\u6240\u53d1\u751f\u7684\u5316\u5b66\u53cd\u5e94\uff0c\u8fdb\u884c\u4e0b\u4e00\u6b65\u8ba1\u7b97\u6c42\u89e3\u3002
\u8bbe18.84gNaOH\u548cNaHCO3\u6070\u597d\u5b8c\u5168\u53cd\u5e94\uff0c\u56fa\u4f53\u51cf\u5c11\u4e3ax
NaOH+NaHCO3\uff1dNa2CO3+H2O\u2191 \u25b3m
(40+84)g 18g 18g
18.4g x
(48+84) g\u223618.4g= 18g\u2236x x=2.67g
\u56fa\u4f53\u8d28\u91cf\u5b9e\u9645\u51cf\u5c11\uff1a18.4g\u201415.73g=2.67g
\u5373\u56fa\u4f53\u8d28\u91cf\u51cf\u5c11\u662f\u4ea7\u751f\u4e86H2O\uff0c\u4e14NaOH\u548cNaHCO3\u6070\u597d\u5b8c\u5168\u53cd\u5e94\u3002
\u6df7\u5408\u7269\u4e2dNaOH\u7684\u8d28\u91cf\u5206\u6570\u4e3a\uff1a40/(40+84)=32.3%
\u7b54\u6848\uff1a32.3%
\u4f8b2\uff1a\u628a\u4e00\u5757\u94c1\u94dd\u5408\u91d1\u6eb6\u4e8e\u8db3\u91cf\u7684\u76d0\u9178\u4e2d\uff0c\u901a\u5165\u8db3\u91cf\u7684\u6c2f\u6c14\u4e2d\uff0c\u518d\u52a0\u5165\u8fc7\u91cfNaOH\u6eb6\u6db2\uff0c\u8fc7\u6ee4\uff0c\u5c06\u6ee4\u6e23\u5145\u5206\u707c\u70e7\uff0c\u5f97\u5230\u7684\u56fa\u4f53\u6b8b\u7559\u7269\u6070\u597d\u8ddf\u539f\u6765\u5408\u91d1\u7684\u8d28\u91cf\u76f8\u7b49\uff0c\u5219\u6b64\u5408\u91d1\u4e2d\uff0c\u94c1\u4e0e\u94dd\u7684\u8d28\u91cf\u6bd4\u7ea6\u4e3a A\uff0e1:1 B\uff0e3:1 C\uff0e7:3 D\uff0e1:4
\u94c1\u94dd\u5408\u91d1\u7c89\u672b\u6eb6\u4e8e\u8db3\u91cf\u76d0\u9178\u4e2d\uff0c\u751f\u6210Al3+\u548cFe2+\uff0c\u52a0\u5165\u8fc7\u91cfNaOH\u6eb6\u6db2\uff0cAl3+\u8f6c\u5316\u4e3aAlO2\u2014\uff0c\u7559\u5728\u6eb6\u6db2\u4e2d\uff1bFe3+\u751f\u6210\u4e86Fe(OH)3\u6c89\u6dc0\uff0c\u8fc7\u6ee4\u51fa\u6c89\u6dc0\uff0c\u7ecf\u6d17\u6da4\u3001\u5e72\u71e5\u3001\u707c\u70e7\uff0c\u5f97\u5230\u7684\u7ea2\u8272\u7c89\u672b\u4e3aFe2O3\uff0c\u94c1\u5728\u53cd\u5e94\u8fc7\u7a0b\u4e2d\u662f\u5b88\u6052\u7684\uff0c \u8d28\u91cf\u4e0d\u53d8\uff0cFe2O3\u4e2d\u6c27\u7684\u91cf\u7b49\u4e8e\u5408\u91d1\u4e2d\u94dd\u7684\u91cf\uff0c\u5219\uff1a
m(Fe):m(Al)=m(Fe):m(O)=(2\u00d756):(3\u00d716)=7:3
\u6b63\u786e\u9009\u9879\u4e3aC
\u4f8b3\uff1a\u5411\u4e00\u5b9a\u91cf\u7684Fe\u3001FeO\u548cFe2O3\u7684\u6df7\u5408\u7269\u6295\u5165100 mL1mol/L\u7684\u76d0\u9178\uff0c\u6070\u597d\u4f7f\u6df7\u5408\u7269\u5b8c\u5168\u6eb6\u89e3\uff0c\u653e\u51fa224 mL(\u6807\u51c6\u72b6\u51b5)\u7684\u6c14\u4f53\uff0c\u6240\u5f97\u6eb6\u6db2\u4e2d\uff0c\u52a0\u5165KSCN\u6eb6\u6db2\u65e0\u8840\u7ea2\u8272\u51fa\u73b0\uff0c\u82e5\u7528\u8fc7\u91cf\u7684CO\u5728\u9ad8\u6e29\u4e0b\u8fd8\u539f\u76f8\u540c\u8d28\u91cf\u7684\u6df7\u5408\u7269\uff0c\u80fd\u5f97\u94c1\u7684\u8d28\u91cf\u4e3a
A\uff0e11.2 g B\uff0e5.6 g C\uff0e2.8 g D\uff0e\u65e0\u6cd5\u8ba1\u7b97
\u89e3\u6790\uff1a\u4f9d\u9898\u610f\u53ef\u77e5\uff0c\u53cd\u5e94\u540e\u7684\u6eb6\u6db2\u6eb6\u8d28\u53ea\u6709FeCl2\uff0c\u800cCl\u2015\u6765\u81ea\u76d0\u9178\uff0c\u6240\u4ee5n(Fe)=n(Fe2+)=1/2(Cl\u2015)=1/2\u00d70.1L\u00d71mol/L
=0.05mol\uff0c
m(Fe)= 0.05mol \u00d756g/mol=2.8 g
\u6b63\u786e\u9009\u9879\u4e3aC
\u5c06\u51e0\u79cd\u94c1\u7684\u6c27\u5316\u7269\u7684\u6df7\u5408\u7269\u6295\u5165\u52307mol/L\u7684\u76d0\u9178100 mL \u4e2d\uff0c\u6070\u597d\u5b8c\u5168\u6eb6\u89e3,\u5728\u6240\u5f97\u7684\u6eb6\u6db2\u4e2d\u518d\u901a\u51650.56L(\u6807\u51b5)\u6c2f\u6c14\u65f6\uff0c\u521a\u597d\u4f7f\u6eb6\u6db2\u4e2dFe2+ \u5b8c\u5168\u8f6c\u5316\u4e3aFe3+ ,\u5219\u8be5\u6df7\u5408\u7269\u4e2d\u94c1\u5143\u7d20\u7684\u8d28\u91cf\u5206\u6570\u4e3a
A\uff0e74.1% B\uff0e72.4%
C\uff0e70.0% D\uff0e63.6%
\u89e3\u6790\uff1a\u94c1\u7684\u6c27\u5316\u7269\u662f\u7531\u94c1\u548c\u6c27\u4e24\u79cd\u5143\u7d20\u7ec4\u6210\uff0c\u5728\u53cd\u5e94\u4e2d\u6c27\u5143\u7d20\u8f6c\u5316\u4e3a\u6c34\u4e2d\u7684\u6c27\uff0c\u7531\u5173\u7cfb\u5f0f\u5f97\uff1aH2O\uff5e2HCl\uff5eO\uff0cn(O)=1/2n(HCl)=1/2\u00d77mol/L\u00d70.1L=0.35mol
\u5373\uff1am(O)=0.35mol\u00d716g/mol=5.6g\u3002
\u6700\u540e\u7684\u6eb6\u6db2\u4e3aFeCl3\uff0c
n(Cl)= 0.56L\u00f722.4mol/L\u00d72+0.7mol
=0.75mol
n(Fe)=1/3n(Cl)=0.25mol
m(Fe)=0.25mol\u00d756g/mol=14g\uff0c
w(Fe)=14g\u00f7(14g+5.6g) \u00d7100%=71.4%
\u6b63\u786e\u7b54\u6848\uff1aA
1.\u82e5NA\u8868\u793a\u963f\u4f0f\u52a0\u5fb7\u7f57\u5e38\u6570,\u5219\u4e0b\u5217\u8bf4\u6cd5\u9519\u8bef\u7684\u662f:
\u95ee\u9898\u8865\u5145\uff1aA \u5e38\u6e29\u5e38\u538b\u4e0b22.4L\u6c34\u5206\u5b50\u542b2NA\u4e2a\u7535\u5b50
B NA\u4e2a\u6c27\u5206\u5b50\u548cNA\u4e2a\u6c22\u5206\u5b50\u8d28\u91cf\u6bd4\u4e3a16:1
C 1mol\u6c34\u603b\u5171\u542b\u67093NA\u4e2a\u539f\u5b50
D 71gCl\u79bb\u5b50\u53ef\u5f97\u5230NA\u4e2a\u7535\u5b50
2.\u7269\u8d28\u7684\u91cf\u6d53\u5ea6\u76f8\u540c\u7684NaCl,MgCl2,AlCl3,\u4e09\u79cd\u6eb6\u6db2\uff0c\u5f53\u5b83\u4eec\u7684\u4f53\u79ef\u6bd4\u4e3a3:2:1\u65f6\uff0c\u8fd9\u4e09\u79cd\u6eb6\u6db2\u4e2dCl\u79bb\u5b50\u7684\u7269\u8d28\u7684\u91cf\u4e4b\u6bd4\u4e3a
A 1:1:1 B 1:2:3 C 3:2:1 D 3:4:3
3.\u6807\u51c6\u72b6\u51b5\u4e0b\uff0c\u24606.72L NH3 \u24611.24\u00d710^23\u4e2aH2S
\u24625.6g CH4 \u24630.5mol HCl ,\u4e0b\u5217\u5173\u7cfb\u6b63\u786e\u7684\u662f
A \u4f53\u79ef\u5927\u5c0f\uff1a\u2463\uff1e\u2462\uff1e\u2461\uff1e\u2460
B \u539f\u5b50\u6570\u76ee\uff1a\u2462\uff1e\u2460\uff1e\u2463\uff1e\u2461
C \u5bc6\u5ea6\u5927\u5c0f\uff1a\u2463\uff1e\u2461\uff1e\u2462\uff1e\u2460
D\u8d28\u91cf\u5927\u5c0f\uff1a \u2463\uff1e\u2462\uff1e\u2461\uff1e\u2460
1.A(\u6c34\u84b8\u6c14\u662f\u6db2\u5316\u5f62\u6210\u7684\u6240\u4ee5\u662f\u6db2\u4f53\u6240\u4ee5\u4e0d\u53ef\u4ee5\u8ba4\u4e3a\u662f1mol)B\uff08\u6469\u5c14\u8d28\u91cf\u4e0d\u4e00\u5b9a\uff09
2.C\uff08\u56db\u540c\u5b9a\u5f8b\u4e2d\u7b2c\u4e00\u6761\u7269\u8d28\u7684\u91cf\u7684\u6d53\u5ea6\u76f8\u540c\u65f6\u4f53\u79ef\u4e4b\u6bd4\u7b49\u4e8e\u7269\u8d28\u7684\u91cf\u7684\u6bd4\uff09
3.\u6211\u628a \u80fd\u6c42\u7684\u90fd\u6c42\u4e86:(a)0.3molNH3\uff0c\u51711.2Na\u4e2a\u539f\u5b50\uff0c\u53c8\u56e0\u56db\u540c\u5b9a\u5f8b\u4e2d\u7b2c\u4e09\u6761\uff1a\u5bc6\u5ea6\u4e4b\u6bd4\u7b49\u4e8e\u76f8\u5bf9\u539f\u5b50\u8d28\u91cf\u4e4b\u6bd4\uff08\u6469\u5c14\u8d28\u91cf\u6bd4\uff09\u6240\u4ee5\u53ef\u8bbe\u6bd4\u7684\u4e00\u4efd\u662fx\u5219\u670917x\uff0c5.1gNH3\uff08b\uff090.205\uff08\u7ea6\u7b49\uff09molH2S\uff0c\u51710.6Na\u4e2a\u539f\u5b50\uff0c\u4f53\u79ef\u4e3a4.48L\uff0c\u5bc6\u5ea6\u4e3a34x\uff0c\u8d28\u91cf\u4e3a17g\uff08c\uff090.35molCH4\uff0c\u51711.75Na\u4e2a\u539f\u5b50\uff0c\u4f53\u79ef\u4e3a7.84L,\u5bc6\u5ea6\u4e3a16x\uff0c\u8d28\u91cf\u4e3a5.6g\uff08d\uff090.5molHCl,\u51711Na\u4e2a\u539f\u5b50\uff0c\u4f53\u79ef\u4e3a11.2L\uff0c\u5bc6\u5ea6\u4e3a36.5x,\u8d28\u91cf\u4e3a18.25g\u3002\u3002\u3002\u6545\u9009B
\u5df2\u77e5\u201c\u5728\u540c\u4e00\u6e29\u5ea6\u548c\u538b\u5f3a\u4e0b,\u76f8\u540c\u4f53\u79ef\u7684\u4efb\u4f55\u6c14\u4f53\u542b\u5206\u5b50\u4e2a\u6570\u90fd\u76f8\u7b49\u3002\u201d\u5728\u4e00\u4f53\u79ef\u7a7a\u6c14\uff08\u7a7a\u6c14\u4e8c\u6c27\u5316\u78b3\u5ffd\u7565\u4e0d\u8ba1\uff09\u4e2d\u6df7\u4eba1\u4f53\u79ef\u4e8c\u6c27\u5316\u78b3\uff0c\u9ad8\u6e29\u4e0b\u8ddf\u8db3\u91cf\u7684\u7126\u78b3\uff0c\u5047\u8bbe\u6c27\u6c14\u4e8c\u6c27\u5316\u70ad\u90fd\u5168\u90e8\u53cd\u5e94\uff0c\u5219\u53cd\u5e94\u540e\u7684\u6c14\u4f53\u4e2d\u4e00\u6c27\u5316\u70ad\u7684\u4f53\u79ef\u5206\u6570\u662f\u591a\u5c11\u3002
\u7a7a\u6c14\u4e2d,O2:N2=1:4 ;
1mol\u7a7a\u6c14\u5f97\u52300.4molCO\u548c0.8molN2 ;
1molCO2\u5f97\u52302molCO.
2.4/3.2=75%
\uff088\u5206\uff09\u5c06SO2\u548cO2\u7684\u6df7\u5408\u6c14\u4f53\u901a\u5165\u5bb9\u79ef\u4e3a1L\u7684\u5bc6\u95ed\u5bb9\u5668\u5185\uff0c\u5728\u4e00\u5b9a\u6e29\u5ea6\u548c\u50ac\u5316\u5242\u5b58\u5728\u7684\u6761\u4ef6\u4e0b\uff0c\u53cd\u5e94\u8fbe\u5e73\u8861\u65f6\u6d4b\u5f97SO2\u3001O2\u548cSO3\u7269\u8d28\u7684\u91cf\u5206\u522b\u4e3a2mol\u30011mol\u548c3mol\u3002
\uff081\uff09SO2\u548cO2\u53cd\u5e94\u7684\u65b9\u7a0b\u5f0f\uff1a
\u3002
\uff082\uff09\u521d\u59cb\u6df7\u5408\u6c14\u4f53\u4e2d\uff1aSO2\u7684\u6d53\u5ea6\u4e3a\u591a\u5c11mol/L\uff0c\u5176\u8f6c\u5316\u7387\u4e3a\u591a\u5c11\uff1bO2\u7684\u6d53\u5ea6\u4e3a\u591a\u5c11mol/L\uff0c\u5176\u8f6c\u5316\u7387\u4e3a\u591a\u5c11
\uff083\uff09\u82e5\u5c06O2\u7684\u8d77\u59cb\u6d53\u5ea6\u589e\u52a0\u81f36 mol/L\uff0c\u6d4b\u5f97\u76f8\u540c\u5b9e\u9a8c\u6761\u4ef6\u4e0b\u8fbe\u5e73\u8861\u65f6SO3\u7269\u8d28\u7684\u91cf\u4e3a4 mol\uff0c\u5219SO2\u7684\u8f6c\u5316\u7387\u4e3a\u591a\u5c11\uff1bO2\u7684\u8f6c\u5316\u7387\u4e3a\u591a\u5c11\u3002
1 \uff081\uff09\u7565
\uff082\uff095\uff1b60%\uff1b2.5\uff1b60%
\uff083\uff09 80%\uff1b33.3%
2\uff0e \uff0810\u5206\uff09\u6c2e\u80a5\u6216\u571f\u58e4\u4e2d\u7684\u542b\u6c2e\u91cf\u53ef\u4ee5\u7528\u9178\u78b1\u6ef4\u5b9a\u6cd5\u6d4b\u5b9a\u3002\u79f0\u53d6\u6c2e\u80a5\u6c2f\u5316\u94f50.2000 g\u4e8e\u84b8\u998f\u74f6\u4e2d\uff0c\u52a0\u84b8\u998f\u6c34\u6eb6\u89e3\u540e\u52a0\u5165\u8fc7\u91cf\u6d53NaOH\u6eb6\u6db2\uff0c\u52a0\u70ed\u4f7f\u4ea7\u751f\u7684\u6c28\u6c14\u5bfc\u516540.00 mL\u6d53\u5ea6\u4e3a0.1004 mol/L\u7684\u786b\u9178\u6eb6\u6db2\u4e2d\u88ab\u5438\u6536\u3002\u7136\u540e\u75280.1600 mol/L\u7684NaOH\u6807\u51c6\u6eb6\u6db2\u6ef4\u5b9a\u4f59\u91cf\u7684\u786b\u9178\uff0c\u6d88\u8017NaOH\u6807\u6db220.11 mL\u3002
\uff081\uff09\u5199\u51fa\u6ef4\u5b9a\u53cd\u5e94\u65b9\u7a0b\u5f0f\uff1b\u9009\u7528\u7684\u6307\u793a\u5242\u662f
\uff082\uff09\u6ef4\u5b9a\u6d88\u8017NaOH\u7269\u8d28\u7684\u91cf\u4e3a\u591a\u5c11mmol\u3002
\uff083\uff09\u5438\u6536\u6c28\u6d88\u8017\u7684H2SO4\u7269\u8d28\u7684\u91cf\u4e3a\u591ammol\u3002
\uff084\uff09\u6c2e\u80a5\u8bd5\u6837\u4e2d\u6c2e\uff08\u76f8\u5bf9\u539f\u5b50\u91cf14\uff09\u7684\u8d28\u91cf\u5206\u6570\u4e3a\u591a\u5c11
2\uff0e \uff081\uff092 NaOH\uff0bH2SO4 = Na2SO4 + 2 H2O\uff1b \u7532\u57fa\u7ea2
\uff082\uff093.218\uff1b
\uff083\uff092.407\uff1b
\uff084\uff0916.85%
3\uff0e(7\u5206)\u67d0\u5929\u7136\u78b1\u53ef\u4ee5\u770b\u4f5c\u662fCO2\u548cNaOH\u53cd\u5e94\u540e\u7684\u4ea7\u7269\u7ec4\u6210\u7684\u4e00\u79cd\u7269\u8d28\u3002\u4e3a\u4e86\u6d4b\u5b9a\u8be5\u7269\u8d28\u7684\u6210\u5206\uff0c\u8fdb\u884c\u5982\u4e0b\u5b9e\u9a8c\uff1a
(1) \u79f0\u53d63.32 g\u5929\u7136\u78b1\u6837\u54c1\uff0c\u52a0\u516530 mL\u8fc7\u91cf\u7a00\u76d0\u9178\uff0c\u4ea7\u751f672 mLCO2\u6c14\u4f53(\u6807\u51c6\u72b6\u51b5)\u3002
(2) \u53e6\u79f0\u53d63.32 g\u5929\u7136\u78b1\u6837\u54c1\uff0c\u5728300 \u2103\u4e0b\u52a0\u70ed\u81f3\u5206\u89e3\u5b8c\u5168\uff0c\u4ea7\u751fCO2 112 mL(\u6807\u51c6\u72b6\u51b5)\u548c0.45 g\u6c34\u3002
\u8bd5\u901a\u8fc7\u8ba1\u7b97\uff0c\u786e\u5b9a\u5929\u7136\u78b1\u7684\u5316\u5b66\u5f0f\u3002
3\uff0e(7\u5206)
\u5df2\u77e5CO2\u548cNaOH\u53cd\u5e94\u7684\u4ea7\u7269\u53ef\u80fd\u6709Na2CO3\u3001NaHCO3\u6216\u4e8c\u8005\u7684\u6df7\u5408\u7269\u3002\u9898\u4e2d\u4e24\u6b21\u5b9e\u9a8c\u4ea7\u751fCO2\u7684\u4f53\u79ef\u5173\u7cfb\uff0c\u53ef\u4ee5\u63a8\u77e5\u5929\u7136\u78b1\u4e2d\u542b\u6709Na2CO3\u548cNaHCO3\u6210\u5206\u3002(1\u5206)
\u6839\u636e\u53cd\u5e94\uff1a2NaHCO3=Na2CO3+H2O\u2191+CO2\u2191
\u6837\u54c1\u4e2d\uff1a2NaHCO3=Na2CO3+H2O\u2191+CO2\u2191
n(H2O)=0.5\u00d70.01mol\u00d718g/mol=0.09g (2\u5206)
\u5219\u6837\u54c1\u4e2d\uff1an(NaHCO3)=0.02mol (2\u5206)
\u7ed3\u6676\u6c34\uff1an(H2O)=0.02mol
\u6240\u4ee5\uff0c\u5929\u7136\u78b1\u7684\u5316\u5b66\u5f0f\u4e3a\uff1a2Na2CO3•NaHCO3•2H2O\u3002(1\u5206)
4\uff0e(8\u5206)\u86cb\u58f3\u7684\u4e3b\u8981\u6210\u5206\u662fCaCO3\uff0c\u5176\u6b21\u662fMgCO3\u3001\u86cb\u767d\u8d28\u3001\u8272\u7d20\u7b49\u3002\u4e3a\u6d4b\u5b9a\u5176\u4e2d\u9499\u7684\u542b\u91cf\uff0c\u6d17\u51c0\u86cb\u58f3\uff0c\u52a0\u6c34\u716e\u6cb8\u7ea65 min\uff0c\u7f6e\u4e8e\u84b8\u53d1\u76bf\u4e2d\u7528\u5c0f\u706b\u70e4\u5e72\uff0c\u7814\u7ec6\u3002
(1) \u79f0\u53d60.3 g(\u8bbe\u4e3a0.3000g)\u86cb\u58f3\u6837\u54c1\uff0c\u7f6e\u4e8e\u9525\u5f62\u74f6\u4e2d\u9010\u6ef4\u52a0\u5165\u5df2\u77e5\u6d53\u5ea6c(HCl)\u7684\u76d0\u917840.00 mL\uff0c\u800c\u540e\u7528\u5c0f\u706b\u52a0\u70ed\u4f7f\u4e4b\u6eb6\u89e3\uff0c\u51b7\u5374\u540e\u52a02\u6ef4\u7532\u57fa\u6a59\u6eb6\u6db2\uff0c\u7528\u5df2\u77e5\u6d53\u5ea6c(NaOH)\u56de\u6ef4\uff0c\u6d88\u8017V(NaOH) L\u8fbe\u7ec8\u70b9\u3002
\u2460 (2\u5206)\u5199\u51fa\u8ba1\u7b97\u9499\u542b\u91cf\u7684\u7b97\u5f0f\u3002
\u2461 (1\u5206)\u8ba1\u7b97\u5f97\u5230\u7684\u662f\u9499\u7684\u542b\u91cf\u5417\uff1f
\u2462 (1\u5206)\u662f\u539f\u86cb\u58f3\u4e2d\u9499\u7684\u542b\u91cf\u5417\uff1f
(2) \u79f0\u53d60.3 g(\u8bbe\u4e3a0.3000 g)\u86cb\u58f3\u6837\u54c1\uff0c\u7528\u9002\u91cf\u5f3a\u9178\u6eb6\u89e3\uff0c\u7136\u540e\u52a0(NH4)2C2O4\u5f97\u6c89\u6dc0\uff0c\u7ecf\u8fc7\u6ee4\u3001\u6d17\u6da4\uff0c\u6c89\u6dc0\u6eb6\u4e8eH2SO4\u6eb6\u6db2\uff0c\u518d\u7528\u5df2\u77e5\u6d53\u5ea6c(KMnO4)\u6ef4\u5b9a(\u751f\u6210Mn2+\u548cCO2)\uff0c\u6d88\u8017V(KMnO4)L\u8fbe\u5230\u7ec8\u70b9\u3002
\u2460 (2\u5206)\u5199\u51fa\u8ba1\u7b97\u9499\u542b\u91cf\u7684\u7b97\u5f0f\uff1b
\u2461 (2\u5206)\u6b64\u6cd5\u6c42\u5f97\u7684\u9499\u542b\u91cf\u7565\u4f4e\u4e8e\u4e0a\u6cd5\u3002\u4e3a\u4ec0\u4e48\uff1f
4.(1) \u2460
(2\u5206)
\u2461\u5e94\u662fCa\u3001Mg\u7684\u603b\u91cf(1\u5206)
\u2462\u4e0d\u662f\uff0c\u56e0\u6d17\u6da4\u3001\u716e\u6cb8\u65f6\u9664\u53bb\u4e86\u5c11\u91cf\u86cb\u767d\u8d28\uff0c\u800c\u7b97\u5f0f\u4e2d\u5168\u6309Ca2+\uff0c\u537340.00 g/mol\u8ba1\u7b97(1\u5206)
(2) \u2460CaCO3+2H+ Ca2++H2O+CO2\u2191
Ca2++C2O42- CaC2O4\u2193
CaC2O4+2H+ Ca2++H2C2O4
2MnO4+5H2C2O4+6H+ 2Mn2++10CO2\u2191+8H2O
\u53731 mol CaCO3\uff5e1 mol Ca2+\uff5e1 mol H2C2O4\uff5e2/5 mol KMnO4
(2\u5206)
\u2461 Ca2C2O4\u4e3a\u96be\u6eb6\u7269\uff0c\u80fd\u4ece\u6eb6\u6db2\u4e2d\u5b8c\u5168\u6c89\u6dc0\uff0c\u53c8\u80fd\u5b8c\u5168\u6eb6\u4e8e\u8fc7\u91cf\u7a00\u786b\u9178\u3002\u5b9e\u9a8c\u7ed3\u679c\u9499\u542b\u91cf\u4f4e\uff0c\u53ef\u80fd\u662fMgC2O4\u6eb6\u89e3\u5ea6\u4e0d\u5f88\u5c0f\u4e4b\u6545(\u9644\uff1a18 \u2103\u65f6MgC2O4•10H2O\u6eb6\u89e3\u5ea6\u4e3a0.03 g)\uff0c\u7528\u786b\u9178\u6eb6\u89e3\u65f6\uff0cH2C2O4\u91cf\u51cf\u5c11\u4e4b\u6545\u3002(2\u5206)
5\uff0e\uff087\u5206\uff09\u67d0NaOH\u56fa\u4f53\u56e0\u5bc6\u5c01\u4e0d\u4e25\u800c\u90e8\u5206\u53d8\u8d28\u4e3aNa2CO3\u3002\u4e3a\u6d4b\u5b9a\u5176\u6210\u4efd\u542b\u91cf\uff0c\u79f0\u53d60.700g\uff08\u5176\u5b83\u6742\u8d28\u4e0d\u4e0eHCl\u53cd\u5e94\uff09\u70e7\u78b1\u56fa\u4f53\u7a00\u91ca\u81f3100mL\uff0c\u7136\u540e\u4f5c\u5982\u4e0b\u6d4b\u5b9a\uff1a
\u2460\u53d6\u7a00\u91ca\u6db220.0mL\u6ef4\u51652~3\u6ef4\u7532\u57fa\u6a59\u4f5c\u6307\u793a\u5242\uff0c\u75280.110mol/L\u7684\u76d0\u9178\u6ef4\u5b9a\uff0c\u8fbe\u7ec8\u70b9\u65f6\u6d88\u8017\u76d0\u917826.0mL\uff1b
\u2461\u53e6\u53d6\u7a00\u91ca\u6db220.0mL\uff0c\u52a0\u5165\u8fc7\u91cf\u7684BaCl2\u6eb6\u6db2\uff0c\u8fc7\u6ee4\uff0c\u5728\u6ee4\u6db2\u4e2d\u6ef4\u51652~3\u6ef4\u915a\u915e\u4f5c\u6307\u793a\u5242\uff0c\u7528\u4e0a\u8ff0\u76d0\u9178\u6ef4\u5b9a\uff0c\u8fbe\u7ec8\u70b9\u65f6\u65f6\u6d88\u8017\u76d0\u917820.0mL\u3002
\u8bf7\u56de\u7b54\uff1a
(1)\u64cd\u4f5c\u2460\u8fbe\u7ec8\u70b9\u65f6\u989c\u8272\u53d8\u5316\u662f \u3002
(2)\u7b2c\u2461\u6b65\u64cd\u4f5c\u5982\u679c\u4e0d\u8fc7\u6ee4\uff0c\u5728\u6709\u6c89\u6dc0\u7684\u6eb6\u6db2\u4e2d\u76f4\u63a5\u7528\u76d0\u9178\u6ef4\u5b9a\uff0c\u5f53\u6ef4\u5b9a\u5230\u7ec8\u70b9\u65f6\uff0c\u6eb6\u6db2\u4e2d\u7684BaCO3\u53d8\u4e3a\u4e86\uff08\u5199\u5316\u5b66\u5f0f\uff09 \uff0c\u539f\u56e0\u662f
\u3002
(3)\u8bf7\u8ba1\u7b97\u8be5\u70e7\u78b1\u6837\u54c1\u4e2dNaOH\u548cNa2CO3\u7684\u8d28\u91cf\u5206\u6570\u3002
5.\uff081\uff09\u6eb6\u6db2\u7531\u9ec4\u8272\u53d8\u4e3a\u6a59\u8272\uff081\u5206\uff09
(2)BaCl2\u3001Ba(HCO3)2\uff081\u5206\uff09\uff1bNaHCO3\u6c34\u89e3\u540e\u7684\u7a00\u6eb6\u6db2pH\u503c\u8303\u56f4\uff0c\u6070\u597d\u662f\u915a\u915e\u7684\u53d8\u8272\u8303\u56f4(1\u5206)
\uff083\uff09\u7b54\uff1a\u8be5\u70e7\u78b1NaOH\u8d28\u91cf\u5206\u6570\u662f62.9%\uff0cNa2CO3\u7684\u8d28\u91cf\u5206\u6570\u662f25.0%
32\uff0e\uff0810\u5206\uff09\u4e3a\u6d4b\u5b9a\u67d0\u6c27\u5316\u7269\uff08\u5316\u5b66\u5f0f\u4e3aMO\uff09\u4e2dM\u662f\u4f55\u79cd\u91d1\u5c5e\uff0c\u505a\u4ee5\u4e0b\u5b9e\u9a8c\uff1a\u79f0\u53d6\u8be5\u6c27\u5316\u72698.0g\u6eb6\u4e8e\u9002\u91cf\u7684\u7a00\u786b\u9178\u4e2d\uff0c\u518d\u914d\u5236\u6210250.0mL\u6eb6\u6db2\u3002\u53d6\u8be5\u6eb6\u6db250mL\u7528\u60f0\u6027\u7535\u6781\u8fdb\u884c\u7535\u89e3\uff0c\u5f53\u521a\u597d\u7535\u89e3\u5b8c\u5168\u65f6\uff0c\u7535\u6781\u6790\u51faM1.28g \u3002\u8bf7\u901a\u8fc7\u8ba1\u7b97\u56de\u7b54\u4ee5\u4e0b\u95ee\u9898\uff1a
\u2474M\u662f\u4ec0\u4e48\u91d1\u5c5e\uff1f
\u2475\u7535\u89e3\u8fc7\u7a0b\u4e2d\uff0c\u5bfc\u7ebf\u4e0a\u6d41\u8fc7\u4e86\u7684\u7535\u5b50\u4e2a\u6570\u662f\u591a\u5c11\uff1f
\u2476\u6700\u521d\u914d\u5236\u7684\u6eb6\u6db2\u4e2d\uff0c\u8be5\u91d1\u5c5e\u79bb\u5b50\u7269\u8d28\u7684\u91cf\u6d53\u5ea6\u662f\u591a\u5c11\uff1f
\u2477\u82e5\u6b64\u7535\u89e3\u6db2\u5728\u7535\u89e3\u540e\u4f53\u79ef\u4e3a40mL\uff0c\u6b64\u65f6\u6eb6\u6db2\u7684pH\u503c\u662f\u591a\u5c11\uff1f
32\uff0e\uff0810\u5206\uff09\u89e3\uff1a\u2474\u8be5\u91d1\u5c5e\u7684\u8d28\u91cf\u4e3a\uff1a1.28\u00d7(250/50)=6.4(g) \u2026\u2026\u2026\u2026\u2026 (1\u5206 )
\u8bbe\u5176\u76f8\u5bf9\u539f\u5b50\u8d28\u91cf\u4e3ax\uff0c\u5219\u89e3\u5f97\uff1ax=64 \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\uff082\u5206\uff09
\u6545\u8be5\u91d1\u5c5e\u662f\u94dc\u3002\uff081\u5206\uff09
\u2475\u7531Cu2++2e=Cu\u2193\u77e5\uff0c\u7535\u8def\u4e2d\u4e0a\u901a\u8fc7\u7684\u7535\u5b50\u4e3a\uff1a0.04mol \u2026\u2026\u2026\u2026\u2026\uff081\u5206\uff09
\u5373\uff1a0.04\u00d76.02\u00d71023=2.408\u00d71022(\u4e2a)\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\uff081\u5206\uff09
\u2476\u539f\u6eb6\u6db2\u4e2d cu\u79bb\u5b50\u7269\u8d28\u7684\u91cf\u6d53\u5ea6\u662f 0.4mol/L \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\uff082\u5206 \uff09
\u2477\u7531\u7535\u89e3\u65b9\u7a0b\u5f0f\uff1a2Cu2++2H2O=2Cu\u2193+O2\u2191+4H+ \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 \u2026\u2026\u2026\u2026\u2026.\uff081\u5206 \uff09
\u5f97\uff1aH\u79bb\u5b50\u7269\u8d28\u7684\u91cf\u6d53\u5ea6\u662f 1mol/L \uff081\u5206 \uff09\u6240\u4ee5\uff1apH= \u2014lg[H+]= \u2014lg1=0 \u2026\uff081\u5206 \uff09
7\uff0e\u53d6100mL 18.3mol/L\u7684H2SO4\u4e0eZn\u53cd\u5e94\uff0c\u5f53Zn\u5b8c\u5168\u6eb6\u89e3\u65f6\uff0c\u751f\u6210\u7684\u6c14\u4f53\u5728\u6807\u51c6\u72b6\u51b5\u4e0b\u5360\u6709\u7684\u4f53\u79ef\u4e3a22.4L\u3002\u5c06\u6240\u5f97\u7684\u6eb6\u6db2\u7a00\u91ca\u62101L\uff0c\u6d4b\u5f97\u6eb6\u6db2\u4e2dH\uff0b\u6d53\u5ea6\u4e3a1mol/L\uff0c\u5219\u6240\u751f\u6210\u7684\u6c14\u4f53\u4e2dSO2\u548cH2\u7684\u4f53\u79ef\u6bd4\u7ea6\u4e3a
A\u30011\u22362 B\u30012\u22361 C\u30011\u22364 D\u30014\u22361
7.A
13\uff0e\u5c06\u4e24\u79cd\u786b\u9178\u76d0\u6309\u4e00\u5b9a\u6bd4\u4f8b\u6df7\u5408\u540e\u5171\u7194\uff0c\u53ef\u5236\u5f97\u5316\u5408\u7269X\uff0cX\u6eb6\u4e8e\u6c34\u80fd\u7535\u79bb\u51faK\uff0b\u3001Cr3\uff0b\u3001SO42\uff0d\uff0c\u82e5\u5c062.83 g X\u4e2d\u7684Cr3\uff0b\u5168\u90e8\u6c27\u5316\u4e3aCr2O72\uff0d\u540e\uff0c\u6eb6\u6db2\u4e2d\u7684Cr2O72\uff0d\u53ef\u548c\u8fc7\u91cfKI\u6eb6\u6db2\u53cd\u5e94\uff0c\u5f97\u52303\uff0e81 g I2\uff0c\u53cd\u5e94\u7684\u79bb\u5b50\u65b9\u7a0b\u5f0f\u4e3a\uff1aCr2O72\uff0d\uff0b6I\uff0d\uff0b14H\uff0b\uff1d2Cr3\uff0b\uff0b3I2\uff0b7H2O\uff0c\u82e5\u5411\u6eb6\u67092.83 g X\u7684\u6eb6\u6db2\u4e2d\uff0c\u52a0\u5165\u8fc7\u91cf\u7684BaCl2\u6eb6\u6db2\uff0c\u53ef\u5f97\u52304.66 g\u767d\u8272\u6c89\u6dc0\u3002\u7531\u6b64\u53ef\u63a8\u65ad\u51faX\u7684\u5316\u5b66\u5f0f\u4e3a\uff08 \uff09
A\uff0eK2SO4•2Cr2(SO4)3 B\uff0e2K2SO4•Cr2(SO4)3
C\uff0eK2SO4•Cr2(SO4)3 D\uff0eK2SO4• Cr2(SO4)3
8.C
9.\uff0e\u5728\u4e00\u6052\u5b9a\u5bb9\u79ef\u7684\u5bb9\u5668\u4e2d\u5145\u51652 mol\u7684A\u548c1 mol\u7684B\u53d1\u751f\u53cd\u5e94\uff1a2A(s)+B(g) xC(g)\u3002\u8fbe\u5230\u5316\u5b66\u5e73\u8861\u540e\uff0cC\u7684\u4f53\u79ef\u5206\u6570\u4e3aa\u3002\u82e5\u5728\u6052\u6e29\u6052\u5bb9\u4e0b\uff0c\u63090.6 mol\u7684A\u30010.3 mol\u7684B\u30011.4 mol\u7684C\u4e3a\u8d77\u59cb\u7269\u8d28\uff0c\u8fbe\u5230\u5316\u5b66\u5e73\u8861\u540e\uff0cC\u7684\u4f53\u79ef\u5206\u6570\u4ecd\u4e3aa\uff0c\u5219x\u4e3a
A\uff0e\u53ea\u80fd\u4e3a2 B\uff0e\u53ea\u80fd\u4e3a3 C\uff0e\u53ef\u80fd\u4e3a2\u62163 D\uff0e\u65e0\u6cd5\u786e\u5b9a
9.C
10\uff0e\u5728\u4e00\u5b9a\u6e29\u5ea6\u4e0b\uff0c\u67d0\u6d53\u5ea6\u7684HNO3\u4e0eZn\u53cd\u5e94\uff0c\u751f\u6210NO2\u548cNO\u7684\u7269\u8d28\u7684\u91cf\u4e4b\u6bd4\u4e3a1:3\uff0c\u5219\u8981\u4f7f1mol Zn\u5b8c\u5168\u53cd\u5e94\uff0c\u9700\u8981HNO3\u7684\u7269\u8d28\u7684\u91cf\u4e3a
A\uff0e2.8mol B\uff0e2.6mol C\uff0e2.4mol D\uff0e0.8mol
10.A
1\u3001\u5c06\u5355\u8d28\u94dc\u548c\u6c27\u6c14\u53cd\u5e94\u751f\u6210\u6c27\u5316\u94dc
2\u3001\u6c27\u5316\u94dc\u548c\u7a00\u785d\u9178\u53cd\u5e94\u5236\u785d\u9178\u94dc
2、明矾的电离方程式KAl(SO4)2=K(+)+Al(+3)+2SO4(2-)、明矾的净水原理：Al(+3)水解生成AL(OH)3胶体，胶体具有吸附性，因而能净水。
3、铝遇浓硫酸、浓硝酸会 钝化， 铝片放入稀硫酸溶液 会与H2SO4中的H发生置换反应而生成氢气。
4、铝热反应（和Fe2O3、Fe3O4、MnO2反应）2Al+Fe2O3=Al2O3+2Fe、8Al+3Fe3O4=4Al2O3+9Fe、2Al+3MnO2=2Al2O3+3Mn
5、C还原Fe2O3、Fe3O4、CuO、MnO2
6、CO还原Fe2O3、Fe3O4：2CO+Fe2O3=2CO2+2Fe、4CO+Fe3O4=4CO2+3Fe
7、铝片放入FeCl2、CuSO4溶液中的离子方程2Al+3Fe(2+)=2Al(3+)+3Fe、2Al+3Cu(2+)=2Al(3+)+3Cu
都写离子方程式吧？
1、少量：2AlO2[2-]+CO2+3H2O=CO3[2-]+2Al(OH)3
大量：2AlO2[2-]+2CO2+4H2O=2HCO3[-]+2Al(OH)3
2、电离方程式KAl(SO4)2-.12H2O===K+ +Al3+ +2SO4 2- +12H20
净水原理 Al(3+)+3H20=可逆=Al(OH)3(胶体）+3H+
3 钝化 2Al+6H(+)=2Al(3+)+3H2↑
4氧化铁:
2Al+Fe2O3=Al2O3+2Fe
四氧化三铁:
8Al+3Fe3O4=4Al2O3+9Fe
二氧化锰:
4Al+3MnO2=2Al2O3+3Mn
(反应条件都为高温)
5 2Fe2O3+3C=高温=4Fe+3CO2
Fe3O4+2C=高温=3Fe+2CO2
6 3CO+Fe2O3=（高温）2Fe+3CO2
4CO+Fe3O4==（高温）3Fe+4CO2
7 2Al+3Fe(2+)===3Fe+2Al(3+)
2Al+3Cu(2+)===3Cu+2Al(3+)
1、NaAlO2+ CO2+2H2O=Al(OH)3↓ +NaHCO3
2、KAl(SO4)2·12H2O=K+ +Al3+ +2SO4 2- +12H2O 明矾(硫酸钾铝晶体)溶于水可电离出铝离子，铝离子易水解，生成氢氧化铝胶体
3、钝化 会反应生成气泡（H2）
4、氧化铁:
2Al+Fe2O3=Al2O3+2Fe
四氧化三铁:
8Al+3Fe3O4=4Al2O3+9Fe
二氧化锰:
4Al+3MnO2=2Al2O3+3Mn
反应条件都是高温，记得加上
5、3C+2Fe2O3=4Fe+3CO2↑
2C+Fe3O4=3Fe+2CO2↑
条件都是为高温，记得加上
6、3CO+Fe2O3=2Fe+3CO2
4CO+Fe3O4=3Fe+4CO2
条件的都为高温，记得加上
7、2Al+3Fe2+=3Fe+2Al3+
2Al+3Cu2+=3Cu+2Al3+
(1)2NaAlO3 + CO2 = Na2CO3 + 2Al(OH)3 Na2CO3 + CO2 + H2O = 2NaHCO3
(2)Al(OH)3 = Al3+ + 3OH- 氢氧化铝胶体的吸附作用
（3）钝化 2Al + 6H+ = 2Al3+
(4)2Al+Fe2O3=2Fe+Al2O3 8Al+3Fe3O4=4Al2O3+9Fe 4Al+3MnO2=2Al2O3+3Mn
1,2NaAlO2+3H2O+CO2=Na2CO3+2Al(OH)3 ↓ NaAlO2+2H2O+CO2=NaHCO3+Al(OH)3 ↓
2,KAl(SO4)2= K+ + Al3+ + 2SO4 2-它的原理是明矾在水中可以电离出两种金属离子：
而Al3+很容易水解，生成胶状的氢氧化铝Al(OH)3：
Al3+ + 3H2O = Al(OH)3+ 3H+ （可逆）
氢氧化铝胶体的吸附能力很强，可以吸附水里悬浮的杂质，并形成沉淀，使水澄清。所以，明矾是一种较好的净水剂。
3,钝化 2Al +3H2SO4 = Al2(SO4)3 +3H2↑
4,2Al+Fe2O3=2Fe+Al2O3 4Al+3MnO2=2Al2O3 +3Mn 8Al+3Fe3O4=9Fe+4Al2O3
53C+ 2Fe2O3 高温 4Fe + 3CO2↑ 2C+ Fe3O4 高温 3Fe + 2CO2↑
6,3CO+ Fe2O3 高温 2Fe + 3CO2 4CO+ Fe3O4 高温 3Fe + 4CO2
7,2Al+3Fe2+=3Fe+2Al3+ 2Al+3Cu2+=3Cu+2Al3+
1：2NaAlO2+CO2+3H2O=2Al(OH)3（沉淀）+2Na2CO3
Na2CO3+CO2+H2O=2NaHCO3
PS：写一个的话：NaAlO2+CO2+2H2O=Al(OH)3(沉淀)+NaHCO3
2：KAl（SO4）2=K（离子）+Al（离子）+2SO4（离子）
电离出的Al离子和水反应生成Al（OH）3胶体，Al（OH）3胶体有很强的吸附性，能凝聚水中的悬浮物使之沉降。
3：钝化 溶解放出气体
4：2Al+Fe2O3=2Fe+Al2O3 3Fe3O4+8Al=9Fe+4Al2O3 3MnO2+4Al=2Al2O3+3Mn
条件都要高温！
5：3C+2Fe2O3=4Fe+3CO2 2C+Fe3O4=3Fe+2CO2 条件都要高温！
6：3CO+Fe2O3=2Fe+3CO2 4CO+Fe3O4=3Fe+4CO2 条件都要高温！
PS：FexOy+yCO=xFe+yCO2
7：2Al+3Cu（离子）=3Cu+2Al（离子） 2Al+3Fe（离子）=3Fe+2Al（离子）
绛旓細A锛岄敊H3C-CH3 锛孋-H鍏变环閿6涓 C-C鍏变环閿1涓紝鍏7涓 銆11.2鍗囦负0.5mol 銆 0.5x7=3.5mol=3.5NA B锛屾纭22.4L娣峰悎姘斾綋鏍囧噯鐘舵佷负1mol 锛1mol鐨凮2鎴栬1mol鐨凜O2閮藉惈鏈2NA涓狾鍘熷瓙 C锛岄敊1mol鐨凜H4鍚槸鏈10NA鐢靛瓙锛屼絾22.4l涓嶆槸鏍囧噯鐘舵侊紝鏍囧噯鐘舵佹槸0鎽勬皬搴 涓涓爣鍑嗗ぇ姘斿帇 D...
绛旓細1)姘寲閾电殑鐗╄川鐨勯噺=107/锛14+4+35.5锛=2mol 2NH4Cl+Ca(OH)2=CaCl2+2NH3+2H2O 2 2 2 x x=2*2/2=2 浜х敓鐨凬H3鐨勭墿璐ㄧ殑閲=2mol 鏍囧喌涓嬭繖浜涙皵浣撶殑浣撶Н=2*22.4=44.8鍗 2锛夋皑姘寸殑鐗╄川鐨勯噺娴撳害=2/0.1=20mol/L
绛旓細(涓)鎺屾彙涔﹀啓鍖栧寮忕殑瑕侀 鍖栧寮忓湪鍖栧鐢ㄨ绯诲垪涓,澶勪簬鎵夸笂鍚笅鐨勫湴浣,鍓嶆湁鍏冪礌绗﹀彿鍜屽寲鍚堜环鐭ヨ瘑,杩欐槸涔﹀啓鍖栧寮忕殑鍩虹;鍚庢湁鍖栧鏂圭▼寮忓拰鐢电鏂圭▼寮忕瓑,杩欏張鏄互鍖栧寮忎负鍩虹鐨,鍏朵腑濡傛湁涓涓寲瀛﹀紡閿欒,鍒欏叏寮忔鏃犳剰涔,鑻ュ啀浠ヨ繖鏍风殑閿欒鍖栧鏂圭▼寮忎綔渚濇嵁杩涜鍖栧璁＄畻,鍒欓敊寰楁洿杩,鐪熷彲璋撴槸鈥滃け涔嬫鍘,宸箣鍗冮噷...
绛旓細瀵逛簬C.D鏉ヨ鍒楁柟绋嬩緥濡傚厛浠涓轰緥锛岃涓変环鐨勭鏈塜涓簲浠风殑纰樻湁Y涓墍浠+Y=4,3X+5Y=18鐪嬫柟绋嬭兘涓嶈兘寰楀埌姝ｆ暣鏁扮殑瑙ｅ鏋滃彲浠ョ殑璇濆垯璇佹槑鐚滄兂姝ｇ‘鎵浠=1.Y=3銆傚浜嶤閫夐」鏄В涓嶅嚭鏉ユ鏁存暟瑙ｇ殑浣犲彲浠ヨ嚜宸辫瘯楠屼竴涓.杩閬撻涓嶆槸鐪嬬殑鑰屾槸闇瑕佸姩绗旂畻鐨勶紝涓昏鑰冪殑鏄鍖栧悎浠风殑鎺屾彙绋嬪害濡備綍銆
绛旓細OH-澶т簬NH3澶т簬H2O OH- + H+鍙互寰楀埌NH3+H2O NH3 + H+鍙互寰楀埌H2O 鍝堝搱銆
绛旓細閫 B 杩欓亾鍖栧棰鍦ㄩ珮涓畻鏄腑涓婇毦搴︾殑棰樹簡锛屾ゼ涓讳粩缁嗙湅浜嗭細鍥犱负纭吀鐨勬祿搴﹀彧鏈0.1mol/L,涓虹█纭吀锛屾墍浠ヤ笉蹇呰冭檻Cu涓庣～閰哥殑鍙嶅簲锛屼絾鏄～閰稿彲浠ユ彁渚涙阿绂诲瓙锛屽嵆鏄锛屽湪濡傛灉Cu涓庣閰哥殑鍙嶅簲鑳藉娑堣楀畬纭濋吀鍘熸湁鐨勬墍鏈夌殑H锛岃孋u杩樻湁鍓╀綑锛岃繖鏃跺師灞炰簬纭吀鐨勬阿绂诲瓙鑳藉涓庣閰告牴缁撳悎锛屽彉鎴愮閰革紙瀹為檯涓婏紝婧舵恫...
绛旓細鍔犲叆閾濈墖鑳戒骇鐢熸阿姘旓紝璇存槑婧舵恫鏄鹃吀鎬э紝鏈夊ぇ閲廐锕 鈶燬绂诲瓙鍜孒绂诲瓙缁撳悎鐢熸垚H2S 鈶′簹閾佺瀛愬拰纰樼瀛愯兘鍙嶅簲 鈶CO3锕ｅ拰H绂诲瓙缁撳悎鐢熸垚CO2鍜孒2O 鎵浠ョ瓟妗堥塂
绛旓細閫塁 A: 宸茬兎涓烘恫浣 B: 娌¤鏍囧喌涓 C:瀵. O2 O3 瀹冧滑鐨勭粍鎴愰兘鏄疧鍘熷瓙锛屾墍浠(O)=m/M=16/16=1mol 鎵浠ュ惈O鍘熷瓙鏁颁负NA D: 搴斾负0.1NA 2Na2O2+ 2H2O = 4NaOH + O2(^)---2e- 2 2 7.8/78 n(e-) n锛坋-)=0.1mol ...
绛旓細姘斾綋鐨勫瘑搴︽槸鐩稿悓鐘跺喌涓嬫阿姘斿瘑搴︾殑20鍊嶏紝鍒欒姘斾綋鐨勫钩鍧囩浉瀵瑰垎瀛愯川閲忎负20*2=40 鐢熸垚鐗╂槸NO2锛岀浉瀵瑰垎瀛愯川閲忎负46锛屽洜姝ゅ弽搴旂墿杩樻湁鍓╀綑銆傝嫢鍓╀綑鏄疧2锛岃NO2鐨勭櫨鍒嗗惈閲忎负X 46*X+32*(1-X)=40 X=57%锛屽墿浣橭2涓43 2NO+O2=2NO2 1---1---2 57%--Y---57 Y=28.5 娣峰悎鍓峃O鍜孫2鐨勭墿璐ㄧ殑...
绛旓細1銆侀塁銆 A娌＄敤鐨勶紝鐩愭按鍜屾隘姘旀病浠涔堝叧绯汇侭鏈夎厫铓鎬с傜敤C锛岀⒈鎬уお寮猴紝涓嶄細鑵愯殌锛岃屼笖姘皵鏄吀鎬х殑锛岀⒊閰搁挔鍙互鍚告敹瀹 2銆侀塁銆 ABD鍏夌収鍒嗚В銆傜閰哥敓鎴怤O2/O2/H2O锛屾姘吀鍒嗚В涓篐Cl/O2锛孌鍒嗚В涓篈g/Br2 3銆侀塂銆侫-B鍙互鐢佃В锛孊-C鍙互鍔燙a(OH)2锛孋-D鍙互鍔燙O2锛孌-E涓嶅彲鑳斤紝鍥犱负寮遍吀鍒...
